3.6.6 · Hinglish3D Geometry

Equation of a line in 3D — vector, symmetric, parametric forms

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3.6.6 · Maths › 3D Geometry


1. Vector form — master equation

KYUN yeh kaam karta hai (scratch se derivation): Maano line par koi bhi point hai aur uس par ek fixed point hai. Vector line ke saath saath rehta hai, isliye yeh direction ke parallel hona chahiye. Do parallel vectors ek doosre ke scalar multiples hote hain: Ab ko origin se position vectors use karke likho: Substitute karo: Yeh step kyun? Kyunki "line par hona" ka matlab yehi hai ki ek fixed point se displacement, direction ka ek multiple ho — aur kuch nahi.

Figure — Equation of a line in 3D — vector, symmetric, parametric forms

2. Parametric form — vector ko coordinates mein tod do

Maano aur (direction ratios). Likho .

(x,y,z)=(x_1+\lambda a,\; y_1+\lambda b,\; z_1+\lambda c)$$ > [!formula] Parametric equations > $$x = x_1+\lambda a,\qquad y=y_1+\lambda b,\qquad z=z_1+\lambda c$$ > Numbers $a,b,c$ line ke ==direction ratios== (DRs) hain. **KAISE use karein:** $\lambda$ ki koi value plug karo → ek point milega. $\lambda=0$ anchor $A$ deta hai; $\lambda=1$, $A+\vec{b}$ deta hai, wagera. --- ## 3. Symmetric (Cartesian) form — $\lambda$ hatao > [!intuition] KYUN $\lambda$ hatate hain > $\lambda$ "scaffolding" hai. Agar hum har parametric equation ko $\lambda$ ke liye solve karein, toh teeno expressions usi $\lambda$ ke barabar honge, toh woh ek doosre ke barabar hain — aur $\lambda$ gayab ho jaata hai. Parametric equations se (maano $a,b,c\neq 0$): $$\lambda=\frac{x-x_1}{a},\qquad \lambda=\frac{y-y_1}{b},\qquad \lambda=\frac{z-z_1}{c}.$$ Inhe barabar karo: > [!formula] Symmetric form > $$\frac{x-x_1}{a}=\frac{y-y_1}{b}=\frac{z-z_1}{c}\;(=\lambda)$$ > **Point** $(x_1,y_1,z_1)$ numerators se padho, **direction ratios** $(a,b,c)$ denominators se. > [!mistake] Jab koi denominator zero ho > Galat instinct: "$\frac{z-z_1}{0}$ likho aur aage badho." Yeh theek lagta hai kyunki pattern symmetric dikhta hai — lekin 0 se divide karna meaningless hai. > **Fix:** zero DR ka matlab hai line us coordinate mein **constant** hai. Agar $c=0$, likho > $$\frac{x-x_1}{a}=\frac{y-y_1}{b},\qquad z=z_1.$$ > Teesra coordinate frozen hai; yeh line ke saath kabhi nahi badlega. --- ## 4. Do points se line > [!definition] Two-point form > Points $A(\vec{a})$ aur $B(\vec{b})$ se hone wali line ki direction $\vec{b}-\vec{a}$ hai, toh > $$\vec{r}=\vec{a}+\lambda(\vec{b}-\vec{a}).$$ > Cartesian: > $$\frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1}=\frac{z-z_1}{z_2-z_1}.$$ **KYUN:** "$A$ se $B$ ki taraf" direction *hi* $\vec{AB}=\vec{b}-\vec{a}$ hai. Anchor bas $A$ hai. Wahi master equation, naya costume. --- ## 5. Worked examples > [!example] Example 1 — Teeno forms banao > $A(2,-1,3)$ se $\vec{b}=2\hat i+3\hat j-\hat k$ ke parallel line ke vector, parametric aur symmetric forms dhundho. > > **Vector:** $\vec{r}=(2\hat i-\hat j+3\hat k)+\lambda(2\hat i+3\hat j-\hat k)$. > *Kyun?* Master equation: anchor $+$ $\lambda\cdot$direction. > > **Parametric:** $x=2+2\lambda,\; y=-1+3\lambda,\; z=3-\lambda$. > *Kyun?* $\vec{r}$ ke components alag alag padho. > > **Symmetric:** $\dfrac{x-2}{2}=\dfrac{y+1}{3}=\dfrac{z-3}{-1}$. > *Kyun?* Har parametric equation ko $\lambda$ ke liye solve karo aur barabar karo. Note karo $y-(-1)=y+1$. > [!example] Example 2 — Do points > $P(1,0,2)$ aur $Q(4,5,2)$ se line. > > Direction $=\vec{PQ}=(4-1,\,5-0,\,2-2)=(3,5,0)$. > *Yeh step kyun?* Direction points ke beech ka displacement hai. > > Kyunki $c=0$ (z-DR zero hai), line plane $z=2$ mein rehti hai: > $$\frac{x-1}{3}=\frac{y-0}{5},\qquad z=2.$$ > *Kyun?* Dono points ka $z$-coordinate $2$ hai, toh yeh badal nahi sakta. > [!example] Example 3 — Symmetric form se info padho > Diya gaya $\dfrac{x+1}{4}=\dfrac{y-2}{-1}=\dfrac{z}{3}$, ek point aur direction batao. > > $\dfrac{x-x_1}{a}$ se match karo: numerator $x+1=x-(-1)\Rightarrow x_1=-1$. Similarly $y_1=2$, aur $z=z-0\Rightarrow z_1=0$. > **Point** $(-1,2,0)$, **direction** $(4,-1,3)$. > *Kyun?* Numerators point encode karte hain, denominators DRs — hamesha signs check karo $x-x_1$ likhke. > [!example] Example 4 — Pehle Andaza, Phir Verify > **Andaza:** Kya point $(6,1,0)$ line $\vec r=(0,3,2)+\lambda(2,-1,-1)$ par hai? Pehle guess karo. > **Verify:** $x$ solve karo: $6=0+2\lambda\Rightarrow\lambda=3$. $y$ check karo: $3+3(-1)=0\neq 1$. ✗ > Toh point line par **nahi** hai (ek $\lambda$ *teeno* equations ek saath satisfy karna chahiye). *Kyun?* Wahi parameter sabhi coordinates control karta hai. --- > [!mistake] Teen classic traps ko steel-man karo > 1. **"Direction ratios actual point displacements hone chahiye."** Sahi lagta hai kyunki two-point form mein $(x_2-x_1)$ etc. use hota hai. Lekin direction ka *koi bhi* scalar multiple kaam karta hai — $(2,3,-1)$ aur $(4,6,-2)$ ek hi line dete hain. **Fix:** DRs sirf ek nonzero scalar tak unique hain. > 2. **"Symmetric form ke numerators direction hain."** Galat — numerators **point** dete hain, denominators **direction** dete hain. **Fix:** hamesha $\frac{x-x_1}{a}$ likhke dono ko label karo. > 3. **"Ek point line par hai agar woh ek equation fit kare."** Sufficient lagta hai. **Fix:** *usi* $\lambda$ ko teeno satisfy karne chahiye; har jagah check karo. --- > [!recall]- Feynman: ek 12-saal ke bachche ko samjhao (click to reveal) > Socho tum ek bade kamre mein ek jagah khade ho aur apna haath kisi direction mein pointing kar rahe ho. Line woh **har jagah hai jo tum apne haath ke saath seedha chalne par hit karte**, aage ya peeche, kitne bhi steps. Jis jagah se tum shuru ho woh "point" hai, tumhare haath ki direction "direction" hai. Agar tum $\lambda$ steps loge (negative = peeche), tum line par utaroge. Yahi poora secret hai — starting point plus ek direction. > [!mnemonic] Structure yaad karo > **"PADDLE"** → **P**oint **A**nchor, **D**irection **D**rives, **L**ambda **E**xplores. > Aur symmetric form ke liye: **"Top = tum KAHAN ho (point), Bottom = tum KAHAN jaate ho (direction)."** --- ## #flashcards/maths 3D mein ek line uniquely determine karne ke liye kaunse do data chahiye? ::: Line par ek point aur uss ke parallel ek direction vector. $\vec a$ se $\vec b$ ke parallel line ki vector equation? ::: $\vec r = \vec a + \lambda\vec b$, $\lambda\in\mathbb R$. $\vec r-\vec a=\lambda\vec b$ kyun hai? ::: Kyunki $\vec{AP}$ line ke saath rehta hai isliye woh $\vec b$ ke parallel hai, hence uska scalar multiple hai. Symmetric form mein numerators kya encode karte hain? ::: Line par fixed point $(x_1,y_1,z_1)$. Symmetric form mein denominators kya encode karte hain? ::: Line ke direction ratios $(a,b,c)$. Zero direction ratio ko, jaise $c=0$, kaise handle karte hain? ::: Us fraction ko drop karo aur $z=z_1$ likho (coordinate constant hai) doosre equal ratios ke saath. Points $A$ aur $B$ se hone wali line ki direction? ::: $\vec b-\vec a$ (yaani $\vec{AB}$). Kya direction ratios unique hain? ::: Nahi — sirf ek nonzero scalar multiple tak; $(2,3,-1)$ aur $(4,6,-2)$ ek hi direction describe karte hain. Test kaise karein ki koi point parametric line par hai? ::: Ek coordinate se $\lambda$ dhundho aur check karo ki wahi $\lambda$ teeno equations satisfy karta hai. $\lambda=0$ par kaunsa point milta hai? ::: Anchor point $\vec a$ khud. --- ## Connections - [[Vectors — scalar multiplication & parallel vectors]] ($\vec{AP}=\lambda\vec b$ ke peeche ka engine) - [[Direction ratios and direction cosines]] - [[Angle between two lines in 3D]] - [[Shortest distance between two skew lines]] - [[Equation of a plane in 3D]] - [[Coplanarity of two lines]] - [[Distance of a point from a line in 3D]] ## 🖼️ Concept Map ```mermaid flowchart TD A[Line in 3D] -->|needs| PT[Anchor point A] A -->|needs| DIR[Direction vector b] PT -->|combine| VEC[Vector form r = a + lambda b] DIR -->|combine| VEC VEC -->|derived from| AP[AP parallel to b] VEC -->|read coordinates| PAR[Parametric form] PAR -->|x1 y1 z1| POINT[Point coords] PAR -->|a b c| DR[Direction ratios] PAR -->|eliminate lambda| SYM[Symmetric form] DR -->|denominators| SYM POINT -->|numerators| SYM VEC -->|lambda is| SCAL[Scalar parameter] ``` ## 🔬 Deep Dive > [!intuition] Aur gehraai mein jao — visual, zero se > Is topic ke step-by-step 3Blue1Brown-style breakdowns. - [[3.6.06 D1 Foundations|D1 · Foundations — har symbol zero se]] - [[3.6.06 D2 Visual Walkthrough|D2 · Visual walkthrough — derivation pictures mein]] - [[3.6.06 D3 Worked Examples|D3 · Worked examples — har scenario]] - [[3.6.06 D4 Exercises|D4 · Exercises — graded, full solutions]] - [[3.6.06 D5 Question Bank|D5 · Question bank — concept traps]]