3.4.2 · Maths › Conic Sections
Intuition Har parabola ke peeche ek hi idea
Parabola un sabhi points ka set hai jo ek fixed point (focus) aur ek fixed line (directrix) se equidistant hote hain .
YE kyun zaroori hai: neeche diya hua har formula bas is ek sentence ko coordinates mein likha hua hai. Agar tumhe sirf "distance to focus = distance to directrix" yaad hai, toh tum scratch se charon standard forms rebuild kar sakte ho — kuch bhi memorize karne ki zaroorat nahi.
Ek fixed point F (focus ) aur ek fixed line ℓ (directrix ) diya hua hai jo F se nahi guzarti, toh parabola un points P ka locus hai jiske liye
distance ( P , F ) = distance ( P , ℓ ) .
Constant ratio (eccentricity) hai e = 1 .
PARTS kya hain?
Focus F — woh special point.
Directrix — woh special line.
Axis — focus se guzarne wali line, directrix ke perpendicular (symmetry ki axis).
Vertex — axis pe parabola ka woh point jo focus aur directrix ke beech exactly midway hota hai.
Latus rectum — focus se guzarne wala chord, directrix ke parallel.
KAISE — convenient coordinates set karo. Vertex ko origin pe rakho, axis x -axis ke along, focus dayi taraf F = ( a , 0 ) pe jahan a > 0 ho. Kyunki vertex focus aur directrix ke beech midway hai, isliye directrix hai x = − a .
Maano P = ( x , y ) .
Focus tak distance: P F = ( x − a ) 2 + y 2 .
Directrix x = − a tak distance: perpendicular distance = ∣ x + a ∣ .
Inhe equal karo (definition), phir square karo:
( x − a ) 2 + y 2 = ( x + a ) 2
Square kyun karte hain? Square root aur absolute value dono ko cleanly khatam karne ke liye — dono sides non-negative hain.
Expand karo:
x 2 − 2 a x + a 2 + y 2 = x 2 + 2 a x + a 2
x 2 aur a 2 cancel ho jaate hain:
y 2 = 4 a x
YE kyun jaanna zaroori hai? Ye batata hai ki parabola focus pe kitna "wide" hai — sketch banane mein kaam aata hai.
Latus rectum woh chord hai jo F = ( a , 0 ) se guzarta hai aur directrix ke parallel hai, yaani vertical line x = a . Isse y 2 = 4 a x mein substitute karo:
y 2 = 4 a ⋅ a = 4 a 2 ⟹ y = ± 2 a .
Toh endpoints hain ( a , 2 a ) aur ( a , − 2 a ) . Length:
LR = 2 a − ( − 2 a ) = 4 a .
Sign badalne aur usi derivation mein x ↔ y swap karne se hume charon milte hain. (Hamesha a > 0 ; equation mein sign direction control karta hai.)
Equation
Opens
Focus
Directrix
Axis
LR
y 2 = 4 a x
Right
( a , 0 )
x = − a
y = 0
4 a
y 2 = − 4 a x
Left
( − a , 0 )
x = a
y = 0
4 a
x 2 = 4 a y
Up
( 0 , a )
y = − a
x = 0
4 a
x 2 = − 4 a y
Down
( 0 , − a )
y = a
x = 0
4 a
Intuition Equation ko map ki tarah padhna
Agar y 2 aaye → axis hai x -axis (horizontal opening).
Agar x 2 aaye → axis hai y -axis (vertical opening).
Focus usi side pe hota hai jis taraf parabola khulta hai. Sign + ⇒ right/up, − ⇒ left/down.
y 2 = 12 x ka focus, directrix, LR nikalo
Step 1: y 2 = 4 a x se match karo. Toh 4 a = 12 ⇒ a = 3 .
Kyun? x ka coefficient hi 4 a hai, isliye a uska one-quarter hai.
Step 2: Right ki taraf khulta hai (y 2 , positive). Focus = ( a , 0 ) = ( 3 , 0 ) .
Step 3: Directrix x = − a ⇒ x = − 3 .
Step 4: Axis y = 0 ; Latus rectum = 4 a = 12 .
Worked example Ex 2 — Parabola
x 2 = − 8 y
Step 1: x 2 = − 4 a y se match karo. Toh 4 a = 8 ⇒ a = 2 .
Negative kyun? x 2 ke saath minus matlab ye down ki taraf khulta hai.
Step 2: Focus = ( 0 , − a ) = ( 0 , − 2 ) . Directrix y = a = 2 .
Step 3: Axis x = 0 ; LR = 8 .
Worked example Ex 3 — Data se equation banao
Focus ( 0 , 4 ) , directrix y = − 4 .
Step 1: Focus origin ke upar, directrix neeche → up ki taraf khulta hai, form x 2 = 4 a y .
Kyun? Vertex midway pe hai → ( 0 , 0 ) ; focus ( 0 , a ) pe hai toh a = 4 .
Step 2: x 2 = 4 ( 4 ) y ⇒ x 2 = 16 y .
Check: directrix honi chahiye y = − a = − 4 . ✓
Worked example Ex 4 — Ek point + definition se reverse karna
Focus ( 2 , 0 ) aur directrix x = − 2 se seedha definition se parabola ki equation nikalo.
Step: ( x − 2 ) 2 + y 2 = ∣ x + 2∣ . Square karo: ( x − 2 ) 2 + y 2 = ( x + 2 ) 2 ⇒ y 2 = 8 x .
Ye kyun kaam karta hai: humne standard form assume nahi ki — humne ise derive kiya, jo confirm karta hai a = 2 , LR = 8 .
y 2 = 12 x mein, a = 12 ."
Ye sahi kyun lagta hai: a equation mein "woh number" lagta hai.
Fix: coefficient 4 a hai, a nahi. Yahan 4 a = 12 ⇒ a = 3 . Hamesha 4 se divide karo.
y 2 = 4 a x ki directrix x = a hai."
Ye sahi kyun lagta hai: tum a ko focus ( a , 0 ) se associate karte ho aur reuse kar dete ho.
Fix: directrix vertex ke focus wali side se opposite side pe hoti hai, isliye x = − a . Vertex midpoint hai.
x 2 = 4 a y sideways khulta hai kyunki x hai."
Ye sahi kyun lagta hai: tum "squared variable = direction" match karte ho.
Fix: ye ulta hai — non-squared variable ki axis hi axis of symmetry hai. x 2 squared → up/down khulta hai (axis = y -axis).
a < 0 ko valid standard form maanna.
Ye sahi kyun lagta hai: algebra mein a kuch bhi ho sakta hai.
Fix: convention mein a > 0 liya jaata hai aur equation mein sign direction set karta hai. a ko positive rakhो.
Recall Quick self-test (answers chhupao, pehle forecast karo!)
Parabola ko define karne wali ek property kya hai? → focus aur directrix se equidistant.
Vertex focus aur directrix ke relative kahan hota hai? → midpoint pe.
y 2 = 4 a x : focus? directrix? → ( a , 0 ) , x = − a .
Latus rectum ki length? → 4 a .
x 2 = − 4 a y kis taraf khulta hai? → neeche (down).
Recall Feynman: ek 12-saal ke bachche ko samjhao
Socho ek point (the focus ) aur zameen pe ek seedhi fence (the directrix ) hai. Tum chalo is tarah ki tum hamesha point se utni hi door ho jitnी fence se . Jo curved path tum banate ho woh parabola hai — jaise satellite dish ya pheenki hui ball ka path. Point jitna fence ke paas hoga, curve utna tight hoga; jitna door hoga, utna wide failega. "Vertex" wahan hai jahan tum dono ke sabse paas ho — dono ke beech mein bilkul right.
Mnemonic Layout yaad rakhne ka tarika
"FoVeD on the axis" — Fo cus, Ve rtex, D irectrix sab axis pe line up hote hain, is order mein (vertex beech mein). Aur "4a is the width" — 4 a coefficient hi latus rectum length hai.
Parabola ki defining property Har point focus aur directrix se equidistant hota hai (e = 1 ).
Standard form opening right y 2 = 4 a x jahan a > 0 .
y 2 = 4 a x ka focus aur directrixFocus ( a , 0 ) , directrix x = − a .
y 2 = 4 a x ka latus rectum length4 a .
y 2 = 4 a x ke latus rectum ke endpoints( a , 2 a ) aur ( a , − 2 a ) .
y 2 = 12 x se a kaise nikaalein4 a = 12 ⇒ a = 3 (coefficient ko 4 se divide karo).
Agar equation mein x 2 ho toh axis of symmetry kaun si hai? y -axis (up/down khulta hai).
x 2 = − 4 a y ki directionNeeche (downward) khulta hai; focus ( 0 , − a ) , directrix y = a .
Vertex kahan hota hai Focus aur directrix ke beech midpoint pe, axis pe.
Focus ( 0 , 4 ) , directrix y = − 4 se equation x 2 = 16 y .
through F, parallel to directrix
Parabola: dist to F = dist to line
Axis: through F, perp to directrix
Vertex: midway F and directrix
Latus rectum: chord through F