2.1.20 · Physics › Analytical Mechanics
Jab do pendulums (ya springs pe masse) ko couple karte ho, to wo alag-alag swing nahi karte — ek ko push karo, aur energy slosh karne lagti hai. Ye bahut complicated lagta hai. Magic claim ye hai:
Har chhoti-oscillation wala system, chahe kitna bhi tangled ho, independent simple harmonic oscillators ke ek set ke roop mein re-describe kiya ja sakta hai — inhe normal modes kehte hain. Har mode ki apni ek single frequency hoti hai. Asli messy motion sirf in clean modes ka superposition hai.
YE kyun matter karta hai: ye coupled differential equations ke ek system ko alag-alag, trivially-solvable 1D oscillator equations mein badal deta hai. Vibration physics ka ye 80/20 hai — molecules, bridges, crystals, circuits sab iska use karte hain.
Classic case lo: do equal masses m jo walls se aur ek doosre se springs se jude hain.
Bahari springs ka constant k ho aur coupling spring k c . Equilibrium se displacements x 1 , x 2 .
Definition Coupled oscillator
Ek aisa system jiske equations of motion mein cross terms hote hain jo coordinates ko mix karte hain, jaise x ¨ 1 ka x 2 pe depend karna. Coupling = variables independently move nahi kar sakte.
Energy kyun use karein? Forces mein signs bahut jaldi confusing ho jaati hain. Lagrangian mechanics mein sign error kabhi nahi hoti.
Kinetic energy:
T = 2 1 m x ˙ 1 2 + 2 1 m x ˙ 2 2
Potential energy — ye step kyun? har spring 2 1 k ( stretch ) 2 store karta hai. Beech wale spring ki stretch ( x 2 − x 1 ) hai:
V = 2 1 k x 1 2 + 2 1 k x 2 2 + 2 1 k c ( x 2 − x 1 ) 2
Lagrangian L = T − V . Euler–Lagrange apply karo d t d ∂ x ˙ i ∂ L = ∂ x i ∂ L :
m x ¨ 1 = − k x 1 + k c ( x 2 − x 1 )
m x ¨ 2 = − k x 2 − k c ( x 2 − x 1 )
Ye step kyun? ∂ V / ∂ x 1 mein wall spring (k x 1 ) aur coupling term dono hain, ( x 2 − x 1 ) 2 se chain-rule wala sign lekar. k c term dono equations mein opposite sign ke saath appear hota hai — yahi coupling hai.
Forecast: agar normal modes exist karte hain, to kuch aisi special motions hoti hain jahan dono masses ek hi frequency ω par fixed proportion mein oscillate karte hain. Guess karo:
x j ( t ) = A j cos ( ω t + ϕ )
Substitute karo. Har x ¨ j = − ω 2 x j . Cosine divide karne par algebraic equations milti hain:
− m ω 2 A 1 = − ( k + k c ) A 1 + k c A 2
− m ω 2 A 2 = + k c A 1 − ( k + k c ) A 2
Matrix form mein ( K − ω 2 M ) A = 0 :
( k + k c − m ω 2 − k c − k c k + k c − m ω 2 ) ( A 1 A 2 ) = 0
Expand karo:
( k + k c − m ω 2 ) 2 − k c 2 = 0 ⟹ k + k c − m ω 2 = ± k c
To:
ω 1 2 = m k ω 2 2 = m k + 2 k c
Har ω ko wapas plug karo aur ratio A 2 / A 1 nikalo.
Mode 1 (ω 1 2 = k / m ): bracket k + k c − m ω 1 2 = k c hai, to k c A 1 − k c A 2 = 0 ⇒ A 2 = A 1 .
→ In-phase / symmetric : masses saath chalte hain, coupling spring kabhi stretch nahi hoti, isliye k c feel nahi hoti → frequency sirf k / m hai.
Mode 2 (ω 2 2 = ( k + 2 k c ) / m ): bracket = − k c hai, to A 2 = − A 1 .
→ Anti-phase / antisymmetric : masses opposite direction mein chalte hain, coupling spring maximum work hoti hai → zyada stiff → higher frequency.
Intuition Symmetric mode slow kyun hota hai
Symmetric mode mein beech wali spring passenger hai — kabhi stretch nahi hoti. Kam restoring force ⇒ kam ω . Antisymmetric mode mein beech wali spring sabse zyada fight karti hai (effective stiffness k + 2 k c ) ⇒ zyada ω . Symmetry algebra se pehle answer bata deti hai.
Naye variables define karo jo equations ko decouple karte hain:
η 1 = 2 1 ( x 1 + x 2 ) η 2 = 2 1 ( x 1 − x 2 )
Ye kyun? Ye symmetric aur antisymmetric combinations hain — exactly eigenvectors. Dono EOMs ko add aur subtract karo:
Add karo: m ( x ¨ 1 + x ¨ 2 ) = − k ( x 1 + x 2 ) ⇒ η ¨ 1 = − ω 1 2 η 1
Subtract karo: m ( x ¨ 1 − x ¨ 2 ) = − ( k + 2 k c ) ( x 1 − x 2 ) ⇒ η ¨ 2 = − ω 2 2 η 2
Definition Normal coordinates
Coordinates η a jisme equations of motion completely decoupled ho jaati hain, har ek simple harmonic oscillator equation η ¨ a = − ω a 2 η a follow karta hai. Har ek ek independent normal mode hai.
Worked example Energy sloshing (beats)
Mass 1 ko side mein khincho, mass 2 rest mein: x 1 ( 0 ) = a , x 2 ( 0 ) = 0 , velocities zero.
Step: η nikalo. η 1 ( 0 ) = a / 2 , η 2 ( 0 ) = a / 2 . Kyun? sirf definitions mein plug karo. Velocities zero ⇒ ϕ a = 0 .
To η 1 = 2 a cos ω 1 t , η 2 = 2 a cos ω 2 t .
Back-transform karo:
x 1 = 2 a ( cos ω 1 t + cos ω 2 t ) = a cos ( 2 ω 2 − ω 1 t ) cos ( 2 ω 1 + ω 2 t )
Result: ek fast oscillation slow envelope se modulate ho rahi hai — beats . Energy poori tarah mass 2 mein transfer hoti hai aur wapas aati hai. Ye kyun matter karta hai: weak coupling (k c ≪ k ) ⇒ ω 1 ≈ ω 2 ⇒ bahut slow energy exchange.
Worked example Ek pure mode excite karna
Sirf symmetric mode chahiye? x 1 ( 0 ) = x 2 ( 0 ) = a set karo. Tab η 2 ( 0 ) = 0 aur zero hi rehta hai. Dono masses hamesha ω 1 = k / m par oscillate karte hain, coupling spring untouched.
Kyun: initial condition ke roop mein eigenvector choose karna single-frequency motion deta hai — normal coordinates ka poora point yahi hai.
Common mistake "Har mass ki apni frequency hoti hai"
Ye sahi kyun lagta hai: uncoupled hote to mass 1 ek rate se aur mass 2 doosre rate se oscillate karta, to surely wo apni frequencies rakhenge?
Fix: Coupling shared frequencies force karta hai. Ek normal mode mein saare parts EK common ω par oscillate karte hain. Individual masses ki messy motion in shared-frequency modes ka sum hai — har mass ki alag single frequency nahi.
ω 2 2 = ( k + 2 k c ) / m mein factor of 2 bhool jaana
Ye sahi kyun lagta hai: V mein k c ek baar dikhta hai aur tum k + k c likh dete ho.
Fix: antisymmetric stretch ( x 1 − x 2 ) = 2 x 1 hai, isliye coupling spring ka effective contribution double ho jaata hai. Hamesha secular determinant se derive karo, kabhi guess mat karo.
Common mistake Eigenvectors galat normalize karna /
M mix karna
Ye sahi kyun lagta hai: ise ordinary eigenvalue problem KA = λ A jaisa treat karna.
Fix: ye ek generalized problem hai KA = ω 2 MA . Orthogonality M ke respect mein hai: A a T M A b = 0 jab a = b ho. Equal masses ke saath M = m 1 se ye chhup jaata hai, lekin jab masses alag hote hain to ye bite karta hai.
Recall Feynman: ek 12 saal ke bachche ko explain karo
Do swings imagine karo jo rubber band se bande hain. Agar tum unhe ek hi direction mein ek saath push karo, rubber band saath chal leta hai — wo relaxed hai, aur wo apni normal slow speed se swing karte hain. Agar tum unhe opposite direction mein push karo, rubber band bar bar stretch aur snap back hota rehta hai, unse fight karta hai, to wo zyada tez swing karte hain. Ye do special tarike "normal modes" hain. Koi bhi aur crazy swinging jo tum shuru karte ho wo actually in do special taridon ka mix hai jo ek saath ho raha hai. In special taridon ko pakad ke, confusing motion do simple motions ban jaati hai.
Mnemonic SLOW = Same, FAST = Fight
S ymmetric mode S low hota hai (spring S ota rehta hai). Anti-symmetric fast hota hai (spring fight karta hai). ω 2 : chhota = k / m , bada = ( k + 2 k c ) / m .
Normal mode kya define karta hai? Ek collective motion jisme har coordinate ek single common frequency par fixed amplitude ratio mein oscillate karta hai (K − ω 2 M ka eigenvector).
Normal-mode frequencies konsi equation deti hai? Secular equation det ( K − ω 2 M ) = 0 .
Do equal masses ke liye bahari k , coupling k c ke saath do frequencies kya hain? ω 1 2 = k / m (symmetric) aur ω 2 2 = ( k + 2 k c ) / m (antisymmetric).
Symmetric mode ki frequency kam kyun hoti hai? Dono masses saath chalte hain isliye coupling spring kabhi stretch nahi hoti; sirf k restoring force deta hai.
Normal coordinate kya hota hai? Original coordinates ka ek linear combination jo uncoupled SHM equation η ¨ a = − ω a 2 η a follow karta hai.
Do equal masses ke liye normal coordinates? N-DOF system mein kitne normal modes hote hain? Exactly N.
Coupled oscillators mein 'beats' kab aate hain? Do nearly equal frequencies wale modes ke superposition se; energy masses ke beech slow envelope frequency ( ω 2 − ω 1 ) /2 se transfer hoti hai.
Ek single pure mode excite kaise karte hain? Initial conditions us mode ke eigenvector ke equal rakh do (jaise symmetric ke liye x 1 = x 2 ).
Eigenvectors konsi orthogonality follow karte hain? Mass-weighted: A a T M A b = 0 jab a = b ho.
Lagrangian Mechanics — jisse humne EOMs derive kiye bina force-sign errors ke
Simple Harmonic Motion — har normal coordinate EK SHM hai
Eigenvalues and Eigenvectors — secular equation = generalized eigenvalue problem
Beats and Superposition — do close modes ka observable consequence
Small Oscillations — V ko quadratic order tak Taylor-expand karne par K milta hai
Phonons and Lattice Vibrations — solids mein coupled oscillators ka N→∞ limit
Cross terms mixing coords
Lagrangian L equals T minus V
Coupled equations of motion
Algebraic matrix equation
K minus w2 M times A equals 0
Secular equation det equals 0
Superposition of real motion