"+1" KYUN?k=2,3,4,5 count karo: kya ye 5−2=3 hai? Nahi — ye 4 numbers hain. Endpoints ghataane se hamesha ek kam ho jaata hai, isliye usse wapas jodte hain: n−m+1.
KYUN? Addition commutative aur associative hai — ek finite sum ko aap freely reorder aur regroup kar sakte ho. c bahar nikalana sirf distributive law hai jo n baar apply hota hai. Aur ek constant c jo n baar add ho, wo nc hai (kyunki n terms hain, har ek c ke barabar hai).
∑k2 KAISE derive karte hain (cubes ko telescope karna — ek preview!):
Identity (k+1)3−k3=3k2+3k+1 use karo. Dono sides ko k=1 se n tak sum karo.
Left side telescope ho jaati hai (agli section dekho) (n+1)3−1 mein:
(n+1)3−1=3∑k2+3∑k+∑1=3∑k2+3⋅2n(n+1)+n.∑k2 ke liye solve karo aur simplify karo → 6n(n+1)(2n+1). Ye trick KYUN? Kyunki
cube-difference k2 ke baare mein jaanta hai, aur ek difference ko sum karna cleanly collapse ho jaata hai.
Telescoping sum KAISE pehchante hain: general term aksar ek aisi fraction hoti hai jiska denominator consecutive-ish pieces mein factor ho jaata hai, jaise k(k+1)1. Isse f(k)−f(k+1) mein split karne ke liye partial fractions use karo.
Ek lambi line mein khade dominoes imagine karo. Sigma bas kehta hai "line mein sab kuch count karo."
Ek telescoping sum ek magical line hai jahan har domino ek plus hai aur bilkul agli same
number ka minus hai — to wo ek doosre ko knock out kar dete hain! Saari cancelling ke baad, sirf pehla
aur aakhri domino khade rahte hain. To sau cheezein add karne ki jagah, tum bas
"pehla minus aakhri" karte ho. Yehi saara trick hai.