4.1.19 · Maths › Calculus I — Limits & Derivatives
Intuition Badi baat (YEH kyun matter karta hai)
Jyadatar functions differentiate karne par zyada complicated ho jaate hain (x 3 → 3 x 2 , sin → cos ). Lekin e x woh ek function hai jo apna khud ka derivative hai : har point par uska slope uski height ke barabar hota hai. Yahi ek fact hai jo e ko "natural" base banata hai aur yahi wajah hai ki e x growth, decay, aur probability mein sabse important hai. Neeche sab kuch ek hi sawaal ka jawaab dene ke liye banaya gaya hai: ek exponential ka slope kya hota hai, aur e special kyun hai?
Definition First principles se derivative
Kisi bhi f ke liye,
f ′ ( x ) = lim h → 0 h f ( x + h ) − f ( x ) .
Yeh tangent ka slope hai: rise over run jab run h shrink hokar 0 ho jaata hai.
Isse f ( x ) = a x par apply karo jahan a > 0 ho. KAISE: exponent law a x + h = a x a h use karo.
f ′ ( x ) = h → 0 lim h a x + h − a x = h → 0 lim h a x a h − a x = a x ⋅ isse M ( a ) kehte hain h → 0 lim h a h − 1 .
a x limit se bahar nikal jaata hai
x sirf a x mein hai, jo h → 0 hone par ek constant ki tarah hai — yeh h par depend nahi karta. Isliye yeh limit se bahar aa jaata hai. Jo bacha, M ( a ) = lim h → 0 h a h − 1 , woh ek pure number hai jo sirf a par depend karta hai. Yeh a x ka slope x = 0 par hai (wahan height a 0 = 1 hoti hai).
Toh har exponential ke liye:
d x d a x = M ( a ) a x , M ( a ) = h → 0 lim h a h − 1
Derivative wahi function hai, bas constant M ( a ) se scale hoke.
e special KYUN hai
Hum ek aisi base chahte hain jahan slope-at-0 exactly 1 ho, taaki function apna khud ka derivative ho bina kisi annoying constant ke. e ko wahi base define karo:
lim h → 0 h e h − 1 = 1.
Yeh e ≈ 2.71828 ko define karne ka ek clean tarika hai. Isse:
d x d e x = e x
M ( a ) = 1 self-derivative kyun deta hai
§1 ke boxed result mein a = e plug karo: d x d e x = M ( e ) e x = 1 ⋅ e x = e x . Yeh step kyun? Kyunki humne e ko specifically isliye choose kiya taaki M ( e ) = 1 ho.
Consistency check (pehle forecast, phir verify): kya yeh limit definition famous e = lim n → ∞ ( 1 + n 1 ) n se agree karti hai? h ko chhota maano: e h − 1 ≈ h ka matlab hai e h ≈ 1 + h , yani e ≈ ( 1 + h ) 1/ h . h = 1/ n → 0 lene par e = lim ( 1 + 1/ n ) n milta hai. ✓ Same number.
Hum M ( a ) ko ek mystery limit ki tarah nahi chhodna chahte. KAISE: kisi bhi base ko e ki terms mein likho.
a = e l n a ⟹ a x = ( e l n a ) x = e ( l n a ) x .
Ab e ( l n a ) x ko chain rule se differentiate karo (outer e u , inner u = ( ln a ) x ):
d x d a x = d x d e ( l n a ) x = e ( l n a ) x ⋅ ( ln a ) = a x ln a .
ln a kyun aur kuch kyun nahi
Agar a = e , toh ln a = ln e = 1 → slope constant = 1 → self-derivative. ✓
Agar a > e toh curve 0 par zyada steep hai, aur actually ln a > 1 bhi hai. Agar a < 1 (decay) hai, toh ln a < 0 , isliye slope negative hai — curve girta hai. Sab picture ke saath consistent hai.
d x d e 5 x
Inner function u = 5 x , u ′ = 5 . Chain rule: e 5 x ⋅ 5 = 5 e 5 x .
Yeh step kyun? e x apna khud ka derivative hai, isliye extra factor sirf inner derivative 5 hai.
d x d 2 x 2
2 x 2 = e x 2 l n 2 likho. Derivative = e x 2 l n 2 ⋅ ( 2 x ln 2 ) = 2 x 2 ( 2 x ) ln 2 .
Kyun? Base e mein convert karo taaki chain rule clean rahe; x 2 ln 2 ka inner derivative 2 x ln 2 hai.
e x ka slope x = 0 par vs 2 x ka x = 0 par
e x : slope = e 0 = 1 . 2 x : slope = 2 0 ln 2 = ln 2 ≈ 0.693 .
Kyun matter karta hai: 2 x shuru mein e x se dheere rise karta hai — diagram mein yeh ek gentler tangent ki tarah dikhta hai.
d x d a x = x a x − 1 "
Kyun sahi lagta hai: yeh power rule d x d x n = n x n − 1 ko copy karta hai.
Kyun galat hai: x n mein base vary karta hai aur exponent fixed hota hai; a x mein exponent vary karta hai aur base fixed hota hai — opposite situation, isliye power rule apply nahi hota.
Fix: exponential variable → a x ln a . Yaad rakho kaun si cheez move kar rahi hai.
d x d e x = x e x − 1 "
Same power-rule trap a = e ke saath. Fix: e x apna khud ka derivative hai, bas.
d x d e 5 x = e 5 x (chain rule bhool gaye)"
Kyun sahi lagta hai: "e kuch bhi apna khud ka derivative hai." Yeh tabhi sach hai jab kuch bhi = x ho.
Fix: inner derivative se multiply karo: e 5 x ⋅ 5 .
M ( a ) = log 10 a "
Kyun sahi lagta hai: "a ka log" vague hai. Fix: proof a = e l n a force karta hai natural log ke saath. Yeh ln a hona chahiye, log 10 a nahi.
Recall Feynman style: ek 12-saal ke bachche ko samjhao
Socho aisa paisa jo grow karta hai. Ek normal curve jaise x 2 jab upar jaata hai toh speed up karta hai, lekin uska slope ek alag shape hota hai. e x woh magic curve hai jahan abhi kitna steep hai woh exactly abhi kitna tall hai uske barabar hai . Toh agar yeh 5 units tall hai, toh speed 5 se climb kar raha hai. Doosre growth-curves jaise 2 x ya 3 x ke liye, climb-speed height times ek fixed "personality number" hai — aur woh number base ka natural log hota hai. e woh ek base hai jiska personality number exactly 1 hai, isliye mathematicians ise natural kehte hain.
"e selfie leta hai, baaki ln pehnte hain."
e x selfie leta hai (khud ko return karta hai). a x ko ln a coat pehnnna padta hai: a x ln a .
d x d e x kya hai?e x (yeh apna khud ka derivative hai).
d x d a x kya hai?a x ln a .
Difference quotient mein a x factor kyun hota hai a x M ( a ) ki tarah? Kyunki a x + h = a x a h , aur a x h mein constant hai isliye limit se bahar aa jaata hai; M ( a ) = lim h → 0 h a h − 1 .
Limit M ( a ) = lim h → 0 h a h − 1 kiske barabar hai, aur yeh kya represent karta hai? ln a ; yeh a x ka slope x = 0 par hai.
Is limit ke through e kaise define hota hai? e woh base hai jिसके liye lim h → 0 h e h − 1 = 1 ho.
e se d x d a x derive karo.a x = e ( l n a ) x ; chain rule se e ( l n a ) x ⋅ ln a = a x ln a milta hai.
d x d e 5 x kya hai aur sirf e 5 x kyun nahi?5 e 5 x ; chain rule inner derivative 5 se multiply karta hai.
2 x 2 differentiate karo.2 x 2 ( 2 x ) ln 2 .
"d x d a x = x a x − 1 " galat kyun hai? Power rule fixed exponent/varying base ke liye hai; yahan exponent vary karta hai, isliye apply nahi hota.
2 x ka slope x = 0 par?ln 2 ≈ 0.693 .
M of a = limit of a^h - 1 over h
e = limit of 1+1/n to the n