2.6.9Matrices & Determinants — Introduction

Properties of determinants

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WHAT is a determinant (so we know what we're proving)

WHY this definition? It's the only formula that is (a) linear in each row and (b) zero when two rows are equal — and those two facts force every property below.


HOW each property follows (derive, don't memorize)

Write AA with rows R1,R2,,RnR_1,R_2,\dots,R_n. Think of det\det as a function D(R1,,Rn)D(R_1,\dots,R_n).

P1. Transpose leaves it unchanged

det(A)=det(A)\det(A^\top)=\det(A) Why: In the permutation sum, aiσ(i)a_{i\sigma(i)} vs aσ(i)ia_{\sigma(i)\,i} — reindexing by σ1\sigma^{-1} gives the same set of terms with the same sign (since sgn(σ)=sgn(σ1)\operatorname{sgn}(\sigma)=\operatorname{sgn}(\sigma^{-1})). Consequence: every row property is also a column property.

P2. Swapping two rows flips the sign

D(,Ri,,Rj,)=D(,Rj,,Ri,)D(\dots,R_i,\dots,R_j,\dots)=-D(\dots,R_j,\dots,R_i,\dots) Why: A swap composes each permutation with a transposition, flipping sgn\operatorname{sgn} of every term.

P3. Two equal rows ⟹ determinant =0=0

Why: Swap the two equal rows: value must equal -(itself). So det=detdet=0\det=-\det\Rightarrow\det=0.

P4. Multiplying one row by kk multiplies the determinant by kk

D(,kRi,)=kD(,Ri,)D(\dots,kR_i,\dots)=k\,D(\dots,R_i,\dots) Why: Every term contains exactly one factor from row ii, so kk factors out of all of them. Corollary: det(kA)=kndetA\det(kA)=k^n\det A (each of nn rows contributes a kk).

P5. Additivity in a single row (linearity)

D(,Ri+Ri,)=D(,Ri,)+D(,Ri,)D(\dots,R_i+R_i',\dots)=D(\dots,R_i,\dots)+D(\dots,R_i',\dots) Why: Each term is linear in the one entry it takes from row ii.

P6. Adding a multiple of one row to another leaves it unchanged

D(,Ri+kRj,,Rj,)=D(,Ri,,Rj,)D(\dots,R_i+kR_j,\dots,R_j,\dots)=D(\dots,R_i,\dots,R_j,\dots) Why: By P5 it splits into the original plus kD(,Rj,,Rj,)k\cdot D(\dots,R_j,\dots,R_j,\dots); the second has two equal rows, so it's 00 (P3). This is the workhorse for hand computation.

P7. A row of zeros ⟹ determinant =0=0

Why: Take k=0k=0 in P4.

P8. Triangular matrix ⟹ product of diagonal

det=a11a22ann\det=a_{11}a_{22}\cdots a_{nn} Why: In a triangular matrix, the only permutation that picks a nonzero entry from every row is the identity (any off-diagonal choice forces a zero factor).

P9. Product rule

det(AB)=det(A)det(B)\det(AB)=\det(A)\,\det(B) Why (sketch): Both sides are multilinear-alternating in the rows of AA and normalized on II; the axioms pin down a unique such function, forcing equality. Consequence: det(A1)=1detA\det(A^{-1})=\dfrac{1}{\det A}.

Figure — Properties of determinants

Worked Examples



Recall Feynman: explain it to a 12-year-old

Imagine a stretchy sheet of graph paper. A matrix bends and stretches it. The determinant is the number that says "how many times bigger did one little square get?" If you flip the sheet over (mirror image), the number goes negative — that's the swap-rows sign flip. If two directions point the same way, the square gets squashed flat to zero area — that's "two equal rows give 0." Adding one row's worth of another row is like sliding the top of a stack of cards sideways: the shape leans but the area stays the same — so the determinant doesn't change.


Flashcards

What geometric quantity does a determinant measure?
The (signed) scaling factor of area/volume under the linear map; sign encodes orientation.
Why does swapping two rows negate the determinant?
A swap is one transposition, flipping the sign of every permutation term. (P2)
If two rows are equal, why is det =0=0?
Swapping the equal rows gives det=det\det=-\det, so det=0\det=0. (P3)
Effect of multiplying ONE row by kk?
Determinant is multiplied by kk. (P4)
Effect of multiplying the WHOLE n×nn\times n matrix by kk?
det(kA)=kndetA\det(kA)=k^n\det A.
Which row operation leaves the determinant unchanged?
Adding a multiple of one row to another: RiRi+kRjR_i\to R_i+kR_j. (P6)
Why does det(A)=detA\det(A^\top)=\det A?
Reindexing the permutation sum by σ1\sigma^{-1} gives identical signed terms. (P1)
Determinant of a triangular matrix?
Product of the diagonal entries. (P8)
State the product rule and its corollary for inverses.
det(AB)=detAdetB\det(AB)=\det A\det B; hence det(A1)=1/detA\det(A^{-1})=1/\det A.
Is det(A+B)=detA+detB\det(A+B)=\det A+\det B true?
No — linearity holds only per-row with other rows fixed.
Fastest way to compute a numeric determinant by hand?
Use P6 to make a triangular matrix, then multiply the diagonal (P8).

Connections

Concept Map

forces

forces

reindex by inverse

so rows equal columns

self equals negative self

factor k out

split entries

combined with

second term vanishes

set k=0

only identity survives

Determinant as signed permutation sum

Linear in each row

Zero when two rows equal

P1 Transpose unchanged

P2 Swap rows flips sign

P3 Equal rows give 0

P4 Scale row scales det

P5 Row additivity

P6 Add k times row unchanged

P7 Zero row gives 0

P8 Triangular is diagonal product

Hinglish (regional understanding)

Intuition Hinglish mein samjho

Dekho, determinant ka matlab sirf ek number nikaalna nahi hai — yeh number batata hai ki matrix apne saath jo transformation karti hai usme ek chhota sa square (area 1) kitne guna bada ya chhota ho jaata hai. Agar orientation ulti ho jaaye (mirror image), toh determinant negative ho jaata hai. Isliye do rows swap karo toh sign flip hota hai (P2), aur agar do rows bilkul same hain toh area collapse hoke line ban jaati hai, matlab determinant zero (P3). Yeh geometry samajh loge toh saari properties automatically yaad ho jaayengi.

Sabse kaam ki property exam ke liye hai P6: kisi row me doosri row ka multiple add karo, determinant bilkul nahi badalta. Iska use karke hum column me zeros bana dete hain aur matrix ko triangular bana dete hain — phir P8 se seedha diagonal multiply kar do, bas jawaab mil gaya. Bade-bade expansion se bachne ka yahi 80/20 trick hai.

Do galtiyaan bahut common hain. Pehli: log sochte hain det(A+B)=detA+detB\det(A+B)=\det A+\det B — galat! Linearity sirf ek row ke liye hoti hai, poori matrix ke liye nahi. Doosri: det(kA)=kdetA\det(kA)=k\det A likh dete hain, jabki har row scale hoti hai isliye answer kndetAk^n\det A hota hai. In dono ko yaad rakho.

Mantra simple hai: "Swap Flips, Copy Kills, Scale Scales, Slide Saves." Row swap sign flip karta hai, equal (copy) row kill kar deta hai (0), row ko kk se scale karo toh det bhi ×kk, aur ek row ka multiple slide karke add karo toh det save reh jaata hai. Bas itna, aur tum properties ke master ho.

Go deeper — visual, from zero

Test yourself — Matrices & Determinants — Introduction

Connections