1.1.9 · Maths › Arithmetic & Number Systems
Intuition Ek saans mein badi idea
Har whole number jo 1 se bada hai, woh ek word ki tarah hai jo ek fixed alphabet of primes se bana hota hai. Numbers jaise 4 , 6 , 12 ko chote factors mein toda ja sakta hai , lekin primes (2 , 3 , 5 , 7 , … ) ko nahi toda ja sakta — ye multiplication ke atoms hain. Prime factorization woh kaam hai jisme hum kisi number ko tab tak todte rahte hain jab tak sirf ye atoms na bache.
Intuition Primes ki parwah kyun karein?
Uniqueness humein ek fingerprint deti hai. Fundamental Theorem of Arithmetic kehta hai ki har number ki exactly ek prime factorization hoti hai (order ko ignore karte hue). Toh 12 = 2 2 ⋅ 3 aur kuch nahi — yahi fingerprint humein HCF/GCD , LCM compute karne, fractions simplify karne, divisibility check karne, aur divisors count karne mein help karti hai.
80/20 payoff: ek skill master karo (number ko primes mein todna) aur poora ek chapter unlock ho jaata hai — LCM, HCF, rationalising, cryptography roots — bilkul free mein.
Prime ek aisa natural number hota hai jo > 1 ho aur jiske sirf do divisors hon: 1 aur khud woh number. Examples: 2 , 3 , 5 , 7 , 11 , 13 . Note karo ki 1 prime nahi hai (iske sirf ek divisor hai).
Definition Prime factorization
Kisi number n > 1 ko primes ke product ke roop mein likhna:
n = p 1 a 1 p 2 a 2 ⋯ p k a k
jahan har p i prime hai aur har exponent a i ≥ 1 hai. Yeh form reordering tak unique hoti hai.
Definition Fundamental Theorem of Arithmetic (FTA)
Har integer n > 1 ko primes ke product ke roop mein likha ja sakta hai, aur yeh factorization unique hoti hai sivaay factors ke order ke.
Tree kyun?
Tum ek number ko kisi bhi do factors mein todte rehte ho. Composite branches phir se split hoti hain; prime branches ruk jaati hain (leaves ban jaati hain). Jo leaves milti hain wahi tumhare primes hain. Split karne ke alag-alag choices se same leaves milti hain — yahi FTA in action hai, aur ek achha self-check bhi hai.
60 ka Factor tree
60 = 6 × 10 mein split karo.
6 = 2 × 3 → dono prime, ruko. Yeh step kyun? 2 , 3 ke koi chote factors nahi hain.
10 = 2 × 5 → dono prime, ruko.
Leaves collect karo: 2 , 3 , 2 , 5 .
60 = 2 × 2 × 3 × 5 = 2 2 ⋅ 3 ⋅ 5
Steel-man check: alag se shuru karo, 60 = 4 × 15 .
4 = 2 × 2 , 15 = 3 × 5 → leaves 2 , 2 , 3 , 5 . Same answer. ✅ (Yeh tumhari apni aankhon ke saamne uniqueness ko prove karta hai.)
Ladder kyun?
Kisi bhi factors mein split karne ki jagah, tum sabse chota prime jo fit ho use divide out karte ho , baar baar, quotients ko ladder ki rungs ki tarah neeche likhte jaate ho. Yeh systematic hai — koi guessing nahi — isliye exam pressure mein yeh zyada safe method hai.
60 ke liye Ladder
Hamesha sabse chote prime se shuru karo: 2 , phir 3 , phir 5 , phir 7 …
2 | 60
2 | 30
3 | 15
5 | 5
| 1 ← jab 1 aaye tab ruko
2 se shuru kyun? 60 even hai → 2 se divisible hai. Jab tak even ho, 2 se divide karte raho.
3 par kyun aaye? 15 odd hai, 2 se divisible nahi; sabse chota prime jo 15 ko divide karta hai woh 3 hai.
1 par kyun rukna? Jab quotient 1 ho jaaye, koi factors nahi bache.
Left side ke primes: 2 , 2 , 3 , 5 .
60 = 2 2 ⋅ 3 ⋅ 5
84 ke liye Ladder (poora walk-through)
2 | 84
2 | 42
3 | 21
7 | 7
| 1
84 even → ÷2 se 42 milta hai. Kyun? Even numbers hamesha 2 ka factor lete hain.
42 even → ÷2 se 21 milta hai. Ab 21 odd hai, 2 se divide karna band karo.
21 = 3 × 7 : ÷3 se 7 ; ÷7 se 1 .
84 = 2 2 ⋅ 3 ⋅ 7
Recall Dekhne se pehle predict karo
Q: 360 ko factorize karo. Pehle 2 , 3 , 5 ke exponents forecast karo.
Verify (ladder):
2 | 360 2 | 180 2 | 90 3 | 45 3 | 15 5 | 5 | 1
360 = 2 3 ⋅ 3 2 ⋅ 5
Divisors = ( 3 + 1 ) ( 2 + 1 ) ( 1 + 1 ) = 24 . Kya tumne 2 3 ⋅ 3 2 ⋅ 5 likha? Agar tumne 2 2 likha, toh dobara count karo kitni baar 360 even hai (360 → 180 → 90 = teen halvings).
Common mistake "1 ek prime hai, toh main ise include karunga."
Kyun sahi lagta hai: 1 sab kuch divide karta hai aur basic/indivisible lagta hai. Fix: ek prime ko exactly do distinct divisors chahiye; 1 ke sirf ek hain. 1 ko include karne se uniqueness toot jaati (6 = 2 ⋅ 3 = 1 ⋅ 2 ⋅ 3 = 1 ⋅ 1 ⋅ 2 ⋅ 3 … ). Isliye 1 ek unit hai, prime nahi.
Common mistake Repeated primes ko powers ke roop mein likhna bhool jaana.
Kyun sahi lagta hai: 60 = 2 ⋅ 2 ⋅ 3 ⋅ 5 sahi hai . Fix: yeh galat nahi hai, lekin 2 2 ⋅ 3 ⋅ 5 mein compress karo — exam mein divisors/HCF/LCM ke formulas ko exponents chahiye hote hain. Ek repeat miss karna (likhna 2 ⋅ 3 ⋅ 5 = 30 ) ek real error hai though: jab tak same prime fit ho, divide karte raho.
Common mistake Ladder ko jaldi band kar dena.
Kyun sahi lagta hai: tum ek odd number par pahunch jaate ho aur feel karte ho ki ho gaya. Fix: tab ruko jab quotient 1 ho. Agar tumhe koi bada number jaise 77 mile, toh primes 3 , 5 , 7 , 11 … test karo — yahan 77 = 7 × 11 .
Common mistake Non-prime divisor test karna.
Kyun sahi lagta hai: "60 ÷ 6 = 10 , nice round numbers!" Fix: ladder mein sirf primes use karne chahiye, warna atoms nahi milenge. 6 se split karna ek tree mein theek hai (tum 6 ko phir split karte ho) lekin ladder rung mein kabhi nahi.
"2-3-5-7, phir 11 ka darwaza khatkhatao"
Primes ko order mein test karo 2 , 3 , 5 , 7 , 11 , 13 . Tab test karna band karo jab trial prime squared baaki number se zyada ho jaaye (tab jo bacha hai woh khud prime hai). E.g. 77 ke liye, 77 ≈ 8.7 tak check karo: sirf 7 kaam karta hai → 77 = 7 ⋅ 11 .
Recall Simply explain karo (hidden)
Socho har number ek LEGO castle hai. Kuch blocks chote blocks mein tod sakte hain, lekin prime blocks (2 , 3 , 5 , 7 … ) aur nahi toot sakte — ye sabse tiny pieces hain. Prime factorization matlab apna castle tab tak todna jab tak sirf ye tiny LEGO pieces table par na hon. Cool magic yeh hai: chahe tum kisi bhi tarah se todein (tree method) ya ek ek step carefully (ladder method), tumhe hamesha exactly same pile of tiny blocks milti hai. Yeh "har baar same pile" wala rule hi math ko itna clean banata hai.
1 prime number kyun nahi hai? Ek prime mein exactly do distinct divisors hone chahiye (1 aur khud woh); 1 ka sirf ek divisor hai, isliye woh unit hai, prime nahi.
Fundamental Theorem of Arithmetic batao. Har integer >1 primes ka product hota hai, aur woh factorization unique hoti hai sivaay factors ke order ke.
60 ko prime-factorize karo. 2 2 ⋅ 3 ⋅ 5 .
84 ko prime-factorize karo. 2 2 ⋅ 3 ⋅ 7 .
Ladder method mein kab rukna chahiye? Jab quotient 1 ban jaaye.
Factor tree mein kaunse nodes leaves hote hain? Prime numbers (unhe aur split nahi kiya ja sakta).
n = p 1 a 1 ⋯ p k a k ke divisors ki count ka formula?d ( n ) = ( a 1 + 1 ) ( a 2 + 1 ) ⋯ ( a k + 1 ) .
Prime powers se HCF aur LCM kaise nikaalte hain? HCF = primes ka product min exponent par; LCM = max exponent par.
60 aur 84 ka HCF aur LCM primes se compute karo. HCF = 2 2 ⋅ 3 = 12 ; LCM = 2 2 ⋅ 3 ⋅ 5 ⋅ 7 = 420 .
Ladder mein pehle kaunsa prime test karna chahiye? Sabse chota, 2 (jab tak even ho divide karte raho), phir 3, 5, 7...
Alag factor trees same answer kyun dete hain? Unique factorization (FTA) ki wajah se — prime leaves ka multiset fixed hota hai.
360 = 2 3 ⋅ 3 2 ⋅ 5 ke kitne divisors hain?( 3 + 1 ) ( 2 + 1 ) ( 1 + 1 ) = 24 .
HCF and LCM — directly in-hi prime powers se compute hote hain (min/max exponents).
Divisibility Rules — decide karte hain ki ladder mein aage kaunsa prime divide karega.
Fundamental Theorem of Arithmetic — guarantee karta hai ki answer unique hai.
Simplifying Fractions — numerator & denominator ke shared prime factors cancel karo.
Number of Divisors — exponent-plus-one formula use karta hai.
Sieve of Eratosthenes — woh prime "alphabet" generate karta hai jise tum test mein use karte ho.
Fundamental Theorem of Arithmetic
n as product of prime powers
HCF LCM divisibility fractions