Hum kyun care karte hain? Reverse bias ke neeche depletion region wide ho jaati hai aur lagbhag poora applied voltage hold karti hai. Is region mein ek huge electric field hota hai. Physics sirf do tarike deta hai jisse woh field achanak bahut saare free carriers conjure kar sake — aur kaun sa jeetta hai yeh depend karta hai junction kitna heavily doped hai usse.
Lightly doped kyun? Light doping ⇒ wide depletion region ⇒ carrier ke paas ionization energy Ei gain karne ke liye collide karne se pehle ek lamba runway hota hai.
Ek carrier jo distance ℓ (the mean free path) field E mein travel karta hai, energy gain karta hai:
ΔW=qEℓ
Yeh step kyun? Work = force × distance, aur charge par force qE hai. Ek atom ko ionize karne ke liye use ionization energy Ei tak pahunchna chahiye:
qEℓ≥Ei⇒E≥qℓEi
Yeh ek critical fieldEcrit define karta hai. Ab — voltage se yeh kaise relate karta hai? Wide depletion width W ke liye, zaroori voltage roughly VBR≈EcritWeff hai, aur kyunki lightly-doped junctions mein W bada hota hai, VBR bada hota hai.
Temperature signature: Zyada T ⇒ zyada lattice vibration ⇒ carriers jaldi collide karte hain (shorter effective ℓ) ⇒ woh har collision mein kam energy gain karte hain ⇒ zyada field chahiye ⇒ VBRT ke saath increase karta hai. Toh avalanche ka positive temperature coefficient hota hai.
Heavily doped kyun? Heavy doping ⇒ narrow depletion region ⇒ ek modest voltage bhi ek colossal field produce karta hai (E=V/W, small W) ⇒ tunneling barrier itna thin ho jaata hai ki punch through ho sake.
Temperature signature: Zyada T band gap Eg ko thoda shrink karta hai ⇒ tunnel karna easier ⇒ breakdown lower voltage par hota hai ⇒ Zener ka negative temperature coefficient hota hai.
Reverse current mein achanak badi rise jab VR critical VBR tak pahunche.
Avalanche mechanism
Impact ionization — fast carriers electrons ko bonds se knock out karte hain, ek chain reaction.
Zener mechanism
Electrons ki quantum tunneling ek narrow band gap ke across bahut high field mein.
Avalanche needs which doping?
Light doping → wide depletion → long acceleration runway.
Zener needs which doping?
Heavy doping → narrow depletion → huge field → tunneling.
Temp coefficient of avalanche
Positive (VBR temperature ke saath rise karta hai).
Temp coefficient of Zener
Negative (VBR temperature ke saath fall karta hai).
Approx voltage where mechanisms cross over
~5–6 V (TC ≈ 0, bahut stable references).
Multiplication factor formula
M=1/[1−(VR/VBR)n].
Is breakdown destructive?
Nahi, agar current limited ho; destruction sirf excess power/heat se hoti hai.
Why does avalanche VBR rise with T?
Zyada lattice vibration → shorter mean free path → carriers kam energy gain karte hain → zyada field chahiye.
Why does Zener VBR fall with T?
Band gap shrink hota hai → tunneling easier → lower voltage par breakdown.
Recall Feynman: 12-year-old ko explain karo
Socho ek bheed ek fence ke through push karne ki koshish kar rahi hai (diode reverse current block kar raha hai). Avalanche aise hai jaise ek runner ek lambe hallway mein tezi se sprint karta hai, logon se crash karta hai aur unhe bhi running karwa deta hai — jaldi ek stampede ho jaata hai. Uske liye ek lamba hallway chahiye (lightly-doped, wide gap). Zener tab hota hai jab wall itni thin hai ki log seedha ghost ho ke iske through nikal jaate hain jaise magic (tunneling) — uske liye ek super-thin wall chahiye (heavily-doped). Lamba hallway = stampede se pehle high voltage; thin wall = ghost through karne ke liye low voltage. Aur yeh neat trick hai: heating ghosts ki madad karta hai (Zener down) lekin runners ko slow karta hai (avalanche up).