4.8.3 · Chemistry › Spectroscopy & Analysis (Intro)
Intuition 30-second picture
Ek molecule ke bonds chote springs hote hain jo masses (atoms) ko connect karte hain. Unpar infrared light daalo aur har spring absorb karta hai exactly woh frequency jis par use wiggle karna pasand hai. Stiffer spring (stronger bond) ya lighter masses tezi se vibrate karte hain → higher frequency par absorb karte hain. Toh ek IR spectrum literally ek fingerprint hai — kaun se bonds hain aur kitne stiff hain .
Definition Infrared absorption
Ek bond IR radiation tab absorb karta hai jab photon ki frequency bond ki natural vibrational frequency se match kare AUR vibration molecule ka dipole moment change kare. Dipole change nahi ⇒ absorption nahi (IR-inactive).
Dipole rule kyun? Light ek oscillating electric field hai. Usase energy lene ke liye, molecule ko ek oscillating "handle" present karna padta hai — ek changing dipole. O 2 ka symmetric stretch zero dipole change deta hai, isliye O 2 IR mein invisible hai. C = O jaisa polar bond ek bada dipole swing deta hai, isliye woh strongly absorb karta hai.
Bond = harmonic oscillator. Do masses m 1 , m 2 ek spring se jude hain jiska stiffness k hai (the force constant , units N/m).
Step 1 — Newton + Hooke. Ek single mass ke liye spring par, F = − k x aur F = ma = m x ¨ :
m x ¨ = − k x ⇒ x ¨ = − m k x
Yeh SHM hai jiska angular frequency ω = k / m hai.
Yeh step kyun? x ¨ = − ω 2 x ka solution x = A cos ω t hai — ω par oscillation.
Step 2 — ek nahi, do atoms. Dono atoms move karte hain, isliye m ki jagah reduced mass use karo:
μ = m 1 + m 2 m 1 m 2
Kyun? Centre-of-mass frame mein relative coordinate ek single particle ki tarah behave karta hai jiska mass μ hai spring par.
Step 3 — frequency.
ν = 2 π 1 μ k
Step 4 — chemists wavenumber use karte hain ν ~ = 1/ λ = ν / c (units cm⁻¹):
ν ~ = 2 π c 1 μ k
Intuition C–H itna high (≈3000 cm⁻¹) kyun hai
H sabse halka atom hai ⇒ tiny μ ⇒ k / μ bahut bada ho jaata hai. Spring extra-stiff nahi hai; mass bas pankh jaisa halka hai.
Yeh yaad kar lo — yeh ~80% IR problems solve kar deta hai.
Group
ν ~ (cm⁻¹)
Shape / note
Kyun wahan hai
O–H (alcohol)
3200–3550
broad, rounded
H-bonding isse smear kar deti hai
O–H (carboxylic acid)
2500–3300
bahut broad
strong H-bonding
N–H
3300–3500
1–2 sharper spikes
NH₂ mein do dikhte hain
≡C–H
~3300
sharp
high k region
=C–H / C–H
2850–3100
sharp
light H
C≡N
2200–2260
sharp, medium
triple-ish, stiff
C≡C
2100–2260
weak (low dipole)
symmetric ⇒ weak
C=O
1670–1750
strong, sharp
bada dipole → tall peak
C=C
1620–1680
weak–medium
small dipole
C–O
1000–1300
strong
fingerprint edge
neeche jaao = bonds looser/heavier hote jaate hain
"O Never Cuts Cake On Cake" key absorptions ke descending order ke liye:
O –H (3550) → N –H (3400) → C –H (3000) → C ≡N/C≡C (2200) → O =C yaani C=O (1700) → C =C (1650). High-energy stretches upar, single bonds neeche.
Definition Fingerprint region
Woh bheed-bhaad wala zone ~1500 cm⁻¹ se neeche (400 tak). Complex bending aur skeletal C–C, C–O vibrations se bhara hua hai jo ek-ek karke assign karna mushkil hai, lekin overall pattern har molecule ke liye unique hota hai — ek fingerprint ki tarah. Molecular identity confirm karne ke liye reference spectrum se match karke use kiya jaata hai.
~1500 cm⁻¹ se upar ka region diagnostic / functional-group region hai — clean, assignable peaks.
Intuition "Fingerprint" kyun?
1500 cm⁻¹ se neeche har C–C bend apne neighbours se couple karta hai. Do molecules jo kisi bhi chhote structural detail mein alag hain woh peaks ka alag tangle produce karte hain — toh exact match ⇒ same compound.
Worked example Example 2 — Carboxylic acid (ethanoic acid)
Dono expect karo — ek bahut broad O–H (2500–3300) aur ek strong C=O (~1710).
Yeh step kyun? –COOH mein O–H aur C=O dono hote hain. O–H exceptionally broad hai kyunki acids strong hydrogen bonds se dimerize karte hain, absorption ko spread kar dete hain.
C–H region ke upar ek wide hump plus 1710 peak dikhe ⇒ carboxylic acid.
Worked example Example 3 — Formula se predict karo: C≡N vs C=N
k triple > k double , same atoms toh same μ . Isliye ν ~ C ≡ N > ν ~ C = N .
Yeh step kyun? Sirf k change hota hai; master equation kehti hai higher k ⇒ higher ν ~ . Indeed C≡N ≈ 2250 vs C=N ≈ 1650.
Common mistake "C=C ko C=O ki tarah ek strong peak deni chahiye."
Kyun sahi lagta hai: dono double bonds hain similar-ish positions par, toh similar peaks expect karte ho.
Fix: Peak height dipole change par depend karta hai, bond order par nahi. Similar carbons ke beech C=C mein tiny dipole swing hoti hai ⇒ weak peak (symmetric ho toh absent bhi). C=O bahut polar hai ⇒ strong . Bond order position set karta hai; polarity intensity set karti hai.
Common mistake "Broad band ka matlab hamesha alcohol ka O–H hota hai."
Kyun sahi lagta hai: alcohol O–H textbook broad band hai.
Fix: Carboxylic acids ek aur bhi broad band deti hain jo ~2500 tak neeche phailti hai aur ~1710 par C=O ke saath pair hoti hai. Decision lene se pehle partner C=O peak check karo.
Common mistake "Heavier/stronger bond ⇒ higher frequency, hamesha."
Kyun sahi lagta hai: "stronger" sunne mein "faster" lagta hai.
Fix: ν ~ ∝ k / μ . Stronger (k ↑ ) ise raise karta hai, lekin heavier (μ ↑ ) ise lower karta hai. Dono levers opposite act karte hain — inhe alag-alag track karo.
IR wavenumber set karne wale do molecular factors kaun se hain? Force constant
k (stiffness) aur reduced mass
μ — via
ν ~ = 2 π c 1 k / μ .
IR selection rule kya hai? Vibration molecule ka dipole moment change kare; dipole change nahi ⇒ IR-inactive.
Reduced mass define karo. μ = m 1 + m 2 m 1 m 2 , spring par do atoms ke liye effective single mass.
C–H ~3000 cm⁻¹ ke paas kyun absorb karta hai? H bahut light hai ⇒ small
μ ⇒ large
k / μ .
C=O ka typical wavenumber aur yeh strong kyun hai? ~1700 cm⁻¹; strong hai kyunki polar carbonyl ek large dipole change deta hai.
Alcohol O–H aur carboxylic-acid O–H mein fark karo. Alcohol: broad 3200–3550. Acid: bahut broad 2500–3300 + saath mein C=O ~1710.
C=C IR mein aksar weak kyun hota hai? Stretching par small dipole change (often near-symmetric) ⇒ weak/absent peak.
Fingerprint region kya hai aur iska use kya hai? ~1500 cm⁻¹ se neeche; tangled skeletal/bending bands jinka unique pattern matching se molecular identity confirm karta hai.
O–H, C–H, C≡N, C=O, C=C ko decreasing wavenumber mein order karo. O–H (3300) > C–H (3000) > C≡N (2250) > C=O (1700) > C=C (1650).
Bond order peak position set karta hai ya peak height? Position (via k ). Height dipole change (polarity) se set hoti hai.
C≡N vs C=N — kaun sa higher hai aur kyun? C≡N higher; same μ par larger k ⇒ higher ν ~ .
Recall Feynman: ek 12-saal ke bacche ko samjhao
Socho ki molecule mein har bond ek choti si spring hai jo do balls ko pakde hue hai. Agar tum use dhakelo, woh apni special speed par aage-peeche bounce karta hai. Tighter springs aur halki balls fast bounce karti hain; loose springs aur bhaari balls slow bounce karti hain. Ab molecule par invisible "heat light" (infrared) daalo. Har spring sirf woh light pakadta hai jiska flicker uski apni bounce se match kare. Yeh dekh kar ki kaun si lights swallow ho gayi, hum figure out kar lete hain ki molecule mein kaun si springs (bonds) hain. Jo springs lop-sided hain (ek end zyada electrons kheenchta hai) woh sabse zyada light pakadti hain — isliye C=O spring ek badi dark line deti hai. Neeche wali tiny springs ki messy bheed itni unique hoti hai ki woh exact molecule ka naam batane ke liye fingerprint ki tarah kaam karti hai.
Mnemonic Intensity rule yaad rakho
"Lopsided springs shout, balanced springs whisper." Bada dipole change = tall peak (C=O shouts), symmetric = weak/silent (C=C whispers, O 2 mute hai).
Molecular dipole moment — set karta hai kaun si vibrations IR-active hain aur kitni intense.
Simple harmonic oscillator — master equation ke peeche physics model.
Hydrogen bonding — O–H aur N–H bands ki broadening explain karta hai.
Bond order and bond strength — k ko single/double/triple bonds se link karta hai.
Mass spectrometry & NMR spectroscopy — complementary structure-elucidation tools.
Electromagnetic spectrum — IR kahan hota hai (visible aur microwave ke beech).
omega = sqrt of k over mu
Stiffer bond: triple > double > single
Lighter atoms e.g. C-H high
Characteristic group peaks
Fingerprint region identifies molecule