2.2.12 · Physics › Fluid Mechanics
Intuition Ek dum simple mein badi baat
Fluid na toh kahin se aata hai, na kahin jaata hai. Agar tum ek behte hue stream ko ek narrow pipe mein squeeze karo, toh wahi mass har second se guzarna chahiye — isliye uski speed badhni hi padegi. Narrow ⇒ fast, wide ⇒ slow. Yahi poori kahani hai; equation sirf ise precise banati hai.
Definition Continuity equation
Kisi tube (real pipe ya imaginary "stream tube") mein behne wale fluid ke liye, unit time mein andar aane wala mass = unit time mein bahar jaane wala mass , agar koi mass accumulate na ho. Symbols mein:
ρ 1 A 1 v 1 = ρ 2 A 2 v 2 = constant
jahan ρ = density, A = cross-sectional area, v = us section par flow speed hai.
Incompressible fluid ke liye (ρ = const): A 1 v 1 = A 2 v 2 = const .
ρ A v quantity mass flow rate (kg/s) hai. A v quantity volume flow rate Q (m³/s) hai.
Intuition "Rate in = rate out" kyun?
Socho ki pipe ke ek section ko ek aisi box maano jisme koi leak nahi hai. Mass na banaya ja sakta hai, na destroy kiya ja sakta hai. Agar har second zyada mass andar aaye aur kam bahar jaaye, toh box hamesha bharta rahega (impossible — yeh incompressible fluid se pehle se bhara hua hai). Agar kam andar aaye aur zyada bahar jaaye, toh box khaali ho jayega aur vacuum ban jayega. Steady hone ki sirf ek hi possibility hai: in = out .
Hum us mass ko track karte hain jo ek tiny time Δ t mein ek cross-section se cross karta hai.
Step 1 — Time Δ t mein ek section se kitna fluid cross karta hai?
Cross-section 1 par, fluid v 1 speed se move karta hai. Time Δ t mein yeh itni distance aage badhta hai:
Δ x 1 = v 1 Δ t .
Yeh step kyun? Speed × time = distance — yahi fluid ka woh slab hai jo boundary se guzarta hai.
Step 2 — Us slab ka Volume.
Slab ek cylinder hai jiska area A 1 aur length Δ x 1 hai:
Δ V 1 = A 1 Δ x 1 = A 1 v 1 Δ t .
Yeh step kyun? Volume = area × length; yahi woh volume hai jo andar aaya.
Step 3 — Us slab ka Mass.
Δ m 1 = ρ 1 Δ V 1 = ρ 1 A 1 v 1 Δ t .
Yeh step kyun? Mass = density × volume. Yeh section 1 se andar aane wala mass hai.
Step 4 — Section 2 par wahi logic (bahar jaane wala mass).
Δ m 2 = ρ 2 A 2 v 2 Δ t .
Step 5 — Conservation of mass apply karo (steady state).
Sections ke beech koi mass accumulate nahi hota, isliye mass in = mass out:
Δ m 1 = Δ m 2 ⇒ ρ 1 A 1 v 1 Δ t = ρ 2 A 2 v 2 Δ t .
Yeh step kyun? Sections ke beech ki "box" bhari hui aur unchanging hai, isliye jo bhi andar aata hai woh bahar bhi jaana chahiye.
Step 6 — Δ t cancel karo.
ρ 1 A 1 v 1 = ρ 2 A 2 v 2
Incompressible flow ke liye ρ 1 = ρ 2 , ise divide kar do:
A 1 v 1 = A 2 v 2 = Q
Worked example Example 1 — Pipe jo narrow ho jaati hai
Water (ρ const) 4 cm radius ki pipe mein 2 m/s se flow karta hai. Pipe narrow hokar 2 cm radius ki ho jaati hai. Exit speed nikalo.
A ∝ r 2 , isliye A 1 v 1 = A 2 v 2 use karo:
v 2 = v 1 A 2 A 1 = v 1 r 2 2 r 1 2 = 2 × 2 2 4 2 = 2 × 4 = 8 m/s .
Yeh step kyun? Area, radius ke square ke saath scale karta hai; radius aadhi hone par area quarter ho jaata hai, isliye speed 4 guni ho jaati hai.
Worked example Example 2 — Volume flow rate
Ek garden hose jiska area 1 cm 2 = 1 × 1 0 − 4 m 2 hai, 5 m/s se paani baahir fekta hai. 10 L = 0.01 m 3 ki bucket bharne mein kitna time lagega?
Q = A v = ( 1 × 1 0 − 4 ) ( 5 ) = 5 × 1 0 − 4 m 3 / s .
t = Q V = 5 × 1 0 − 4 0.01 = 20 s .
Yeh step kyun? Q har second deliver hone wala volume hai; total volume ÷ rate = time.
Worked example Example 3 — Compressible gas (
ρ mat chhodna!)
Air ek duct (A 1 = 0.5 m 2 ) mein ρ 1 = 1.2 kg/m 3 , v 1 = 10 m/s se enter karti hai. Downstream yeh ρ 2 = 2.4 kg/m 3 tak compress hoti hai, area A 2 = 0.5 m 2 mein. v 2 nikalo.
Full form ρ 1 A 1 v 1 = ρ 2 A 2 v 2 use karo:
v 2 = ρ 2 A 2 ρ 1 A 1 v 1 = 2.4 × 0.5 1.2 × 0.5 × 10 = 1.2 6 = 5 m/s .
Yeh step kyun? Yahan ρ change hota hai, isliye A v akela conserved nahi hota — mass flow ρ A v hota hai. Fixed area par density double karne se speed aadhi ho jaati hai.
Common mistake "Same area chahiye, isliye
v 1 = v 2 hamesha."
Kyun sahi lagta hai: uniform pipe mein kuch badlta nahi lagta. Reality: continuity, speed ko area se jodti hai; speed tabhi equal hoti hai jab area (aur ρ ) equal hon. Fix: hamesha A 1 v 1 = A 2 v 2 likho aur unknown solve karo.
Common mistake "Gases ke liye bhi
A 1 v 1 = A 2 v 2 use karo."
Kyun sahi lagta hai: yahi form hum memorize karte hain. Reality: isse ρ drop ho jaata hai, jo sirf incompressible flow ke liye valid hai. Fix: gases/compression ke liye mass form ρ A v use karo.
Common mistake "Wider pipe ⇒ faster flow (zyada room)."
Kyun sahi lagta hai: zyada space lagta hai jaise easier, faster motion. Reality: fixed mass per second ek bade area par spread ho toh woh crawl karta hai. Fix: yaad rakho v ∝ 1/ A — wide ⇒ slow.
A ∝ r 2 bhool jaana.
Kyun sahi lagta hai: radius hi woh "size" hai jo hume di jaati hai. Fix: v 2 / v 1 = ( r 1 / r 2 ) 2 , na ki r 1 / r 2 .
Recall Feynman: ek 12-saal ke bachche ko samjhao
Socho ek busy hallway hai jisme bachche kaandhon se kaandha milaake chal rahe hain. Jahan hallway wide hai, bachche aaram se walk karte hain. Jahan yeh ek narrow doorway mein squeeze hoti hai, wahi number of kids per second abhi bhi pass karne hain — isliye unhe jaldi karni padti hai. Pipe mein paani exactly aisa hi hai: koi create nahi hota, koi gayab nahi hota, isliye ek narrow spot fluid ko speed up karne par majboor karta hai. Squeeze karo, speed badhti hai; widen karo, speed ghatti hai.
"Squeeze to Speed." Aur conserved quantity: "ρAv stays, mass obeys." Hose par thumb ki picture socho — choti hole, fast jet.
Continuity equation kis physical law ka statement hai? Conservation of mass (koi mass create/destroy nahi hota).
General continuity equation likho. ρ 1 A 1 v 1 = ρ 2 A 2 v 2 = const (mass flow rate constant).
Incompressible fluids ke liye kaunsa form hold karta hai aur kyun? A 1 v 1 = A 2 v 2 , kyunki ρ constant hai aur cancel ho jaata hai.
Narrowing pipe mein, fluid speed up hota hai ya slow down? Speed up hota hai; v ∝ 1/ A .
Agar radius aadhi ho jaaye (incompressible), speed ka kya hoga? Speed 4× ho jaati hai (v ∝ 1/ r 2 ).
Volume flow rate Q kya hai aur iske units kya hain? Q = A v , units m³/s.
Compressing gas ke liye A 1 v 1 = A 2 v 2 kyun use nahi kar sakte? Kyunki ρ change hota hai; sirf ρ A v (mass flow) conserved hota hai.
Time Δ t mein speed v par fluid slab ki distance derive karo. Δ x = v Δ t , isliye volume = A v Δ t , mass = ρ A v Δ t .
SABHI fluids ke liye (compressible bhi) kaunsi quantity conserved hoti hai? Mass flow rate m ˙ = ρ A v .
Bernoulli's equation — continuity woh speeds deti hai jo Bernoulli ko chahiye.
Volume flow rate and discharge
Incompressible vs compressible flow
Conservation of mass — parent principle.
Venturi meter — A 1 v 1 = A 2 v 2 ka direct application.
Streamlines and stream tubes
Mass in = mass out per second
Mass flow rate rho A v = const
Incompressible: A1 v1 = A2 v2