Hum chain rule se shuru karte hain, yahi ek cheez hame chahiye.
y depend karta hai x pe, aur x depend karta hai t pe:
dtdy=dxdy⋅dtdx
Yeh sirf chain rule hai jo y pe apply kiya gaya hai t ke function ke roop mein throughx. Ab jo hum chahte hain uske liye solve karo, dono sides ko dtdx se divide karo (allowed jab dtdx=0 ho):
Socho tum car chala rahe ho. GPS tumhe tumhari east-west speed aur north-south speed alag alag bata raha hai. Map pe tumhara path kitna steep hai? Bas north-speed ko east-speed se divide karo — wahi slope hai. Tumhe road ka koi equation chahiye hi nahi tha! "Slope khud kitna bend ho raha hai" ke liye (second derivative), tum sirf accelerations divide nahi kar sakte; tumhe track karna hoga ki slope kaise change hoti hai jab tum east move karte ho, matlab east-speed se ek extra baar divide karna padega — wahi rahasyamayi "cube" x˙3 hai.
Slope vertical aur horizontal change ka ratio hai; common factor dt divide ho jaata hai, isliye chalne ki speed irrelevant hai.
Parametric second derivative formula likho.
dx2d2y=x˙3y¨x˙−y˙x¨.
dx2d2y=x¨y¨ kyun hai?
Kyunki d2y/dx2 ka matlab hai dy/dx ko x ke w.r.t. differentiate karna (t ke through), jisse quotient-rule result milta hai jo phir x˙ se divide hota hai.
Power x˙3 kahan se aati hai?
x˙2 quotient rule se y˙/x˙ pe, aur ek aur x˙ aakhiri ÷dx/dt se.
Jab x˙=0 ho toh geometrically kya hota hai?
Vertical tangent; dy/dx undefined hai (slope →∞).
x=cost,y=sint ke liye dy/dx nikalo.
−cott.
dy/dx se d2y/dx2 nikalne ka general method kya hai?
dy/dx ko t ke w.r.t. differentiate karo, phir dx/dt se divide karo.