Product ko collapse kiye bina likho:
(a+b)n=n brackets(a+b)(a+b)⋯(a+b)
Expand karne ke liye, har bracket se ek letter choose karo aur unhe multiply karo. Ek generic term n letters ka product hota hai.
Sawaal: in products mein se kitne an−rbr ke barabar hain?
Yeh tab hota hai jab hum exactly r brackets se b choose karein aur baaki n−r se a. Yeh choose karne ke ki kaun ser brackets b denge, tarike hain (rn).
Sab possible r (0 se n tak) par sum karne se theorem milti hai. Koi formula yaad nahi kiya — yeh counting se hi nikal aaya. ∎
Recall Reveal karne se pehle predict karo (Forecast-then-Verify)
(a+b)12 mein kitne terms hain? → 13.
(x−x1)10 mein, kaun sa r constant term deta hai? Set karo 10−2r=0⇒r=5.
(1+2x)5 mein x3 ka coefficient? (35)23=10⋅8=80.
(a+b)n ki binomial expansion kya hai?
∑r=0n(rn)an−rbr
(rn) coefficient ki tarah kyun aata hai?
Yeh un brackets ki sankhya count karta hai jisme se hum b choose karte hain (baaki a dete hain), jo sab same an−rbr term produce karte hain.
(a+b)n mein kitne terms hote hain?
n+1.
(a+b)n ka general term likho.
Tr+1=(rn)an−rbr, r=0,1,…,n.
Tr+1 kyun hai, Tr kyun nahi?
Kyunki counter r0 se shuru hota hai; T1 hai r=0, toh subscript ek aage hota hai.
xk wala term kaise dhundho?
Tr+1 ko x ki single power ke roop mein likho, uska exponent =k set karo, r solve karo.
x se independent term kaise dhundho?
Tr+1 mein x ka exponent 0 ke barabar set karo aur r solve karo.
(1+x)n mein xr ka coefficient?
(rn).
(1+x)n ka middle term jab n even ho?
Single term Tn/2+1=(n/2n)xn/2.
(2x−3)n mein, kya coefficient sirf (rn) hai?
Nahi — numeric factors include karo: (rn)(2)n−r(−3)r.
Recall Feynman: ek 12-saal ke bacche ko samjhao
Socho n light switches hain, har ek ya toh "a-on" ya "b-on" hai. Sab switches ko har possible tarike se flip karke result likhne se expansion milti hai. "Exactly r switches b par" paane ke liye, count karo ki woh r switches choose karne ke kitne tarike hain — woh hai (rn). Sab tarike add karo aur tumne (a+b)n bana liya bina kuch yaad kiye.