3.1.18 · Maths › Advanced Trigonometry
Sine, cosine aur tangent periodic aur many-to-one hote hain. Toh sin θ = 2 1 jaisi equation ke infinitely many answers hote hain. "General solution" ek single formula hai jo ek integer n ki madad se SAARE answers pack kar leta hai. Range mein solutions dhundhne ke liye, hum bas woh n ki values choose karte hain jo us range ke andar aati hain.
YEH KYUN MATTER KARTA HAI: general solution ke bina tum angles guess karte rehte. Yeh formula ek machine hai: crank ghhumaao (n = 0 , ± 1 , ± 2 , … ) aur har solution bahar aa jaata hai.
YEH solutions kaise create karta hai: agar θ 0 equation solve karta hai, toh periods ke kisi bhi whole number ko add karne se ek aur solution milta hai, kyunki function usi value par wapas aa jaata hai.
Lekin sine aur cosine dono ek value ko do jagah hit karte hain har cycle mein (peaks ke alawa). Toh humein unke liye do families of angles chahiye, tan ke liye ek family.
± mein kyun collapse hoti hain
cos ek even function hai: cos ( − θ ) = cos θ . Toh agar α kaam karta hai, toh − α bhi kaam karega. Cosine y -axis ke baare mein symmetric hai.
α = cos − 1 c ko principal angle maano. Ek turn mein do solutions hain θ = α aur θ = − α (yaani 2 π − α ). Period 2 π ke multiples add karo:
± kyun? even symmetry ki wajah se. 2 nπ kyun? kyunki yahi period hai.
( − 1 ) n kyun aata hai
sin odd hai aur θ = 2 π ke baare mein symmetric hai. Ek turn mein do solutions hain α aur π − α . Dekho:
n even → hum α type chahte hain
n odd → hum π − α type chahte hain
( − 1 ) n ki trick odd n par α ka sign flip karti hai, aur nπ base ko shift karta hai. Yeh do families ke beech alternate karne ka ek compact tarika hai.
α = sin − 1 s maano. Toh:
Check karo ki kaam karta hai: n = 0 ⇒ α . n = 1 ⇒ π − α . n = 2 ⇒ 2 π + α . Exactly sine solutions. ✓
Intuition SIRF EK family kyun (koi
± nahi)
tan ka period π hai, aur har period ke andar yeh har value ko exactly once hit karta hai. Toh ek base angle plus π ke multiples sab kuch cover kar lete hain.
α = tan − 1 t maano.
sin / cos / tan ( angle ) = number ke roop mein rearrange karo.
Inverse function se principal value α dhundho.
General solution formula likho.
n = … , − 1 , 0 , 1 , 2 , … substitute karo aur sirf woh θ rakho jo range ke andar ho.
Agar equation mein multiple angle hai (jaise cos 2 θ ), pehle andar ki range widen karo, phir divide karo.
Worked example Example 2 — sine using
( − 1 ) n
sin θ = 2 3 solve karo, 0 ≤ θ ≤ 2 π .
α = sin − 1 2 3 = 3 π .
General: θ = nπ + ( − 1 ) n 3 π .
n = 0 : θ = 3 π ✓ Kyun rakha? range mein hai.
n = 1 : θ = π − 3 π = 3 2 π ✓ Minus kyun? ( − 1 ) 1 = − 1 .
n = 2 : θ = 2 π + 3 π — range se bahar, ruko.
Answers: 3 π , 3 2 π .
Worked example Example 3 — tangent
tan θ = − 1 solve karo, 0 ∘ ≤ θ < 36 0 ∘ .
α = tan − 1 ( − 1 ) = − 4 5 ∘ . Negative kyun? tan odd hai; calculator − 4 5 ∘ deta hai.
General: θ = 18 0 ∘ n − 4 5 ∘ .
n = 1 : 13 5 ∘ ✓. n = 2 : 31 5 ∘ ✓. n = 0 : − 4 5 ∘ bahar. n = 3 : 49 5 ∘ bahar.
Answers: 13 5 ∘ , 31 5 ∘ .
Recall Answer padhne se pehle predict karo:
sin θ = 0.4 ke 0 ≤ θ < 2 π mein kitne solutions hain? 0 ≤ θ < 4 π mein?
2 π turn mein 2 solutions → pehli range mein 2 , doosri mein 4 . General formula confirm karta hai: n mein 2 ka har increment ek poora period-pair complete karta hai.
Common mistake Sirf calculator answer dena
Galat idea: "cos θ = 2 1 ⇒ θ = 6 0 ∘ , khatam."
Kyun sahi lagta hai: calculator exactly ek value deta hai, toh complete lagta hai.
Fix: calculator sirf principal value deta hai. Poori family lene ke liye general solution use karo, phir range se filter karo. Warna 30 0 ∘ miss ho jaata.
Common mistake Multiple angles ke liye range widen karna bhool jaana
Galat idea: cos 2 θ = 2 3 ko seedha 2 θ par 0 ≤ θ < 2 π use karke solve karo.
Kyun sahi lagta hai: stated range 2 π hai, toh tum use karte ho.
Fix: substitution ϕ = 2 θ interval ko double karke 0 ≤ ϕ < 4 π bana deta hai. Wahan solve karo, phir divide karo. Warna sirf aadhe solutions milte hain.
( − 1 ) n ke saath sign confusion
Galat idea: sine par ± apply karna jaise cosine ke liye.
Kyun sahi lagta hai: dono symmetric lagte hain.
Fix: sine ke do solutions α aur π − α hain (supplementary), ± α nahi . Sine ke liye nπ + ( − 1 ) n α use karo, cosine ke liye 2 nπ ± α .
Recall Ek 12-saal ke bacche ko explain karo
Socho ek Ferris wheel hai jo forever ghhumti rehti hai. Agar main poochhun "tumhari seat exactly 3 metre upar kab hogi?", toh sirf ek time nahi hoga — yeh har loop mein hota hai, har loop mein do baar (ek baar upar jaate waqt, ek baar neeche aate waqt). General solution kuch aisa kehne jaisa hai: "in do clock positions par, aur phir har full turn ke baad dobara." Chota number n bas yeh batata hai ki tum kaunse loop par ho. Agar tumhe sirf lunch se pehle ke answers chahiye, toh sirf woh loops rakho jo lunch se pehle khatam hote hain.
Mnemonic Teeno formulas yaad karo
"Cos Plus-minus, Sin Signs-alternate, Tan Alone."
C os → 2 nπ ± α (Cos = ±, dono "curvy pair" se shuru hote hain).
S in → nπ + ( − 1 ) n α (Sine → Signs flip karte hain).
T an → nπ + α (Tan akele Travel karta hai, half period π ).
General solution of cos θ = cos α ? θ = 2 nπ ± α , n ∈ Z
General solution of sin θ = sin α ? θ = nπ + ( − 1 ) n α , n ∈ Z
General solution of tan θ = tan α ? θ = nπ + α , n ∈ Z
Cosine ke general solution mein ± kyun hota hai? Kyunki cos even hai, cos ( − α ) = cos α , har turn mein do symmetric roots deta hai.
Tangent ko sirf ek family kyun chahiye? Iska period π hai aur yeh har period mein har value exactly once hit karta hai.
cos 2 θ = c ko 0 ≤ θ < 2 π par solve karte waqt pehle kya change karna chahiye?Range ko 0 ≤ 2 θ < 4 π tak widen karo solve karne se pehle, phir results ko 2 se divide karo.
sin θ = 0.4 ke 0 ≤ θ < 2 π mein kitne solutions hain?Do.
Integer n physically kya represent karta hai? Kaun sa poora period (loop) jisme solution hai.
Kisi bhi trig equation mein pehla step kya hai? sin / cos / tan of the angle ko ek number ke barabar isolate karne ke liye rearrange karo.
Trig functions periodic and many-to-one
Infinitely many solutions
General solution formula with n
cos: theta = 2n pi ± alpha
sin: theta = n pi + -1^n alpha
Tan hits value once per period
tan: theta = n pi + alpha