1.7.17Thermodynamics

γ = Cp - Cv — for monatomic, diatomic, polyatomic

1,789 words8 min readdifficulty · medium5 backlinks

WHAT is γ?


WHY does Cp>CvC_p > C_v? (Derive Mayer's relation)

HOW — from the First Law. For one mole, dQ=dU+dW=dU+PdVdQ = dU + dW = dU + P\,dV.

Constant volume: dV=0dQ=dUdV = 0 \Rightarrow dQ = dU. So Cv=(dQdT)V=dUdT.C_v = \left(\frac{dQ}{dT}\right)_V = \frac{dU}{dT}. Why this step? At fixed volume no work happens, so every joule of heat raises internal energy directly.

Constant pressure: dQ=dU+PdVdQ = dU + P\,dV. For an ideal gas PV=RTPV = RT, so at constant PP, PdV=RdTP\,dV = R\,dT. Thus Cp=dUdT+R=Cv+R.C_p = \frac{dU}{dT} + R = C_v + R. Why this step? The piston must expand to keep PP fixed; that expansion does work RdTR\,dT, which you must supply as extra heat.


WHY does γ depend on degrees of freedom?

Equipartition theorem: each active quadratic degree of freedom holds 12kBT\tfrac12 k_B T per molecule, i.e. 12RT\tfrac12 R T per mole. With ff degrees of freedom: U=f2RTCv=dUdT=f2R.U = \frac{f}{2}RT \quad\Rightarrow\quad C_v = \frac{dU}{dT} = \frac{f}{2}R.

Then Cp=Cv+R=(f2+1)RC_p = C_v + R = \left(\frac f2 + 1\right)R, and

Figure — γ = Cp - Cv — for monatomic, diatomic, polyatomic

The three cases

Gas type Translational Rotational ff CvC_v CpC_p γ=1+2/f\gamma=1+2/f
Monatomic (He, Ne, Ar) 3 0 3 32R\tfrac32 R 52R\tfrac52 R 5/31.675/3\approx1.67
Diatomic (O₂, N₂, H₂) 3 2 5 52R\tfrac52 R 72R\tfrac72 R 7/5=1.407/5=1.40
Polyatomic (CO₂ linear*, H₂O, CH₄) 3 3 6 3R3R 4R4R 4/31.334/3\approx1.33

Worked examples


Common mistakes


Recall Feynman: explain to a 12-year-old

Imagine a toy that can wiggle. A marble (monatomic) can only roll around — one kind of motion. A pencil (diatomic) can roll AND spin end-over-end — more ways to move. A spinning ball of dough (polyatomic) can tumble in every direction. Heat is like energy you pour into the toy. The toy with MORE ways to move shares the heat among all its motions, so its "temperature" (rolling speed) goes up slower. γ is just a score: the simplest toy (marble) gets the biggest γ = 1.67, the fanciest toy gets the smallest γ ≈ 1.33.


Active-recall flashcards

#flashcards/physics

Define γ
The ratio Cp/CvC_p/C_v of molar heat capacity at constant pressure to that at constant volume; always > 1.
Why is Cp>CvC_p>C_v?
At constant P the gas also does expansion work (RdTR\,dT per mole) which needs extra heat.
State Mayer's relation
CpCv=RC_p - C_v = R (for an ideal gas).
Formula for γ from degrees of freedom
γ=1+2/f\gamma = 1 + 2/f where ff is active degrees of freedom.
γ for monatomic gas
5/31.675/3 \approx 1.67 (f = 3).
γ for diatomic gas (room T)
7/5=1.407/5 = 1.40 (f = 5).
γ for polyatomic (non-linear)
4/31.334/3 \approx 1.33 (f = 6).
CvC_v of diatomic gas
52R20.8\tfrac52 R \approx 20.8 J/mol·K.
Given γ, how to find f?
f=2/(γ1)f = 2/(\gamma-1).
Why is f = 5 (not 7) for diatomic at room T?
Vibrational DOF are quantum-frozen at ordinary temperatures.
Equipartition energy per DOF per mole
12RT\tfrac12 RT.
Why does diatomic have only 2 rotational DOF?
Rotation about the bond axis has negligible moment of inertia, so it's frozen out.

Connections

Concept Map

constant V

constant P, PV=RT

defines

U = f/2 RT

substitute

f=3

f=5

f=6

translation + rotation

First Law dQ = dU + PdV

Cv = dU/dT

Cp = Cv + R

Mayer Cp - Cv = R

gamma = Cp/Cv

Equipartition theorem

Cv = f/2 R

gamma = 1 + 2/f

Monatomic gamma = 5/3

Diatomic gamma = 7/5

Polyatomic gamma = 4/3

Degrees of freedom f

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, γ = Cp/Cv ka matlab simple hai: gas ko garam karne ke do tareeke hain. Agar volume fixed rakho (Cv), to saari heat sidha internal energy badhane mein jaati hai. Agar pressure fixed rakho (Cp), to gas ko expand bhi karna padta hai, piston ko dhakka dena padta hai, isliye thodi extra heat chahiye — tabhi Cp hamesha Cv se bada hota hai. Yehi reason hai ki γ hamesha 1 se zyada hota hai. Ye extra heat exactly R ke barabar hoti hai, isko Mayer's relation kehte hain: CpCv=RC_p - C_v = R.

Ab main point: γ batata hai ki molecule ke paas kitne "degrees of freedom" (f) hain — yaani energy store karne ke kitne tareeke. Formula yaad rakho: γ=1+2/f\gamma = 1 + 2/f. Monatomic gas (jaise Helium, Argon) sirf idhar-udhar bhaag sakti hai (3 translational), to f=3, γ=5/3=1.67. Diatomic (O₂, N₂) ek dumbbell ki tarah ghoom bhi sakti hai (2 rotation extra), to f=5, γ=1.40. Polyatomic (paani, methane) har direction mein tumble karti hai (3 rotation), f=6, γ=1.33.

Notice karo — molecule jitna fancy, utne zyada boxes mein energy bat jaati hai, isliye temperature dheere badhti hai, aur γ utna hi 1 ke kareeb aata hai. Exam mein agar γ diya ho to ulta f nikaal sakte ho: f=2/(γ1)f = 2/(\gamma-1). Yeh γ aage adiabatic process (PVγPV^\gamma = const) aur sound ki speed (v=γRT/Mv=\sqrt{\gamma RT/M}) mein kaam aata hai, isliye yeh chhota sa number bahut powerful hai. Bas ek cheez yaad rakhna: room temperature pe vibration "frozen" hoti hai, isliye diatomic ke liye f=5 lete hain, 7 nahi.

Go deeper — visual, from zero

Test yourself — Thermodynamics

Connections