Is chapter mein sab kuch ek aisi object ke baare mein hai jo kisi jagah rehne ke liye majboor hai: ek bead jo wire par piroyi hui hai, ek mass jo rope se latka hai, ek ball jo bina phisale roll kar rahi hai. Object khud se aazad ghoomna chahti hai (gravity khichti hai), lekin kuch cheez kuch motions ko mana karti hai. Hamara poora kaam hai ki dono — aazadi aur pabandi — ko symbols se describe karen.
Tasveer dekho: bead curve par atki hui hai. Woh wire ke saath saath slide kar sakti hai (woh arrow allowed hai) lekin wire se bahar kabhi nahi ja sakti (woh arrow mana hai). Yeh split — saath vs bahar — apne dimaag mein rakho. Neeche har symbol in do directions mein se kisi ek ke baare mein baat karne ka tool hai.
Tasveer: bead ko plane mein locate karne ke liye tum uski horizontal position x aur vertical position y de sakte ho. Yeh do numbers hain, toh q1=x, q2=y. Ya, kyunki woh circle par rehti hai, tum radius r aur angle θ de sakte ho — woh polar coordinates jo parent note pasand karta hai. Kisi bhi tarah, ek coordinate ek dial hai jise tum ghuma ke object ko hilate ho.
Topic ko yeh kyun chahiye: parent note ki har equation "k=1,…,n ke liye" chalti hai. Woh n hai kitne dials tumhare paas hain. Bina pehle coordinates ke tum constraint bhi state nahi kar sakte. Unhen choose karne ki poori kahani ke liye Generalized Coordinates and Degrees of Freedom dekho.
Question — qk mein subscript k ka asal matlab kya hai?
Yeh coordinates ko number karne wala naam tag hai (q1,q2,…); iska koi math nahi, sirf bookkeeping hai.
Question — Agar q2=θ radians mein ek angle hai, toh q˙2 kya hai?
Tasveer: radius R ke hoop par ek bead ke liye, niyam hai "centre se tumhari doori hamesha R hai." Ek function ke roop mein jo zero hona chahiye:
f=r−R=0.
Agar r=R, toh f=0 — allowed. Agar r=1.2R, toh f=0.2R=0 — forbidden. Allowed points ka set (f=0) ek surface hai (yahan, circle). f ko ek aisi height map sochho jiska "sea level" (f=0) bilkul deewar hai.
t kyun? Kabhi kabhi deewar khud time mein chalti hai (ek hoop utha ek uthaya ja raha hai, ek rope reeled in ho rahi hai). f ko time t par depend karne dena unhe cases cover karta hai. Agar deewar fixed hai, toh f mein t aata hi nahi — lekin hum general rehne ke liye t likhte hain.
Question — f=r−R=0 mein, f=0.3 ki value physically kya matlab rakhti hai?
Bead hoop se 0.3 units bahar hai — ek forbidden position.
Question — Ek constraint holonomic kyun hota hai non-holonomic ki jagah?
Yeh sirf positions (aur time) restrict karta hai, velocities kabhi nahi — toh ise f(q,t)=0 ke roop mein likha ja sakta hai.
Yeh pehla sachchi naya tool hai, toh hum ruk ke ise achhe se samajhte hain.
Yeh tool kyun chahiye aur koi nahi: hum jaanna chahte hain "deewar se bahar" kaunsi direction hai. Ek akela ordinary derivative nahi bata sakta, kyunki "bahar" ka matlab ho sakta hai x nudge karna, ya y nudge karna, ya kuch mix. Partial derivative hamare ko har direction alag se test karne deta hai, phir jawab jodne deta hai.
Tasveer: height-map surface f par khado. ∂f/∂qk woh dhaul hai jo tum feel karte ho agar qk direction mein ek kadam lo. f=r−R ke liye:
∂r∂f=1,∂θ∂f=0.r mein kadam lene se f rate 1 par badlata hai (tum seedha sea level se bahar chadh jaate ho). θ mein kadam lene se f bilkul nahi badlata — tum deewar ke saath saath slide karte ho. Woh zero mathematics ka yeh kehna hai "allowed direction θ wali hai."
Tasveer: hoop par, ∇f=(∂f/∂r,∂f/∂θ)=(1,0) — ek arrow jo radially bahar ki taraf point karta hai, circle ke bilkul perpendicular. Yahi woh direction hai jis mein ek deewar ki normal force push kar sakti hai. Yeh is poore topic ka raaz ka kaabza hai.
Question — Ek frictionless constraint force ∇f ke saath kyun point karti hai?
Kyunki ∇f surface ke perpendicular hai, aur ek smooth deewar sirf apne aap ke perpendicular push kar sakti hai.
Question — f=r−R ke liye ∇f kya hai, aur woh kaunsi direction mein hai?
(r,θ) mein (1,0) — radially bahar ki taraf point karta hai, circle se bahar.
Tasveer: bead ko pakdo aur use wire ke saath thoda hilao — kabhi wire se bahar nahi. Move ki woh chhoti si phuskari δq hai. Yeh "virtual" hai kyunki tum actually time nahi badhne dete; tum bas poochh rahe ho "kya hoga agar main ise is taraf nudge karun — kya yeh allowed hai?"
Frozen time kyun? Real motion mein object ka hilna aur deewar ka shayad hilna mix ho jaata hai. Object ki abhi deewar par aazadi ko isolate karne ke liye, hum t ko rok dete hain. Isliye constraint ki variation apna ∂f/∂t term drop kar deti hai:
δf=∑k∂qk∂fδqk=0.
Question — dqk aur δqk mein kya fark hai?
dqk ek real move hai jab time badhta hai; δqk frozen time par ek khayal mein test-nudge hai jo constraint ka maan rakhta hai.
Tasveer: bead ko hoop par adha upar imagine karo. Uski kuch speed hai (yeh T hai) aur kuch height hai (yeh V hai). L unhe ek number mein blend karta hai jo, jab hum ise sahi tarike se differentiate karte hain, Newton ke laws bahar nikalte hain — lekin kisi bhi coordinates mein, chahe ajib kyun na hon. Woh machinery Euler-Lagrange Equations hai.
"Minus" kyun? Combination T−V (T+V nahi) wahi hai jiska variation sahi equations of motion deta hai — least action ke principle ka ek gehri baat. Is foundations page ke liye, bas L=T−V ko recipe ki tarah maano; parent note ise ek black box ki tarah use karta hai.
Question — T kaunse variables par depend karta hai, aur V kaunse par?
T velocities q˙k par depend karta hai (aur shayad positions par bhi); V positions qk par depend karti hai.
Topic ko yeh kyun chahiye: ek free coordinate ke liye, is machine ko zero set karna hi motion ka niyam hai. Ek constraint ke neeche, yeh zero nahi hota — yeh bacha hua push ke barabar hota hai, constraint force λ∂f/∂qk. Toh poori parent equation padhti hai: (momentum ka rate) − (applied force) = (constraint force), jo sirf ma= (real forces) ko rewrite karna hai.
Question — ∂q˙k∂L physically kya quantity hai?
Coordinate qk ke liye generalized momentum.
Question — Ek free (unconstrained) coordinate ke liye, Euler–Lagrange machine kiske barabar hai?
Yeh kyun exist karna chahiye — saafs logic: §5 se, allowed nudge δq, ∇f ke perpendicular hai. d'Alembert se, wahi δq Euler–Lagrange bracket ke perpendicular hai. Do arrows jo ek hi flat plane ke perpendicular hain parallel hone chahiye — toh bracket =λ×∇f kisi number λ ke liye. Woh number exist karne par majboor hai; hum bas ise naam dete hain.
Question — Ek sentence mein, λ physically kya represent karta hai?
Constraint force ki magnitude/strength (tension, normal force, friction).
Question — Hamen guarantee kyun hai ki ek number λ exist karta hai jo bracket ko ∇f se jodata hai?
Dono ek hi allowed-nudge plane ke perpendicular hain, toh woh parallel hone chahiye — parallel vectors ek scalar se differ karte hain, woh scalar λ hai.
Yeh kyun matter karta hai: classic panic — "λ undetermined lagta hai!" — gayab ho jaata hai jab tum count karte ho. Constraint equation f=0 khud woh extra relation hai jo λ ko pin down karta hai. Bookkeeping le aao aur koi variable kabhi mat khona.