1.3.6 · Maths › Basic Data & Probability
Probability measure karta hai ki koi event kitni likely hai occur hone ki. Yeh uncertain situations mein outcomes predict karne ki foundation hai—coin flips se lekar weather forecasts tak, medical diagnoses tak.
Imagine karo tumhare paas ek bag of marbles hai. Probability answer deta hai: "Agar main ek bina dekhe pick karun, to mujhe red marble milne ke chances kya hain?"
Hum count karte hain:
Saare possible outcomes (sample space)
Jo outcomes hum chahte hain (favourable outcomes)
Probability = favourable outcomes ka fraction out of saare possible ones
Yeh bas organized counting + division hai.
Definition Sample Space (S)
Sample space set of all possible outcomes hota hai kisi experiment ya random process ka.
Notation: S or Ω
WHY yeh matter karta hai: Probability calculate karne se pehle, hume har possible cheez jaanni hogi jo ho sakti hai. Missing outcomes calculation ko tod dete hain.
Experiment
Sample Space
Number of outcomes
Toss 1 coin
S = { H , T }
2
Roll1 die
S = { 1 , 2 , 3 , 4 , 5 , 6 }
6
Toss 2 coins
S = { HH , HT , TH , T }
4
Pick a card
S = { 52 different cards }
52
Worked example 2 Dice ke liye Sample Space Banana
Question: Jab do dice roll karo to sample space kya hoga?
Step 1 — WHY: Har die ke 6 outcomes hain. Woh independent hain, isliye hume saare combinations chahiye.
Step 2 — HOW: Pehla die 1–6 dikha sakta hai, aur har ek ke liye , doosra die bhi 1–6 dikha sakta hai.
Total outcomes = 6 × 6 = 36
Step 3 — WHAT:
S = {( 1 , 1 ) , ( 1 , 2 ) , … , ( 1 , 6 ) , ( 2 , 1 ) , ( 2 , 2 ) , … , ( 6 , 6 )}
Sample space mein 36 ordered pairs hain.
Ek event sample space ka koi bhi subset hota hai—ek ya zyada outcomes ka collection jisme hum interested hain.
Types:
Simple event: Exactly 1 outcome contain karta hai (e.g., 3 roll karna)
Compound event: Multiple outcomes contain karta hai (e.g., even number roll karna)
Sure event: E = S (hamesha hota hai, probability = 1)
Impossible event: E = ∅ (kabhi nahi hota, probability = 0)
Ek single die roll karne ke liye jahan S = { 1 , 2 , 3 , 4 , 5 , 6 } :
Event Description
Event Set
Type
"Roll a 4"
E 1 = { 4 }
Simple
"Roll an even number"
E 2 = { 2 , 4 , 6 }
Compound
"Roll less than 7"
E 3 = { 1 , 2 , 3 , 4 , 5 , 6 } = S
Sure event
"Roll a 7"
E 4 = ∅
Impossible
Probability ke axioms se shuru karte hain:
Axiom 1: Kisi bhi event E ke liye, 0 ≤ P ( E ) ≤ 1
Axiom 2: P ( S ) = 1 (kuch na kuch to hona chahiye)
Axiom 3: Agar events mutually exclusive hain, P ( A ∪ B ) = P ( A ) + P ( B )
Equally likely outcomes ke liye:
Agar sample space mein n outcomes hain, sab equally likely, aur kuch na kuch hone ki probability 1 hai:
P ( outcome 1 ) + P ( outcome 2 ) + ⋯ + P ( outcome n ) = 1
Kyunki sab equal hain, maano P ( each outcome ) = p :
n ⋅ p = 1 ⟹ p = n 1
Har outcome ki probability n ( S ) 1 hai.
Ab agar event E mein k outcomes hain, Axiom 3 se (woh mutually exclusive hain):
P ( E ) = k times n ( S ) 1 + n ( S ) 1 + ⋯ + n ( S ) 1 = n ( S ) k = n ( S ) n ( E )
Isliye counting probability ke liye kaam karta hai!
Worked example Complement Ka Use
Question: Ek bag mein 5 red aur 3 blue marbles hain. Red nahi pick karne ki probability kya hai?
Method 1 (Direct):
P ( blue ) = 8 3
Method 2 (Complement):
P ( red ) = 8 5
P ( not red ) = 1 − 8 5 = 8 3 ✓
WHY complement use karein? Jab "not E" count karna, E count karne se aasaan ho (e.g., "at least one success" vs. "all failures").
Worked example Example 1: Single Die Roll
Question: 4 se bada number roll karne ki probability kya hai?
Step 1 — Sample space identify karo:
S = { 1 , 2 , 3 , 4 , 5 , 6 } , so n ( S ) = 6
WHY? Die ke 6 faces hain, sab equally likely.
Step 2 — Event define karo:
E = { numbers > 4 } = { 5 , 6 } , so n ( E ) = 2
WHY? Sirf 5 aur 6 hi "greater than 4" satisfy karte hain.
Step 3 — Formula apply karo:
P ( E ) = n ( S ) n ( E ) = 6 2 = 3 1
Answer: 3 1 or about 33.3%
Worked example Example 2: Two Coins
Question: 2 coins toss karne par exactly ek head aane ki probability kya hai?
Step 1 — Sample space:
S = { HH , HT , TH , TT } , so n ( S ) = 4
WHY yeh outcomes? First coin: H or T. Har ek ke liye, second coin: H or T. Yeh 2 × 2 = 4 combinations hai.
WHY HT aur TH alag hain? Woh alag outcomes represent karte hain (pehla coin vs. doosra coin heads dikhana).
Step 2 — Event:
E = { HT , TH } , so n ( E ) = 2
WHY? "Exactly one head" matlab ek H aur ek T. Woh HT ya TH hai.
Step 3 — Calculate karo:
P ( E ) = 4 2 = 2 1
Answer: 2 1 or 50%
Worked example Example 3: Deck of Cards
Question: Standard deck se face card (J, Q, K) draw karne ki probability kya hai?
Step 1 — Sample space:
Standard deck mein 52 cards hain, so n ( S ) = 52
Step 2 — Favourable outcomes count karo:
4 suits × 3 face cards per suit = 12 face cards
n ( E ) = 12
WHY 3 per suit? Jack, Queen, King har ek mein: hearts, diamonds, clubs, spades.
Step 3 — Calculate karo:
P ( E ) = 52 12 = 13 3
Answer: 13 3 ≈ 0.231 or 23.1%
Worked example Example 4: Sum of Two Dice
Question: Do dice ka sum 7 hone ki probability kya hai?
Step 1 — Sample space:
n ( S ) = 36 (section 1 dekho: 6×6 outcomes)
Step 2 — Favourable outcomes dhundho:
Sum = 7 jab: ( 1 , 6 ) , ( 2 , 5 ) , ( 3 , 4 ) , ( 4 , 3 ) , ( 5 , 2 ) , ( 6 , 1 )
WHY yeh? Hume woh pairs chahiye jo 7 mein add ho jayein. Systematically check karo:
Agar pehla die = 1, doosra 6 hona chahiye
Agar pehla die = 2, doosra 5 hona chahiye
Saari 6 possibilities ke liye continue karo
n ( E ) = 6
Step 3 — Calculate karo:
P ( E ) = 36 6 = 6 1
Answer: 6 1 ≈ 0.167 or 16.7%
Common mistake Mistake 1: Yeh Bhool Jaana Ki Outcomes Hamesha Equally Likely Nahi Hote
Galat soch: "Jab main do coins toss karta hun, mujhe 0, 1, ya 2 heads milte hain—3 outcomes. To P(1 head) = 1/3."
Kyu sahi lagta hai: Humne teen distinct possibilities count ki.
Fix: Woh outcomes equally likely nahi hain!
0 heads: sirf TT (1 tarika)
1 head: HT ya TH (2 tarike)
2 heads: sirf HH (1 tarika)
Sahi sample space: {HH, HT, TH, TT} — yeh 4 outcomes equally likely HAIN.
Rule: Formula n ( S ) n ( E ) TABHI use karo jab S ke saare outcomes equally likely hon.
Common mistake Mistake 2: "Or" ko "And" Samajh Lena (Compound Events)
Example: Die roll karo. P(even OR greater than 4) kya hai?
Galat: Evens count karo: {2,4,6} = 3. >4 count karo: {5,6} = 2. To 6 3 + 2 = 6 5 ?
Kyu galat hai: Humne 6 do baar count kiya! Woh even AND >4 hai.
Fix:
Even: {2, 4, 6}
Greater than 4: {5, 6}
Even OR >4: {2, 4, 5, 6} — duplication ke bina union
P ( E ) = 6 4 = 3 2
Rule: "Or" ke liye, sets ka union lo (no double-counting). "And" ke liye, intersection lo.
Common mistake Mistake 3: Ordered vs. Unordered ke liye Galat Sample Space
Scenario: {R, B, G} se bina replacement ke 2 balls pick karo.
Galat sample space: {RB, RG, BG} — 3 outcomes, to P(R milna) = 2/3?
Kyu sahi lagta hai: Hum sirf pairs dekh rahe hain.
Fix: Kya hum order distinguish kar rahe hain?
Ordered (pehle kaun aaya matter karta hai): {RB, BR, RG, GR, BG, GB} — 6 outcomes
Unordered (sirf pair matter karta hai): {RB, RG, BG} — 3 outcomes, LEKIN probabilities alag hain!
Equally likely picking ke liye: ordered use karo. Har pick sequence equally likely hoti hai.
Rule: Jab objects sequentially draw kiye jayein, order distinguish karo jab tak explicitly na bola jaye ki outcomes "combinations" hain.
Recall Feynman Technique — Ek 12-Saal-Ke Bacche Ko Explain Karo
Imagine karo tum apne chhote sibling ko probability explain kar rahe ho:
"Theek hai, to probability guessing games jaisi hai. Maano tumhare paas ek box hai 10 toys ke saath—7 cars aur 3 dolls. Tum aankhein band karke ek pakad lete ho. Car milne ke chances kya hain?
Pehle, SAARI toys count karo: 10 total. Yeh sab kuch hai jo ho sakta tha.
Phir, jo tum CHAHTE ho woh count karo: 7 cars.
Tumhare chances = fraction: 10 mein se 7, ya 7/10. Woh 0.7 hai, ya 70%.
Agar maine kaha 'Car nahi milne ka chance kya hai?' — to woh doll milna hai. 10 toys mein se 3 dolls = 3/10 ya 30%.
Dhyaan do: 70% + 30% = 100%. Kyunki tum ZAROOR kuch pao ge!
Probability bas hai: (jo tum chahte ho) ÷ (saari possibilities). Jab tak har toy ko equally pick hone ka chance hai, yeh perfectly kaam karta hai."
Mnemonic Formula Yaad Rakho
"FavoURable over TOTal"
P = T F → F avourable / T otal
Ya socho: "PART over WHOLE" — jo part tum chahte ho, poore options ke set par.
Sample Space — saare possible outcomes
Events and Set Theory — events as subsets, unions, intersections
Complement of an Event — jo nahi hota
Mutually Exclusive Events — saath nahi ho sakte
Axioms of Probability — foundation rules
Conditional Probability — extra information dene par probability
Counting Principles — complex sample spaces ke liye permutations aur combinations
Random Variables — numerical outcomes aur unki probabilities
Law of Large Numbers — probability → frequency with many trials
#flashcards/maths
Sample space kya hota hai? :: Kisi random experiment ke saare possible outcomes ka set.
Probability mein event kya hota hai? Sample space ka ek subset; ek ya zyada outcomes ka collection jisme hum interested hain.
Classical probability formula kya hai? P ( E ) = n ( S ) n ( E ) jahan n ( E ) favourable outcomes ki number hai aur n ( S ) total outcomes ki number hai, assuming saare outcomes equally likely hain.
Kisi bhi probability value ki range kya hoti hai? 0 ≤ P ( E ) ≤ 1 . Probability negative ya 1 se badi nahi ho sakti.
Complement rule kya hai? P ( E ′ ) = 1 − P ( E ) jahan E ′ woh event hai ki E occur nahi hota.
Agar fair die roll karo, to P(2 ya kam number aana) kya hai? 6 2 = 3 1 kyunki favourable outcomes {1, 2} hain 6 total outcomes mein se.
Do coins toss karne par sample space kya hoga? {HH, HT, TH, TT} — chaar equally likely outcomes.
Do fair coins toss karne par P(exactly one head) kya hai? 4 2 = 2 1 kyunki {HT, TH} favourable outcomes hain 4 total mein se.
Do dice roll karne par sample space mein kitne outcomes hote hain? 36 outcomes (6 × 6), ordered pairs (1,1) se (6,6) tak.
Do dice roll karne par P(sum = 7) kya hai? 36 6 = 6 1 kyunki sum 7 paane ke 6 tarike hain: {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}.
Hum hamesha outcomes count karke divide kyu nahi kar sakte? Formula P ( E ) = n ( S ) n ( E ) tabhi kaam karta hai jab sample space ke saare outcomes equally likely hon.
52 cards ki deck mein, P(heart draw karna) kya hai? 52 13 = 4 1 kyunki 52 cards mein 13 hearts hain.
Favourable outcomes n of E