WHAT jo pehle chahiye: kisi vector ki time-derivative, frame ke saath rotate karne wale observer aur fixed observer ko alag-alag kaise dikhti hai.
WHY (derive karo). Socho A ko rotating basis {e^1,e^2,e^3} mein likha gaya hai:
A=A1e^1+A2e^2+A3e^3.
Components Ai numbers hain; basis vectors khud rotate karte hain. Inertial frame mein product rule se differentiate karne par:
(dtdA)in=(dA/dt)roti∑A˙ie^i+∑iAidtde^i.ω ke saath rigidly rotate karta hua ek unit vector dtde^i=ω×e^i satisfy karta hai (uski tip radius sinθ ka ek circle trace karti hai). Toh doosra sum ω×∑iAie^i=ω×A hai. Yeh step kyun? Kyunki rotation sirf basis vectors ko reorient karta hai — woh reorientation rate precisely ω× hai. ■
Transport theorem ko position vectorr par apply karo velocity pane ke liye, phir dobara acceleration ke liye.
Step 1 — velocity.A=r set karo:
vin=vrot+ω×r.Kyun? Inertial velocity = woh velocity jo tum frame ke andar measure karte ho + woh velocity jisse frame tumhe kheenchta hai.
Step 2 — acceleration. Operator (dtd)in=(dtd)rot+ω× ko vin par apply karo (ω constant maante hue):
ain=(dtd)rot(vrot+ω×r)+ω×(vrot+ω×r).
Term by term expand karo:
(dtdvrot)rot=arot
(dtd)rot(ω×r)=ω×vrot (kyunki ω˙=0)
+ω×vrot
+ω×(ω×r)
Collect karne par:
ain=arot+2ω×vrot+ω×(ω×r)
Step 3 — Newton lagao. Real forces Freal=main satisfy karte hain. Solve karo ki rotating observer kya dekhta hai, marot:
marot=FrealCoriolis−2mω×vrotcentrifugal−mω×(ω×r)
Recall Forecast-then-Verify: dekhne se pehle predict karo
Q: Equator par ek tall tower se ek ball giraayi jaati hai. Coriolis use kis taraf deflect karta hai?
Forecast… phir verify karo: v neeche ki taraf hai (axis ki taraf-ish), ω Earth ke axis ke along → −2ω×veast ki taraf point karta hai. Ball plumb line se thodi east mein girti hai. (Experimentally confirmed — Hall's drop experiments.)
Recall Feynman: 12-saal ke bacche ko samjhao
Socho tum ek ghoomte hue merry-go-round par ho. Jab floor tumhare neeche ghoomta hai, tumhara body seedha jaana chahta hai (yeh toh bas aalas/inertia hai). Lekin tumhein, jo saath ghoom rahe ho, lagta hai koi tumhe bahar dhakela raha hai — woh "dhakka" hi centrifugal make-believe force hai. Ab ek marble ghoomte hue floor par roll karo: woh sideways curve karta hai, jaise koi ghost hand uska path mod raha ho — yahi Coriolis make-believe force hai. Koi sach mein push nahi kar raha! Floor marble ke neeche ghoom raha hai, toh tumhein ek seedha path bent dikhta hai. Hum yeh pretend forces isliye invent karte hain taaki hamaara usual "force = mass × acceleration" rule tab bhi kaam kare jab hum chakkar mein ghoom rahe hon.