4.6.13 · D1 · Maths › Ordinary Differential Equations › Case 3 - complex conjugate roots — Euler's formula connecti
Jab koi bouncing, wiggling system (ek spring, ek swinging door, ek electric circuit) ko ek equation se describe kiya jaata hai, to uski natural motion hamesha ek shrinking-ya-growing wave hoti hai: ek spinning arrow (woh hai i ) times ek fading envelope (woh hai e α x ). Yeh poora topic bas yahi seekhna hai ki numbers α aur β ko equation se kaise padha jaaye aur scary i ko wapas ordinary sine aur cosine mein kaise badla jaaye.
Yeh page kuch bhi assume nahi karta. Har woh squiggle jo parent note use karta hai, neeche khol ke rebuild kiya gaya hai, ek aisi order mein jahan har piece usse pehle wale piece par khada ho.
Pehle kuch bhi samjhne se pehle, symbol y ′ .
y , aur uske primes y ′ , y ′′
y ek function hai: ek machine jo input x leta hai aur ek number y ( x ) return karta hai. Socho ek curve jo paper par khicha gaya ho — har horizontal position x ke upar height y .
y ′ (padho "y prime") derivative hai: har point par us curve ki steepness (slope). Socho woh direction jisme ek marble roll karta.
y ′′ (padho "y double prime") derivative ka derivative hai: steepness khud kitni tezi se badal rahi hai — curviness , ya physics mein acceleration.
Intuition Topic ko derivatives ki zaroorat kyun hai
Spring ka law kehta hai "acceleration depend karta hai position par". Acceleration hai y ′′ , position hai y . Woh sentence hi hai equation a y ′′ + b y ′ + cy = 0 . Bina y ′′ aur y ′ ke hum physics likh hi nahi sakte.
Dekho prerequisite Characteristic Equation of Linear ODEs jisme bataya gaya hai ki ye primes m ki powers kaise bante hain.
Definition Second-order linear homogeneous ODE with constant coefficients
Naam ko tod ke dekho:
ODE = ordinary differential equation: ek equation jo ek function ko uske apne derivatives ke saath mix karti hai.
Second-order : sabse bada prime jo present hai woh y ′′ hai (do primes).
Linear : y , y ′ , y ′′ sirf pehli power mein aate hain — koi y 2 nahi, koi sin y nahi, koi y ⋅ y ′ nahi.
Homogeneous : right-hand side 0 hai (bahar se kuch system ko force nahi kar raha).
Constant coefficients : a , b , c fixed numbers hain, x ke functions nahi.
Letters:
a , b , c ∈ R ka matlab hai ==a , b , c real numbers hain== (number line par ordinary numbers, symbol R ).
a = 0 taaki y ′′ term genuinely exist kare (warna yeh first-order hoga).
Definition Characteristic root
m
Hum guess karte hain ki solution y = e m x ki form ka hai (kyun e m x ? kyunki uska derivative khud uska copy hota hai times m ). Tab y ′ = m e m x aur y ′′ = m 2 e m x . Substitute karne aur kabhi-zero-nahi-hone-wale e m x ko cancel karne se ODE ek plain quadratic ban jaata hai:
a m 2 + bm + c = 0.
Number m ek characteristic root hai. Socho: har valid m ek "note" hai jo system baja sakta hai.
± (padho "plus or minus") ek saath do answers ka shorthand hai — ek + leta hai, doosra − . Yeh isliye aata hai kyunki ek quadratic ke do roots hote hain.
Δ = b 2 − 4 a c
Δ (capital Greek "delta") discriminant hai: quadratic formula mein square root ke neeche wali quantity. Yeh decide karta hai ki kitne, aur kis tarah ke roots milenge.
Δ ka sign ek fork kyun hai, koi detail nahi
positive ek ordinary number hai; negative number line par bilkul bhi nahi hai. Woh single sign flip hi humein majboor karta hai ek naye tarah ka number invent karne ko — agla section.
Jab Δ < 0 ho to hume ek negative number ka square root lena padta hai. Koi real number negative tak square nahi hota, to hum ek nayi cheez invent karte hain.
Definition Imaginary unit
i
i define kiya jaata hai ==i 2 = − 1 == se. To − 9 = 9 ⋅ − 1 = 3 i . Ek complex number ki shape hoti hai α + i β : real part α plus i times real part β .
Socho: ise number line par mat rakho — ise ek plane par rakho. α steps daayein jaao (real axis) aur β steps upar jaao (imaginary axis). Ek complex number ek 2-D plane mein ek point hai (origin se ek arrow).
i ki powers cycle karti hain
i 0 = 1 , i 1 = i , i 2 = − 1 , i 3 = − i , i 4 = 1 , … phir har chaar mein repeat. Socho: i se multiply karna arrow ko ek quarter-turn (9 0 ∘ ) counter-clockwise rotate karta hai. Chaar quarter-turns = wapas start par. Yeh chaar-beat rhythm exactly wahi reason hai kyun baad mein sines aur cosines ayenge.
α − i β
α + i β ka conjugate imaginary part ka sign flip karta hai: α − i β . Socho: horizontal (real) axis ke across mirror-reflection. Ek real equation ke complex roots hamesha ek mirror pair ke roop mein aate hain — yehi "α ± i β " ek line mein pack karta hai.
α (alpha) aur β (beta)
Jab hum roots ko m = α ± i β likhte hain:
α = − 2 a b real part hai — envelope number. Socho: wave kitni tezi se shrink ya grow karti hai.
β = 2 a 4 a c − b 2 > 0 imaginary part hai (sirf size) — frequency number. Socho: wave kitni tezi se wiggle karti hai.
Yeh bas roots se padhe gaye do real numbers ke naam hain.
e ko ek imaginary power tak uthana (e i θ ) magic bridge hai — Maclaurin Series of exp, sin, cos se build hua aur Euler's Formula and the Unit Circle mein khola gaya.
cos θ aur sin θ circle par coordinates ke roop mein
Radius 1 ka ek circle kheencho. Origin se ek arrow ko angle θ (Greek "theta", counter-clockwise measure) tak ghuma'o. Tab:
cos θ = arrow ka horizontal (x) coordinate.
sin θ = arrow ka vertical (y) coordinate.
Socho: jaise jaise θ badhta hai, tip ghumta rehta hai — horizontal aur vertical shadows upar-neeche wiggle karte rehte hain hamesha ke liye. Woh endless wiggle oscillation hai.
Kyunki radius 1 hai: cos 2 θ + sin 2 θ = 1 hamesha — arrow ki length kabhi nahi badalti.
Intuition Sine aur cosine kyun, koi aur wiggle kyun nahi
i ka four-beat cycle (§4) aur spinning-arrow-ka-shadow (yahaan) ek hi rhythm hai. Woh coincidence hai Euler's formula e i θ = cos θ + i sin θ — length 1 ka spinning arrow. Isi tarah roots mein i real, visible waves banta hai.
C 1 , C 2 aur superposition
Kyunki equation linear aur homogeneous hai, solutions ka koi bhi weighted sum phir bhi ek solution hoga — yeh hai Superposition Principle for Linear ODEs . Unknown weights C 1 , C 2 arbitrary constants hain jo baad mein starting conditions (initial values) se fix hote hain.
W
W ek single number hai jo do candidate solutions u , v aur unke derivatives se compute hota hai:
W = u u ′ v v ′ = u v ′ − v u ′ .
Agar W = 0 ho to do solutions linearly independent hain — genuinely alag, ek doosre ki copy nahi — to yeh ek complete basis form karte hain. Poori detail Wronskian and Linear Independence mein. Socho: W = 0 ka matlab hai ki do curves solution-space ki sach mein alag "directions" mein point karte hain.
Derivatives y prime y double prime
The ODE a y'' + b y' + c y = 0
Guess e to the m x gives quadratic in m
Discriminant Delta = b squared - 4 a c
Roots alpha plus or minus i beta
Euler formula e to i theta
Sine cosine on unit circle
Real solution e to alpha x times cos and sin
Khud test karo — daayein side cover karo.
y ′′ ka matlab haiderivative ka derivative — y ki curviness / acceleration.
Hamare ODE ke liye "homogeneous" ka kya matlab hai? right-hand side 0 hai (koi external forcing nahi).
y ko e m x se kyun replace karte hain?kyunki e m x differentiate hokar khud ki copies mein badal jaata hai, jo ODE ko quadratic a m 2 + bm + c = 0 mein badal deta hai.
Δ = b 2 − 4 a c ; kaun sa sign Case 3 deta hai?Δ < 0 (negative) → complex conjugate roots.
i define karo.imaginary unit jisme i 2 = − 1 .
i se multiply karne ka geometric matlab?complex plane mein 9 0 ∘ counter-clockwise rotation.
α + i β ka conjugate kya hai?α − i β — real axis ke across mirror.
m = α ± i β mein, α kya control karta hai?growth/decay envelope e α x .
β kya control karta hai?oscillation frequency (period 2 π / β ).
cos θ aur sin θ unit-circle arrow ke kaun se coordinates hain?horizontal (x) aur vertical (y) respectively.
∣ e i θ ∣ = 1 kyun hai?kyunki cos 2 θ + sin 2 θ = 1 — spinning arrow ki length 1 rehti hai.
W = 0 tumhe kya batata hai?do solutions linearly independent hain aur ek valid basis form karte hain.