3.4.4 · Chemistry › Coordination Chemistry
Ek central metal ion ek choti si planet ki tarah hai jiske around moons (ligands) hain. Jitne moons usne pakde hain woh coordination number (CN) hai, aur woh moons 3D space mein kaise arrange hote hain woh geometry hai. Dono cheezein ek tug-of-war se decide hoti hain — kitne ligands physically fit ho sakte hain aur metal ke d-electrons kaise arrange hona chahte hain .
Definition Coordination number (CN)
Donor atoms ki sankhya (ligands nahi!) jo directly central metal ion se coordinate bonds ke zariye judi hain.
Monodentate ligands ke liye: CN = ligands ki sankhya.
Chelating ligands ke liye: har donor atom ko alag count karo. Jaise ethylenediamine (en) bidentate hai → 2 contribute karta hai CN mein.
Common mistake Steel-man: "CN = ligand molecules ki sankhya"
Kyun sahi lagta hai: Har ligand ek "cheez" lagti hai jo attached hai, isliye tum cheezein count karte ho.
Kyun galat hai: Ek ligand metal ko multiple haathon se pakad sakta hai (denticity). [ Co(en) 3 ] 3 + mein sirf 3 ligands hain lekin CN = 6 hai (har en 2 N atoms donate karta hai).
Fix: Hamesha donor atoms count karo, molecules nahi.
Intuition Electron-pair repulsion ko minimise karo
Ligands electron-pair donors hain → woh ek dusre ko repel karte hain. Isliye woh metal ke around jitna ho sake utna door spread ho jaate hain. Yahi woh VSEPR idea hai jo tumne CH 4 , BF 3 , etc. ke liye use kiya tha.
Ek sphere par 2 points jitna door ho sakein → opposite poles → linear (180°)
4 points → tetrahedron ke corners (109.5°)
6 points → octahedron ke corners (90°)
Lekin transition metals ke liye ek twist hai: d-orbital electrons aur crystal field stabilisation pure geometry ko override kar sakte hain, khaaskar CN = 4 ke liye (tetrahedral vs square planar).
KYU: Sirf do electron domains ke saath, maximum separation yahi hai ki unhe opposite poles par rakhein.
Yeh kaun karta hai? Zyaadatar Group 11/12 ke d 10 ions jo extra ligands nahi chahte:
[ Ag(NH 3 ) 2 ] + (Tollens' reagent)
[ CuCl 2 ] −
[ Au(CN) 2 ] −
d 10 ions ko linear kyun pasand hai
Ek filled d 10 shell spherical aur "sharmili" hoti hai — use zyaada ligands se extra crystal-field energy nahi milti, isliye woh sirf do ligands ko door-door pakad ke ligand–ligand repulsion minimise karti hai.
Yeh sabse interesting CN hai kyunki do geometries compete karti hain .
Char ligands ek tetrahedron ke corners par, bond angle 109.5° .
KYU choose hota hai: Pure VSEPR optimum (4 points ka maximum spread), tab favoured hota hai jab:
metal d 0 , d 5 , ya d 10 ho (square planar ke liye koi special CFSE advantage nahi),
ligands bulky hon (tetrahedron mein zyaada jagah milti hai),
ligands weak field hon.
Examples: [ NiCl 4 ] 2 − , [ CoCl 4 ] 2 − , [ MnO 4 ] − , [ Zn(NH 3 ) 4 ] 2 + .
Char ligands ek square ke corners par, sab ek hi plane mein, angle 90° . (Socho: ek octahedron jiske do axial ligands hata diye gaye hon.)
KYU choose hota hai: d 8 ions ke saath strong-field ligands ke liye favoured.
d 8 + strong field ki kahaani (KAISE)
Square planar mein, d x 2 − y 2 orbital (seedha 4 ligands ki taraf point karta hai) energy mein bahut upar push ho jaata hai, jabki baaki chaar d-orbitals neeche rehte hain. Ek d 8 ion mein exactly 8 electrons hain, jo neeche ke 4 orbitals ko fill kar sakte hain (4 orbitals mein 8 electrons) aur upar wala d x 2 − y 2 empty chhod sakte hain. Yeh bahut stabilising hota hai — lekin sirf tab jab splitting (yaani field) strong enough ho pairing force karne ke liye.
Toh: d 8 + strong field → square planar . d 8 + weak field → tetrahedral .
Examples: [ Ni(CN) 4 ] 2 − (CN⁻ strong), [ PtCl 4 ] 2 − , [ Pd(NH 3 ) 4 ] 2 + , almost sabhi Pt(II) aur Pd(II) .
Common mistake Steel-man: "Saare
Ni 2 + complexes ek jaisi shape ke hote hain"
Kyun sahi lagta hai: Same metal, same charge → shape bhi same honi chahiye.
Kyun galat hai: [ NiCl 4 ] 2 − tetrahedral aur paramagnetic hai (weak field Cl⁻), lekin [ Ni(CN) 4 ] 2 − square planar aur diamagnetic hai (strong field CN⁻). Ligand field strength geometry ko flip kar deti hai.
Fix: d 8 ki geometry ligand par depend karti hai, sirf metal par nahi.
KYU sabse common: Chhe ek achha compromise hai — bonding/charge satisfy karne ke liye kaafi ligands, jabki 90° separation repulsion manageable rakhta hai. Zyaadatar transition metal complexes (Co 3 + , Fe 3 + , Cr 3 + …) octahedral hote hain.
Examples: [ Co(NH 3 ) 6 ] 3 + , [ Fe(CN 6 ) ] 3 − , [ Cr(H 2 O ) 6 ] 3 + , [ Co(en) 3 ] 3 + (CN = 6 teen bidentate ligands se).
CN
Geometry
Kab
Example
2
Linear
d 10 (Ag⁺, Au⁺, Cu⁺)
[ Ag(NH 3 ) 2 ] +
4
Tetrahedral
d 0 , d 5 , d 10 , weak field, bulky
[ NiCl 4 ] 2 −
4
Square planar
d 8 + strong field
[ Ni(CN) 4 ] 2 −
6
Octahedral
zyaadatar ions
[ Co(NH 3 ) 6 ] 3 +
[ Ag(NH 3 ) 2 ] + ki geometry
Step 1 — CN: 2 NH₃ (monodentate) → CN = 2. Kyun? donor atoms count karo = 2 N.
Step 2 — d-count: Ag +1 hai, [ Kr ] 4 d 10 . Kyun? d 10 spherical hai, 2 ligands prefer karta hai.
Step 3 — geometry: CN 2 → linear, 180° . ✓
[ Ni(CN) 4 ] 2 − vs [ NiCl 4 ] 2 −
Step 1 — d-count: Ni²⁺ = d 8 (dono mein). Kyun? Ni group 10 mein hai, 2e lose karne ke baad 3 d 8 .
Step 2 — ligand field: CN⁻ strong field hai; Cl⁻ weak field hai. Yeh step kyun? Field strength decide karti hai ki d 8 square planar jaata hai ya nahi.
Step 3 — geometry: Strong field d 8 → square planar, diamagnetic ([ Ni(CN) 4 ] 2 − ). Weak field d 8 → tetrahedral, paramagnetic ([ NiCl 4 ] 2 − ).
[ Cr(EDTA) ] − ka CN
Step 1 — denticity: EDTA hexadentate hai (d = 6 ). Kyun? 2 amine N + 4 carboxylate O donors.
Step 2 — CN: 1 × 6 = 6 . Kyun? ek ligand, chhe donor atoms.
Step 3 — geometry: CN 6 → octahedral , EDTA saare 6 sites wrap karta hai. ✓
Recall Feynman: ek 12-saal ke bachche ko samjhao
Socho beech mein ek magnet ball hai aur kuch sticky balls hain jo use pakadna chahti hain. Coordination number bas yeh hai ki kitni sticky balls ne pakad liya. Kyunki sticky balls ek dusre ko dhakkelti hain, woh spread ho jaati hain: 2 balls opposite sides par baith jaati hain (ek seedhi line), 4 balls ek chhoti pyramid-ish shape banati hain (tetrahedron) ya kabhi kabhi flat square, aur 6 balls ek perfect "double pyramid" banati hain (octahedron). Ek twist yeh hai: kuch ball-grabbers ke do haath hote hain (clip ki tarah), isliye unhe do grabs maanat hain!
Mnemonic Shapes yaad rakho
"2 Lines, 4 Tents or Tables, 6 Octopus."
2 → Line ar
4 → Tent (tetrahedral) ya Table (square planar)
6 → Octo hedral (octopus ke 8 hote hain, lekin socho "octa = 6 yahan" → octahedron ke 8 faces, 6 vertices hote hain: ligands 6 vertices par baithte hain)
d 8 flip ke liye: "d 8 Strong → Square."
Coordination number kya hai? Central metal se coordinate bonds ke zariye directly jude donor atoms ki sankhya (donor atoms count karo, ligand molecules nahi).
CN = 2 ke liye geometry? Linear, bond angle 180°, typically d 10 ions jaise Ag⁺, Au⁺, Cu⁺ mein.
CN = 4 ke liye do possible geometries? Tetrahedral (109.5°) aur square planar (90°).
CN = 4 square planar kab hota hai tetrahedral ki jagah? d 8 ions ke liye strong-field ligands ke saath (jaise [ Ni(CN) 4 ] 2 − , Pt(II), Pd(II)).
CN = 6 ke liye geometry? Octahedral, 90° angles; transition complexes ke liye sabse common geometry.
[ Co(en) 3 ] 3 + ka CN?6, kyunki en bidentate hai aur 3 hain (3×2).
[ NiCl 4 ] 2 − tetrahedral kyun hai lekin [ Ni(CN) 4 ] 2 − square planar kyun?Cl⁻ weak field hai (tetrahedral, paramagnetic); CN⁻ strong field hai jo d 8 pairing ko square planar mein force karta hai (diamagnetic).
CN ko denticity se link karne wala formula? CN = ∑ i n i d i (ligands ki sankhya × har ligand ke donor atoms).
4 monodentate ligands ke liye pure VSEPR se ligand repulsion minimise karne wali geometry? Tetrahedral (109.5°), maximum-spread arrangement.
d 10 ions linear (CN 2) kyun prefer karte hain?Filled d-shell ko extra crystal-field stabilisation nahi milta, isliye woh sirf do ligands ko door-door pakad ke repulsion minimise karte hain.
Crystal Field Theory — d 8 ke liye square-planar vs tetrahedral explain karta hai
VSEPR Theory — linear/tetrahedral/octahedral shapes ki origin
Chelation and Denticity — kyun CN ≠ ligands ki sankhya
Magnetic properties of complexes — diamagnetic square planar vs paramagnetic tetrahedral
Isomerism in coordination compounds — geometry cis/trans aur optical isomers decide karti hai