2.1.3 · Maths › Algebra — Introduction & Intermediate
Algebraic expressions mathematical phrases hain jo variables, constants, aur operations ko combine karti hain. Inhe add aur subtract karna equations ko manipulate karne aur problems solve karne ki foundation hai—lekin arithmetic ke unlike, hum sirf like terms ko hi combine kar sakte hain.
Intuition Hum Sab Kuch Add Kyun Nahi Kar Sakte?
Socho tumhare paas 3 seb aur 5 santre hain. Tum nahi keh sakte ki tumhare paas "8 seb" ya "8 santre" hain—tumhare paas 3 seb AUR 5 santre hain. Algebra mein, 3 x aur 5 y seb aur santre ki tarah hain. Hum sirf unhi terms ko combine kar sakte hain jinka same variable part ho.
Rule yeh hai: Sirf like terms (same variables with same powers) ko combine kiya ja sakta hai. Baaki sab alag rehta hai.
Chaliye derive karte hain ki hum like terms ko distributive property use karke kyun add kar sakte hain.
Starting point: Distributive property kehti hai a ( b + c ) = ab + a c
Forward direction (kyun hum combine KAR sakte hain):
3 x + 5 x
Yeh aslaan mein kya hai? Har term matlab hai "x ki kitni copies":
3 x matlab x + x + x
5 x matlab x + x + x + x
Toh: 3 x + 5 x = 3 times x + x + x + 5 times x + x + x + x = 8 times x + x + x + x + x + x = 8 x
Distributive property use karke (reverse):
3 x + 5 x = ( 3 + 5 ) x = 8 x
Yeh step kyun? Hum common x ko "factor out" kar rahe hain, phir coefficients add kar rahe hain.
Backward direction (kyun hum unlike terms combine NAHI kar sakte):
3 x + 5 y
Factor karne ki koshish karo: Humein ek common factor chahiye hoga, lekin x aur y different variables hain.
3 x + 5 y = ( 3 ⋅ x ) + ( 5 ⋅ y )
Yahan koi common factor nahi hai jo bahar nikala ja sake, isliye yeh 3 x + 5 y hi rehta hai. Hum isse aur simplify nahi kar sakte.
Worked example Example 1: Simple Addition
Problem: Add ( 7 x + 3 y ) + ( 2 x + 5 y )
Solution:
Step 1:** Parentheses hataao (addition se signs nahi badalte)
7 x + 3 y + 2 x + 5 y
Yeh step kyun? Parentheses ke aage + hona matlab hai "andar ki sab cheez as-is add karo."
Step 2: Like terms identify karo
x terms: 7 x aur 2 x
y terms: 3 y aur 5 y
Step 3: Like terms combine karo
= ( 7 x + 2 x ) + ( 3 y + 5 y )
Yeh step kyun? Hum commutative aur associative properties use karke regroup kar rahe hain: a + b + c + d = ( a + c ) + ( b + d )
= 9 x + 8 y
Yeh step kyun? 7 + 2 = 9 (x terms ke liye) aur 3 + 5 = 8 (y terms ke liye). Variables bas "saath chale aate hain."
Answer: 9 x + 8 y
Worked example Example 2: Subtraction with Sign Changes
Problem: Subtract ( 5 a 2 + 3 a − 7 ) − ( 2 a 2 − 4 a + 3 )
Solution:
Step 1: Negative sign distribute karo
= 5 a 2 + 3 a − 7 − 2 a 2 + 4 a − 3
Yeh step kyun? Doosre parentheses ke aage minus sign matlab hai "andar ki har cheez ko − 1 se multiply karo":
− ( 2 a 2 − 4 a + 3 ) = − 1 ( 2 a 2 ) + ( − 1 ) ( − 4 a ) + ( − 1 ) ( 3 ) = − 2 a 2 + 4 a − 3
Critical baat: Doosre expression ki har term ka sign flip hota hai!
Step 2: Like terms identify karo
a 2 terms: 5 a 2 aur − 2 a 2
a terms: 3 a aur 4 a
Constants: − 7 aur − 3
Step 3: Like terms combine karo
= ( 5 a 2 − 2 a 2 ) + ( 3 a + 4 a ) + ( − 7 − 3 )
= 3 a 2 + 7 a − 10
Yeh step kyun?
5 − 2 = 3 a 2 terms ke liye
3 + 4 = 7 a terms ke liye
− 7 − 3 = − 10 constants ke liye
Answer: 3 a 2 + 7 a − 10
Worked example Example 3: Multiple Variables and Powers
Problem: Simplify ( 6 x 2 y − 3 x y 2 + 2 x ) + ( 4 x y 2 − 2 x 2 y + 5 y ) − ( x 2 y − x y 2 + 3 x )
Solution:
Step 1: Saare parentheses hataao (signs dekho!)
= 6 x 2 y − 3 x y 2 + 2 x + 4 x y 2 − 2 x 2 y + 5 y − x 2 y + x y 2 − 3 x
Yeh step kyun? Pehle do sets ke aage + hai, toh signs same rehte hain. Last set ke aage − hai, toh saare signs flip ho jaate hain.
Step 2: Saari like terms identify karo
x 2 y terms: 6 x 2 y , − 2 x 2 y , − x 2 y
x y 2 terms: − 3 x y 2 , 4 x y 2 , x y 2
x terms: 2 x , − 3 x
y terms: 5 y
Step 3: Har group combine karo
x^2y \text{ terms:} &\quad 6x^2y - 2x^2y - x^2y = (6-2-1)x^2y = 3x^2y \\
xy^2 \text{ terms:} &\quad -3xy^2 + 4xy^2 + xy^2 = (-3+4+1)xy^2 = 2xy^2 \\
x \text{ terms:} &\quad 2x - 3x = (2-3)x = -x \\
y \text{ terms:} &\quad 5y \text{ (koi aur } y \text{ terms nahi)}
\end{align}$$
**Step 4:** Final expression likho
$$= 3x^2y + 2xy^2 - x + 5y$$
**Answer:** $3x^2y + 2xy^2 - x + 5y$
Common mistake Mistake 1: Unlike Terms Ko Combine Karna
Galat approach: 3 x + 5 y = 8 x y
Yeh sahi kyun lagta hai: "Main 3 aur 5 add kar raha hoon, toh 8 milega, aur mere paas x bhi hai aur y bhi, toh... 8 x y ?"
Steel-man: Yeh intuitively tab sense deta hai jab tum algebra ko basic arithmetic ki tarah sochte ho—bas saare numbers add karo aur saare letters ikatthe karo. Student "add" dekhta hai aur sab kuch add karne ki koshish karta hai.
Fix: Variables labels nahi hain, woh multipliers hain jo unknown numbers represent karte hain. 3 x matlab "3 times koi number x " aur 5 y matlab "5 times ek alag number y ." Inhe combine nahi kar sakte, jaise 3 meters mein 5 kilograms nahi add kar sakte—different units hain!
Sahi: 3 x + 5 y waise hi rehta hai 3 x + 5 y
Common mistake Mistake 2: Negative Sign Distribute Karna Bhool Jana
Galat approach: ( 5 x + 3 ) − ( 2 x + 7 ) = 5 x + 3 − 2 x + 7 = 3 x + 10
Yeh sahi kyun lagta hai: Students aksar sochte hain ki minus sign sirf uske baad ki pehli term par lagta hai, jaise 5 − 2 mein, jahan sirf 2 negative hota hai.
Steel-man: Arithmetic mein hum 5 − 2 likhte hain, 5 − ( + 2 ) nahi. Toh jab − ( 2 x + 7 ) dikhta hai, toh naturally lagta hai "minus 2 x ... aur phir baad mein + 7 ." Parentheses functional ki jagah decorative lagte hain.
Fix: Negative sign actually poore expression par − 1 ka multiplication hai:
− ( 2 x + 7 ) = − 1 ⋅ ( 2 x + 7 ) = − 1 ⋅ 2 x + ( − 1 ) ⋅ 7 = − 2 x − 7
Sahi: ( 5 x + 3 ) − ( 2 x + 7 ) = 5 x + 3 − 2 x − 7 = 3 x − 4
Pro tip: Subtraction ko "opposite add karna" ki tarah likho: A − B = A + ( − B )
Common mistake Mistake 3: Coefficients Ki Jagah Exponents Add Karna
Galat approach: 2 x 3 + 5 x 3 = 7 x 6
Yeh sahi kyun lagta hai: Multiply karte waqt hum exponents ADD karte hain: x 3 ⋅ x 3 = x 6 . Students rules mix up kar dete hain.
Steel-man: Kuch situations HAIN jahan exponents add hote hain (multiplication) aur kuch jahan coefficients multiply hote hain (woh bhi multiplication: 2 x ⋅ 3 x = 6 x 2 ). Genuinely confusing hai ki kaunsa rule kab lagta hai.
Fix:
Addition/subtraction: Sirf coefficients combine hote hain. Exponents same rehte hain.
2 x 3 + 5 x 3 = ( 2 + 5 ) x 3 = 7 x 3
Multiplication: Coefficients multiply hote hain, exponents add hote hain.
2 x 3 ⋅ 5 x 3 = ( 2 ⋅ 5 ) x 3 + 3 = 10 x 6
Yaad rakhne ka tarika: Addition matlab "same cheez zyada count karna." Agar tumhare paas x 3 ke 2 boxes hain aur 5 aur boxes add ho, toh tumhare paas x 3 ke 7 boxes hain—koi alag power nahi!
Mnemonic OLIVE — The Like Terms Rule
O nly
L ike (same variables)
I n
V alue (same powers)
E ver combine
Ek olive ke ped ki imagine karo: har type ki olive (green, black Kalamata) alag branches par ugti hai. Tum zyada green olives count kar sakte ho, lekin green olives ko unhe add karke black mein nahi badal sakte!
Recall Feynman Explanation (12-saal ke bache ko samjhao)
Socho tum apna toy collection organize kar rahe ho. Tumhare paas hai:
3 red cars
5 blue cars
2 red planes
Agar main poochhun "tumhare paas kitni red cars hain jab tumhare dost tumhe 4 aur red cars deta hai?", tum bologe 3 + 4 = 7 red cars. Easy!
Lekin agar main poochhun "kitne toys hain agar tum 3 red cars aur 5 blue cars combine karo?" Tum nahi bol sakte "8 red-blue cars"—yeh sense nahi banta! Tumhare paas 3 red cars AUR 5 blue cars hain. Woh alag rehte hain kyunki woh different types hain.
Algebra bhi same hai:
3 x + 4 x = 7 x ✓ (same type: dono "x " cheezein hain)
3 x + 5 y stays 3 x + 5 y ✗ (different types: "x " cheezein aur "y " cheezein)
Letter (x , y ) batata hai ki tumhare paas kaunsi "type" ki cheez hai. Aage ka number (coefficient) batata hai kitni hain. Tum sirf "kitni" wala part tab add kar sakte ho jab "type" bilkul same ho!
Subtraction signs kyun flip karta hai? Socho tumhara dost toys waapis maangta hai. Agar woh chahta hai ki tum "2 red cars aur 3 blue cars" hataao, tum dono types le rahe ho: − 2 red cars aur − 3 blue cars. Minus sab par lagta hai jo woh le ja rahe hain!
Simplify karo: ( 8 m + 5 n − 3 ) + ( 2 m − 7 n + 9 )
Simplify karo: ( 10 p 2 − 4 p + 6 ) − ( 3 p 2 + 2 p − 5 )
Simplify karo: ( 4 a 2 b − 3 ab + 7 ) + ( − 2 a 2 b + ab − 2 ) − ( a 2 b − 5 ab + 3 )
Error analysis: Ek student ne likha ( 6 x − 4 ) − ( 2 x − 1 ) = 4 x − 5 . Unki galti dhundho aur explain karo.
Like terms kya hote hain? :: Same variables wale terms jo same powers par raised hon. Example: 5 x 2 aur − 3 x 2 like terms hain; 5 x 2 aur 5 x like terms NAHI hain.
Like terms hi add/subtract kyun ho sakte hain? Distributive property ki wajah se. 3 x + 5 x = ( 3 + 5 ) x = 8 x common x factor out karke. Unlike terms mein koi common factor nahi hota jo bahar nikala ja sake.
Parentheses mein likhe expression ko subtract karte waqt signs ka kya hota hai? Parentheses ke andar ki har term ka sign flip hota hai. ( a − b + c ) − ( d − e + f ) = a − b + c − d + e − f . Minus − 1 se multiplication ki tarah distribute hota hai.
Kya 2 x 2 + 3 x 2 simplify ho sakta hai, aur agar haan toh kya milega? Haan. Dono terms mein x 2 hai, toh woh like terms hain. 2 x 2 + 3 x 2 = ( 2 + 3 ) x 2 = 5 x 2 .
Kya 4 x + 7 y aur simplify ho sakta hai? Nahi. x aur y different variables hain, isliye yeh unlike terms hain. Expression 4 x + 7 y hi rehta hai.
5 x + 3 y = 8 x y mein kya galti hai?Unlike terms ko combine nahi kiya ja sakta. 5 x (paanch x 's) aur 3 y (teen y 's) different types hain, jaise seb aur santre. Expression 5 x + 3 y hi rehta hai.
( 9 a − 4 ) − ( 3 a + 2 ) simplify karoNegative distribute karo: 9 a − 4 − 3 a − 2 . Like terms combine karo: ( 9 a − 3 a ) + ( − 4 − 2 ) = 6 a − 6 .
Addition/subtraction mein exponents wale terms mein kya combine hota hai: coefficients ya exponents? Coefficients combine hote hain. Exponents same rehte hain. 4 x 5 + 7 x 5 = ( 4 + 7 ) x 5 = 11 x 5 , na ki 11 x 10 .
ax^n plus bx^n equals a+b x^n