4.6.4 · Maths › Ordinary Differential Equations
Intuition Ek line mein badi baat
Ek first-order linear ODE isliye messy lagti hai kyunki left side mein do alag terms hain — d x d y aur P ( x ) y . Trick yeh hai: ==kisi cleverly chosen function μ ( x ) se multiply karo taaki left side ek single derivative== d x d ( μ y ) mein collapse ho jaye. Jab ek baar yeh single derivative ban jaaye, toh bas dono sides integrate kar do.
"Standard form" kyun important hai: neeche diye saare formulas yeh assume karte hain ki d x d y ka coefficient exactly 1 hai. Agar tumhara a ( x ) d x d y + … hai, toh pehle puri equation ko a ( x ) se divide karo .
Hum poori equation ko kisi function μ ( x ) se multiply karna chahte hain:
μ d x d y + μ P y = μ Q .
chahte kya hain ki ho?
Hum chahte hain ki left side exactly d x d ( μ y ) ki product-rule expansion ho. Yaad karo:
d x d ( μ y ) = μ d x d y + d x d μ y .
Apni left side μ d x d y + μ P y se term-by-term compare karo:
hamari left side
product rule
μ d x d y
μ d x d y ✓ (pehle se match)
μ P y
d x d μ y
Toh sirf yahi ek condition chahiye — y ke coefficients match karein:
d x d μ = μ P ( x )
Yeh khud μ ke liye ek separable ODE hai! Ise solve karo:
μ d μ = P d x ⇒ ∫ μ d μ = ∫ P d x ⇒ ln ∣ μ ∣ = ∫ P d x .
Exponentiate karo (constant drop karo — hume sirf ek kaam karne wala factor chahiye):
Multiply karne ke baad, equation ban jaati hai:
d x d ( μ y ) = μ Q .
Dono sides ko x ke saath integrate karo:
μ y = ∫ μ Q d x + C .
Worked example Example 1 —
d x d y + 2 y = e x
Step 1: P , Q identify karo. Pehle se standard hai: P = 2 , Q = e x .
Kyun? d x d y ka coefficient 1 hai, theek hai.
Step 2: Integrating factor. μ = e ∫ 2 d x = e 2 x .
Kyun? P = 2 ko μ = e ∫ P mein plug karo.
Step 3: Multiply & collapse. d x d ( e 2 x y ) = e 2 x e x = e 3 x .
Kyun? Left side guaranteed ek single derivative hai jab humne μ use kiya.
Step 4: Integrate. e 2 x y = 3 1 e 3 x + C .
Step 5: y ke liye solve karo. y = 3 1 e x + C e − 2 x .
Kyun? μ = e 2 x se divide karo; e 3 x / e 2 x = e x .
Worked example Example 2 —
x d x d y + y = cos x (pehle standardize karna zaroori!)
Step 1: Standardize. x se divide karo: d x d y + x 1 y = x c o s x .
Kyun? Formula ko d x d y par coefficient 1 chahiye.
Toh P = x 1 , Q = x c o s x .
Step 2: μ = e ∫ x 1 d x = e l n ∣ x ∣ = x .
Kyun? ∫ x 1 d x = ln ∣ x ∣ , aur e l n x = x .
Step 3: d x d ( x y ) = x ⋅ x c o s x = cos x .
Yahan dhyan do: μ = x ko Q = x c o s x se multiply karne par nicely cancel ho jaata hai — yeh sign hai ki standardize sahi kiya.
Step 4: x y = sin x + C ⇒ y = x s i n x + C .
Worked example Example 3 — IVP:
d x d y − y = x , y ( 0 ) = 1
P = − 1 , Q = x . μ = e ∫ − 1 d x = e − x .
d x d ( e − x y ) = x e − x .
Integrate by parts: ∫ x e − x d x = − x e − x − e − x + C .
Toh e − x y = − x e − x − e − x + C ⇒ y = − x − 1 + C e x .
y ( 0 ) = 1 apply karo: 1 = − 0 − 1 + C ⇒ C = 2 .
Answer: y = − x − 1 + 2 e x .
IC aakhir mein kyun apply karein? Constant C tabhi fix hota hai jab general solution mil jaaye.
Common mistake "Main pehle divide kiye bina seedha
μ = e ∫ P mein plug kar dunga."
Kyun sahi lagta hai: equation pehle se hi linear lagti hai, toh kyun mushkil karein? Trap: agar d x d y ka coefficient 1 nahi hai, toh woh term jo μ P y ke barabar honi chahiye woh galat hogi, aur product rule collapse nahi karega. Fix: hamesha pehle d x d y + P y = Q mein normalize karo.
Common mistake Integrating factor mein
+ C add karna.
Kyun sahi lagta hai: har integral ko + C milta hai. Trap: hume sirf ek aisa μ chahiye jo kaam kare; ek exponential ke andar extra constant ek harmless multiplicative factor e C ban jaata hai jo cancel ho jaata hai. Fix: μ compute karte waqt constant drop karo; + C sirf final integration par rakho.
Common mistake Final answer ko
μ se divide karna bhool jaana.
Kyun sahi lagta hai: tum μ y = … tak pahunch jaate ho aur done feel karte ho. Trap: woh μ y hai, y nahi. Fix: poori right side (including C ) ko μ ( x ) se divide karo.
e l n ∣ x ∣ ko galat handle karna.
Fix: e ∫ x n d x = e n l n ∣ x ∣ = ∣ x ∣ n ; solution banate waqt hum usually relevant domain par x n lete hain.
Recall Quick self-test (answers cover karo)
Method apply karne se pehle d x d y ka coefficient KYA hona chahiye? → 1
Left side kaunsa single derivative ban jaati hai? → d x d ( μ y )
Constant C kahan jaata hai? → sirf final integration step par
Recall Feynman: ek 12-saal ke bachche ko explain karo
Socho do bachche hain, "d x d y -wala bachcha" aur "P y -wala bachcha", jo haath nahi pakadna chahte isliye tum unhe saath nahi utha sakte. Integrating factor μ ek special pair of mittens hai: jab sabne ek hi mittens pehne, woh jadu se ek bundle, μ y , mein jud jaate hain, jise tum ek hi baar mein uthaa (integrate) sakte ho. Mittens aise chosen hain ki joining automatic ho — isliye μ = e ∫ P .
Mnemonic Recipe yaad rakho:
"Standardize, Mu, Multiply, Integrate, Divide" → "Some Monkeys Make Ice Drinks."
First-order linear ODE ki standard form? d x d y + P ( x ) y = Q ( x )
Integrating factor ka formula? μ ( x ) = e ∫ P ( x ) d x
μ par kaunsi condition left side ko single derivative banati hai?d x d μ = μ P ( x )
μ se multiply karne ke baad, LHS kaunse single derivative ke barabar hoti hai?d x d ( μ y )
Linear ODE ka general solution? y = μ 1 [ ∫ μ Q d x + C ]
Agar y ′ ka coefficient 1 nahi hai toh pehle kya karna chahiye? Poori equation ko us coefficient se divide karo taaki standardize ho jaye
μ compute karte waqt + C kyun drop karte hain?Yeh ek multiplicative e C ban jaata hai jo cancel ho jaata hai; ek kaam karne wala factor kaafi hai
d x d y + x 1 y = … ke liye μ ?μ = e ∫ x 1 d x = x
d x d y + 2 y = e x ke liye integrating factor kya hai?e 2 x
Integration constant kahan introduce hota hai? Sirf final integration μ y = ∫ μ Q d x + C par
Separable ODEs — is derivation ke andar μ solve karne ke liye use hota hai.
Product Rule — woh engine jo μ d x d y + μ P y = d x d ( μ y ) possible banata hai.
Exact ODEs — integrating factors non-exact equations ko exact banane tak generalize hote hain.
Bernoulli Equations — substitution v = y 1 − n se linear form mein reduce ho jaati hain.
Linear Constant-Coefficient ODEs — special case jahan P , Q constant hain.
Standard form dy/dx + Py = Q
Want left side as single derivative
Product rule d/dx of mu y
Integrating factor mu = exp integral P