3.2.9 · Maths › Exponentials & Logarithms
Ek logarithm poochta hai: "Base ko kis power tak uthana padega taaki mujhe yeh number mile?"
Us sawaal ka jawab nahi badalta — chahe tum use alag base mein likhlo.
Isliye log 2 8 aur l o g 10 2 l o g 10 8 same number hain (= 3 ) — hum bas usi "power" ko alag ruler se maap rahe hain.
KYUN zaroori hai yeh: Tumhare calculator mein sirf log 10 aur ln ke buttons hote hain. log 2 8 compute karne ke liye, tumhe ise base-10 ya base-e mein translate karna padega. Change of base formula wohi translator hai.
HAR piece kya hai:
a = purana base (jise tum hatana chahte ho).
b = naya base (jo tumhara calculator samajhta hai, jaise 10 ya e ).
x = argument (andar wala number).
Definition Woh ek fact jahan se hum shuru karte hain
log a x = y ka bilkul sahi matlab hai a y = x .
Yeh logarithm ki definition hai — dono statements ek hi relationship ko alag tarike se likhne ke do tarike hain.
HUM ise step by step kaise derive karte hain:
Step 1 — Jis cheez ko chahte hain usse naam do.
Maano
y = log a x .
Yeh step kyun? Ek mystery ko manipulate nahi kar sakte; use naam y dene se hum uspe algebra kar sakte hain.
Step 2 — Exponential form mein likhte hain.
Upar wali definition se,
a y = x .
Yeh step kyun? Exponentials par kisi bhi base ke logs se attack karna aasaan hota hai, kyunki logs powers ko products mein badal dete hain.
Step 3 — DONO sides par log b lete hain.
log b ( a y ) = log b x .
Yeh step kyun? Dono sides par same function apply karne se equality bani rehti hai. Hum base b isliye choose karte hain kyunki yahi woh base hai jo hum use kar sakte hain (calculator base).
Step 4 — Power law log b ( a y ) = y log b a use karte hain.
y log b a = log b x .
Yeh step kyun? Log lene ka yahi poora point hai: yeh exponent y ko neeche kheench ke ek coefficient bana deta hai, taaki hum use isolate kar sakein.
Step 5 — y ke liye solve karo (log b a se divide karo, jo = 0 hai kyunki a = 1 ):
y = l o g b a l o g b x .
Step 6 — Yaad karo y kya tha.
Kyunki y = log a x ,
log a x = log b a log b x ■
Worked example Example 1 — Basic calculator use
Base 10 use karke log 2 8 compute karo.
log 2 8 = l o g 10 2 l o g 10 8 = 0.3010 0.9031 = 3.
Yeh step kyun? Hum awkward base 2 ko base 10 se swap karte hain, jo calculator ke paas hai. Check: 2 3 = 8 . ✓
Worked example Example 2 — Natural log use karna
ln se log 5 40 compute karo.
log 5 40 = l n 5 l n 40 = 1.6094 3.6889 ≈ 2.292.
Yeh step kyun? "Naye ruler" ka base tumhari free choice hai — 10 ya e dono kaam karte hain aur same answer dete hain. Pehle estimate karo phir verify: 5 2 = 25 , 5 2.5 ≈ 55 , toh 2.29 sensibly beech mein baithta hai. ✓
Worked example Example 3 — Ek sundar consequence (reciprocal identity)
Show karo log a b = log b a 1 .
Formula mein x = b rakho, new base b ke saath:
log a b = l o g b a l o g b b = l o g b a 1 .
Yeh step kyun? log b b = 1 kyunki b 1 = b . Toh base aur argument swap karna bas fraction ko flip kar deta hai — ek handy shortcut.
Worked example Example 4 — Ek expression simplify karna
log 4 x ⋅ log x 16 simplify karo (valid x ke liye).
Dono ko base 2 mein convert karo:
l o g 2 4 l o g 2 x ⋅ l o g 2 x l o g 2 16 = 2 l o g 2 x ⋅ l o g 2 x 4 = 2 4 = 2.
Yeh step kyun? Ek common naya base choose karne se log 2 x terms cancel ho jaate hain — change of base ek messy product ko simple arithmetic mein badal deta hai.
log a x = log x log a " — log ko split karna
Kyun sahi lagta hai: Formula mein division dikhta hai, toh students sochte hain ki single log log a x khud hi log a / log x mein split ho jaata hai. Yeh symmetrical aur clean lagta hai.
Kyun galat hai: log a akela meaningless hai — ek log ko base aur argument dono chahiye. Formula hai l o g b a l o g b x : naye base b mein do complete logs, aur note karo argument x upar hai, base a neeche .
Common mistake Base ko upar rakhna
Kyun sahi lagta hai: log a x padha jaata hai "a phir x", toh log likhte hain l o g x l o g a wohi order rakhte hue.
Fix: Argument hamesha numerator mein jaata hai. Sanity-check log 2 8 = 3 se karo: yeh l o g 2 l o g 8 (bada/chota > 1 ) ke barabar hona chahiye, na ki l o g 8 l o g 2 < 1 .
Common mistake "Yeh sirf base 10 ya
e ke liye kaam karta hai"
Kyun sahi lagta hai: Hum hamesha base 10/e use karte hain calculators ki wajah se.
Fix: Proof ne general b use kiya tha — koi bhi valid base kaam karta hai. Base 10/e sirf ek convenient choice hai, requirement nahi.
Recall Feynman: ek 12-saal ke bachche ko explain karo
Ek log ek sawaal hai: "Kitni baar is base ko multiply karna padega taaki yeh number mile?" log 2 8 poochta hai "kitne 2s multiply karke 8 banta hai?" — jawab 3 hai.
Ab imagine karo tumhare paas sirf ek base-10 ruler hai powers measure karne ke liye. Phir bhi tum "2-wala sawaal" maap sakte ho — bas maap lo 8 kitna bada hai base 10 mein, maap lo 2 kitna bada hai base 10 mein, aur divide karo. Scaling cancel ho jaati hai aur tumhe sahi jawab milta hai, 3. Same height, alag ruler.
Mnemonic Layout yaad karo
"Argument upar, old base neeche, new base dono par."
Ya: "Log of Answer over Log of bAse" → A wale words (Answer, bAse) tumhe numerator/denominator batate hain; answer/argument pehle aata hai (upar).
Change of base formula state karo.
Proof kis ek definition se shuru hota hai?
log b a se safely divide kyun kar sakte hain?
log a b ⋅ log b a kya hai?
Definition log a x = y ka exponential form mein kya matlab hai? a y = x
Change of base formula state karo. log a x = log b a log b x
Change of base mein numerator mein kaunsi quantity jaati hai? Argument x ka log (new base mein).
Denominator mein kaunsi quantity jaati hai? Old base a ka log (new base mein).
log b a se divide karna allowed kyun hai?Kyunki a = 1 , isliye log b a = 0 .
Proof ka pehla step? y = log a x maano, phir a y = x likh do.
Proof mein exponent neeche laane wala kaunsa log law hai? Power law log b ( a y ) = y log b a .
Reciprocal identity log a b = 1/ log b a prove karo. x = b rakho: log a b = l o g b a l o g b b = l o g b a 1 .
Base 10 se log 2 8 compute karo. l o g 2 l o g 8 = 3 .
Kya new base sirf 10 ya e hi hona chahiye? Nahi — koi bhi valid base b > 0 , b = 1 kaam karta hai; 10/e sirf convenient hain.
log a b ⋅ log b a simplify karo.= 1 (yeh dono reciprocals hain).
Definition of a logarithm — woh ek fact jis par poora proof tika hai.
Laws of logarithms — power law derivation ka engine hai.
Exponential functions — Step 2 mein log→exponential form mein convert hota hai.
Natural logarithm ln — common "new base" b = e .
Solving exponential equations — change of base unknown exponents isolate karne deta hai.
log_a x = y means a^y = x
Step 3: log_b of a^y = log_b x
Step 4: y log_b a = log_b x
Step 5: y = log_b x / log_b a
Change of base: log_a x = log_b x / log_b a
Compute log_2 8 via base 10
Calculator only has log10 and ln