3.3.2 · Maths › Sequences & Series
GP ek aisi sequence hai jisme aap har step pe same number se multiply karte ho (add nahi, jaise AP mein hota hai).
KYA HAI: har term, pichli term ko ek fixed ==common ratio r == se multiply karke milti hai.
KYUN ZAROORI HAI: baar baar multiplication exponential hoti hai — yeh compound interest, population growth, radioactive decay, aur geometry (areas ka aadha hona) model karta hai. Nature "add" karne se kahin zyada "multiply" karta hai.
KAISE PEHCHANO: kisi bhi term ko uske pehle wali term se divide karo. Agar woh ratio constant hai, toh yeh GP hai.
Definition Geometric progression
Ek sequence a 1 , a 2 , a 3 , … ek GP hai agar consecutive terms ka ratio constant ho:
a n a n + 1 = r ( same for all n ) , r = 0 , a 1 = 0.
a (ya a 1 ) = first term
r = common ratio
Example: 3 , 6 , 12 , 24 , … mein a = 3 , r = 2 hai.
a = 0 aur r = 0 kyun? Agar a = 0 toh har term 0 hogi (ek degenerate, boring sequence). Agar r = 0 ho, toh pehli term ke baad sab 0 ho jaata hai aur kisi term se divide karna illegal ho jaata hai.
Intuition Pattern kyun hai
Har nayi term paane ke liye tum r se multiply karte ho. Toh pehli term se n -wi term tak pahunchne ke liye, tum total ( n − 1 ) baar r se multiply karte ho — kyunki term 1 aur term n ke beech ( n − 1 ) gaps hote hain.
Derivation (Feynman style, ek baar mein ek multiplication):
a 1 a 2 a 3 a 4 a n = a = a 1 ⋅ r = a r = a 2 ⋅ r = a r 2 = a 3 ⋅ r = a r 3 ⋮ = a r n − 1
Exponent n nahi balki n − 1 kyun hai? Pehli term mein zero multiplications hote hain (r 0 = 1 ). Terms nahi, arrows gino.
Intuition Clever trick kyun exist karta hai
a + a r + a r 2 + … ko term-by-term add karna slow hai. Trick yeh hai: poore sum ko r se multiply karo — isse har term ek slot aage shift ho jaati hai. Dono lines subtract karne par almost sab cancel ho jaata hai (ek telescoping cascade), sirf ends bach jaate hain.
Derivation:
Maano
S_n = a + ar + ar^2 + \cdots + ar^{\,n-1}. \tag{1}
Har term ko r se multiply karo:
rS_n = ar + ar^2 + ar^3 + \cdots + ar^{\,n}. \tag{2}
r se multiply kyun karte hain? Yeh wahi terms ek jagah shift hokar reproduce karta hai, taaki wo cancel ho jaayein.
(1) mein se (2) subtract karo:
S n − r S n = a − a r n
Beech ka hissa kyun gayab ho jaata hai? Har interior term a r k dono lines mein appear karta hai, isliye wo cancel ho jaati hai. Sirf (1) ki pehli term aur (2) ki aakhiri term bachti hai.
Factor karo:
S n ( 1 − r ) = a ( 1 − r n )
( 1 − r ) se divide karo, lekin sirf tab jab r = 1 ho:
S n = 1 − r a ( 1 − r n ) = r − 1 a ( r n − 1 )
Do forms kyun? Ye algebraically identical hain (upar aur neeche dono ko − 1 se multiply karo). Woh wala choose karo jo cheezein positive rakhe taaki sign ki galti na ho.
Worked example Example 1 — ek term dhundho
GP: 5 , 10 , 20 , … . 7th term nikalo.
Step: a = 5 , r = 10/5 = 2 identify karo. Kyun? Consecutive terms ka ratio r define karta hai.
Step: a 7 = a r 6 = 5 ⋅ 2 6 . Exponent 6 kyun? n − 1 = 7 − 1 .
= 5 ⋅ 64 = 320 .
Worked example Example 2 — sum jab
r > 1 ho
3 , 6 , 12 , … ke pehle 6 terms ka sum karo
a = 3 , r = 2 , n = 6 . S n = r − 1 a ( r n − 1 ) use karo. Yeh form kyun? r > 1 ise positive rakhta hai.
S 6 = 2 − 1 3 ( 2 6 − 1 ) = 3 ( 64 − 1 ) = 3 ⋅ 63 = 189 .
Worked example Example 3 — fractional ratio (
r < 1 )
8 , 4 , 2 , 1 ke pehle 4 terms ka sum karo.
a = 8 , r = 2 1 , n = 4 . S n = 1 − r a ( 1 − r n ) use karo. Yeh form kyun? r < 1 hai, isliye 1 − r > 0 hai.
S 4 = 1 − 2 1 8 ( 1 − ( 2 1 ) 4 ) = 2 1 8 ( 1 − 16 1 ) = 16 ⋅ 16 15 = 15 .
Check: 8 + 4 + 2 + 1 = 15 ✓ (Forecast-then-Verify).
Worked example Example 4 —
n dhundho (Forecast-then-Verify)
GP 2 , 6 , 18 , … mein kaun si term 486 ke barabar hai?
Forecast: terms ×3 se badhti hain, toh n lagbhag 6 ke aas paas guess karo.
Solve karo a r n − 1 = 486 ⇒ 2 ⋅ 3 n − 1 = 486 ⇒ 3 n − 1 = 243 = 3 5 ⇒ n − 1 = 5 ⇒ n = 6 . ✓
Common mistake nth term ke liye
r n − 1 ki jagah r n use karna
Kyun sahi lagta hai: "n -wi term, toh power n " natural lagta hai.
Fix: Pehli term ki power 0 hoti hai. a 1 pe test karo: a r 1 − 1 = a r 0 = a ✓. Agar r n use karte toh a r = a aata. Hamesha term 1 pe sanity-check karo.
r = 1 hone par sum formula apply karna
Kyun sahi lagta hai: formula "hamesha kaam karta hai". Fix: r = 1 hone par denominator 1 − r = 0 ho jaata hai → division by zero. Jab r = 1 ho toh saari terms a ke barabar hoti hain, isliye S n = na seedha likhte hain.
Common mistake Do sum forms mix karne se galat sign
Kyun sahi lagta hai: tumne ek form yaad ki aur aisa case mein daali jisme woh suit nahi karti.
Fix: r > 1 ke liye r − 1 a ( r n − 1 ) use karo (dono parts positive); r < 1 ke liye 1 − r a ( 1 − r n ) use karo. Ya sirf signs carefully track karo — dono same equation hain.
r subtract karke compute karna (AP ki aadat)
Kyun sahi lagta hai: AP mein d nikalne ke liye subtract karte hain. Fix: GP mein division use hoti hai: r = a n + 1 / a n , kabhi a n + 1 − a n nahi.
Recall Feynman: ek 12-saal ke bacche ko samjhao
Ek magic photocopier imagine karo jo hamesha double size ki copies banata hai (ya aadha, ya triple). Size 3 ka ek sticker se shuru karo. Andar daalo: 6, phir 12, phir 24 — har baar woh same number se multiply karta hai. Yahi GP hai! Kuch copies ke baad size jaanne ke liye, tum sirf us magic number ko utni baar khud se multiply karte ho jitni baar copy bani — stickers ki sankhya se ek kam, kyunki pehle sticker ki zero baar copy hui thi. Aur agar saare stickers ka total area chahiye, toh ek shortcut hai: unhe ek-ek karke add karne ki jagah, poori pile ko copy karo, ek jagah shift karke rakho, aur subtract karo — almost sab cancel ho jaata hai aur sirf pehla aur aakhiri hissa bachta hai. Neat!
"First term times ratio, ONE less power" → a r n − 1 .
Sum ke liye: "upar aur neeche dono mein ( 1 − r ) ish hai; n sirf upar r n ke roop mein rehta hai." → 1 − r a ( 1 − r n ) .
Arithmetic Progression (AP) — GP wahan multiply karta hai jahan AP add karta hai; S n reverse trick se wahan derive hota hai, yahan shifting se.
Sum of infinite GP — jab ∣ r ∣ < 1 ho, r n → 0 isliye S ∞ = 1 − r a .
Geometric Mean — 3-term GP ki middle term: b = a c .
Exponential functions — GP, a r x ka discrete version hai.
Compound interest — amounts ek GP form karte hain jisme r = 1 + 100 i hota hai.
Logarithms — r n − 1 = k se n solve karne ke liye use hoti hain.
GP kya define karta hai? Consecutive terms ka ratio constant hota hai: a n + 1 / a n = r .
First term a , ratio r wali GP ki nth term kya hogi? a n = a r n − 1 .
Exponent n nahi balki n − 1 kyun hai? Pehli term r se zero baar multiply hoti hai (r 0 = 1 ); term n tak sirf ( n − 1 ) gaps hote hain.
GP ke pehle n terms ka sum (r = 1 ) kya hoga? S n = 1 − r a ( 1 − r n ) = r − 1 a ( r n − 1 ) .
GP sum kaunsi trick se derive hota hai? S n ko r se multiply karo taaki terms shift ho jaayein, phir subtract karo — interior terms cancel ho jaati hain (telescoping).
r = 1 hone par S n kya hoga?S n = na (saari terms a ke barabar hain; formula fail hota hai kyunki 1 − r = 0 hai).
Common ratio r kaise nikaalte hain? Ek term ko pichli term se divide karo, subtract nahi.
Formula se 8 + 4 + 2 + 1 ka sum kya hoga? a = 8 , r = 2 1 , n = 4 : 1/2 8 ( 1 − 1/16 ) = 15 .
Infinite GP sum kab exist karta hai aur kiske barabar hota hai? Jab ∣ r ∣ < 1 ho; tab S ∞ = 1 − r a .
Constant ratio a_n+1 / a_n = r
S_n = a + ar + ... + ar^n-1
S_n = a 1-r^n / 1-r, r != 1
Compound interest, growth, decay