Zaruri rule — upper boundary kyun use karein?
Less-than ogive ke liye, CF ko upper class boundary ke against plot karo, midpoint ke against nahi. KYO? Kyunki CFi class i ki upper boundary se neeche ki sabhi cheezein count karta hai — isliye point (upper boundary,CFi) yeh saaf kehta hai ki "itne values is x se neeche hain."
Curve pehli class ki lower boundary par CF =0 se shuru hoti hai aur N tak uthti hai.
N/2 calculate karo (grouped/continuous data ke liye N/2 use karo, (N+1)/2nahi — neeche mistake dekho).
Y-axis par N/2 mark karo. Curve tak ek horizontal line kheencho.
X-axis par ek vertical line chhaado. Value padho → wahi median hai.
Twin-ogive method: Less-than aur more-than dono ogives ko same axes par draw karo. Jahan woh intersect karein, wahan x-axis par ek perpendicular chhaao — woh x-value median hai.
Graph median class ke andar linear interpolation hai. Chaliye derive karte hain.
Median class woh class hai jahan CF pehli baar N/2 tak pahunchti ya usse zyada hoti hai. Maano us class ke andar frequency uniformly faili hui hai. Maano:
L = median class ki lower boundary
CFb = median class se pehle wali class ki cumulative frequency
f = median class ki frequency
h = class width
Hume CF =CFb (at x=L) se N/2 tak jaana hai. Extra count ki zarurat hai (2N−CFb). Kyunki f observations width h mein evenly faile hain, x ka har unit count mein f/h badhata hai. Toh horizontal distance yeh hai:
x=30 par ogive ki y-value ka literally kya matlab hai?
Grouped data ke liye N/2 kyun use karte hain aur (N+1)/2 kyun nahi?
Twin-ogive method mein crossing point kya khaas hai?
"Count needed = N/2−CFb" se median formula derive karo.
Answers: (1) 30 se kam observations ki sankhya. (2) Grouped data → smooth curve, halfway height. (3) less-than = more-than = N/2 → median. (4) Δx=(N/2−CFb)/(f/h), L mein jodao.
Recall Feynman: ek 12-saal ke bacche ko explain karo
Socho ek queue mein bacche chhaote se lambe sort hain. "Cumulative frequency" sirf yeh count karna hai ki "meri kheechi hui line se kitne bacche chhhote hain." Agar main lines kheenchta rahun aur count karta rahun, aur plot karun, toh mujhe ek curve milta hai jo hamesha upar jaata hai. Ab mujhe beech wala baccha chahiye. Aadhe bacche 20 hain (40 mein se). Toh main height axis par 20 tak jaata hun, right tak chalta hun jab tak curve na mile, phir seedha neeche dekhta hun — woh height beech wale bacche ki height hai. Aasaan!