Ye magic isliye hai kyunki B2−4AC ek rotation invariant hai: axes ko rotate karo taaki xy term khatam ho jaye, aur ye number nahi badalta. To ye shape ki koi intrinsic cheez capture karta hai, tilt ki nahi.
Step 1 — Axes ko angle θ se rotate karo. Replace karo
x=x′cosθ−y′sinθ,y=x′sinθ+y′cosθ.Ye step kyun? Ek tilted conic kisi rotated frame mein axis-aligned ho jaati hai; hum woh frame dhundhna chahte hain.
Step 2 — Ax2+Bxy+Cy2 mein substitute karo. Terms collect karne par naye coefficients A′,B′,C′ milte hain:
A′=Acos2θ+Bcosθsinθ+Csin2θ,C′=Asin2θ−Bcosθsinθ+Ccos2θ,B′=Bcos2θ−(A−C)sin2θ.Ye step kyun? Hum dekhna chahte hain ki A,B,C kaise transform hote hain, taaki ek aisi quantity dhundh sakein jo fixed rahe.
Step 3 — θ choose karo taaki cross term eliminate ho.B′=0 set karo:
Bcos2θ=(A−C)sin2θ⇒tan2θ=A−CB.Ye step kyun? Jab B′=0 ho jata hai, equation mein xy nahi hota: ye ek standard, un-tilted conic hai jise hum instantly pehchan lete hain.
Step 4 — B′2−4A′C′ compute karo. Algebra ke baad (neeche verified):
B′2−4A′C′=B2−4AC.Ye step kyun? Ye prove karta hai ki B2−4AC rotation ke under invariant hai — ye shape ki property hai, tilt ki nahi.
Ek conic collapse ho sakti hai: ellipse ek point mein, hyperbola do crossing lines mein, parabola parallel lines mein. Inhe pakadne ke liye full 3×3 determinant use karo:
Δ=AB/2D/2B/2CE/2D/2E/2F.
Recall Reveal se pehle predict karo (Forecast-then-Verify)
Q: 4x2+4xy+y2+x=0 ke liye B2−4AC ka sign kya hai?
Forecast karo, phir check karo: B2−4AC=16−16=0 → parabola (waakai 4x2+4xy+y2=(2x+y)2).
Recall Feynman: ek 12-saal ke bacche ko samjhao
Ek flashlight imagine karo. Use seedha diwar par maro — tumhe ek round/oval blob milta hai (ellipse). Use thoda tiracha karo jab beam ka edge diwar ko skim kare — blob ek taraf se forever khul jaata hai (parabola). Zyada tiracha karo aur light do curved patches mein split ho jaati hai (hyperbola). x2,xy,y2 wali messy equation sirf woh describe kar rahi hai jahan light padti hai. Use draw karne ki jagah, hum ek magic number compute karte hain, B2−4AC: negative = oval, zero = just-skimming case, positive = two-patch case. xy term ka matlab sirf hai ki flashlight ek angle par pakdi hui hai — ye number badal deta hai lekin kabhi nahi badalta ki teen shapes mein se kaun si milegi.