2.3.5 · Chemistry › Chemical Bonding
Ek covalent bond mein do nuclei share karte hain ek electron glue ka pool apne beech mein. Do nuclei ek doosre ko repel karte hain, aur shared electrons beech mein baithte hain, dono ko andar ki taraf kheenchte hain. Bond us distance par settle hota hai jahan andar ki pull = bahar ki push — woh equilibrium separation hi bond length hai, aur jo energy lagti hai atoms ko us comfortable well se alag karne mein woh bond energy hai. Nuclei ke beech kitne shared electron pairs cramm kiye hain woh bond order hai, aur yahi dono upar wali cheezein control karta hai.
Definition Teen linked quantities
Bond length (r e ): equilibrium internuclear distance — potential-energy curve ke minimum par separation. Measure hota hai pm mein (ya Å; 1 A ˚ = 100 pm).
Bond (dissociation) energy (D e ya B E ): ek mole bonds ko break karne ke liye required energy gas phase mein, homolytically. Units kJ mol− 1 . Hamesha positive hoti hai (break karna energy cost karta hai).
Bond order (BO): do atoms ke beech shared electron pairs ki sankhya . Single = 1, double = 2, triple = 3 (delocalised systems mein fractional values bhi hoti hain).
Do H atoms ko infinity se ek doosre ki taraf laao. Total energy E ko separation r ke saath track karo.
Step 1 — Kaunsi forces kaam karti hain?
Nucleus–nucleus repulsion: ∝ + r 1 (jab r → 0 toh blast ho jaata hai).
Electron–electron repulsion: yeh bhi positive hai.
Nucleus–electron attraction: negative hai, aur — crucially — electron density nuclei ke beech pile up ho jaati hai , isliye har nucleus shared cloud ki taraf attract hota hai.
Density beech mein kyun pile up hoti hai? Kyunki jab atomic orbitals in phase overlap karte hain (wavefunctions ki constructive interference), toh internuclear region mein probability ∣ ψ ∣ 2 badh jaati hai. Woh extra negative charge do positive nuclei ke beech hi unhe bind karta hai.
Step 2 — Energy curve banao.
Bade r par: attraction dominate karta hai → energy girती hai jab atoms paas aate hain.
Chhote r par: nuclear repulsion ∝ 1/ r jeet jaati hai → energy upar shoot karti hai.
Kahin beech mein, E ek minimum par pahunchti hai. Ek convenient model hai Morse potential :
E ( r ) = D e ( 1 − e − a ( r − r e ) ) 2 − D e
Step 3 — Do quantities read off karo.
Minimum r = r e par baithti hai: d r d E = 0 set karo.
d r d E = 2 D e ( 1 − e − a ( r − r e ) ) ⋅ a e − a ( r − r e )
Yeh zero hoga jab 1 − e − a ( r − r e ) = 0 ⇒ r = r e . Toh bond length exactly well minimum hai. ✔
Well ki depth bond energy hai. r = r e par, E = − D e ; r → ∞ par, E → 0 . Toh well se escape karne ki energy hai
B E = E ( ∞ ) − E ( r e ) = 0 − ( − D e ) = D e .
Intuition Deeper well ⇒ stronger bond ⇒ shorter length kyun
Zyada shared pairs (higher BO) nuclei ko aur paas kheenchte hain (chhota r e ) aur well ko aur gehra karte hain (bada B E ). Isliye teeno quantities saath saath chalti hain.
Carbon–carbon evidence (yeh numbers yaad karo):
Bond
BO
Length (pm)
Energy (kJ mol− 1 )
C–C
1
154
348
C=C
2
134
614
C≡C
3
120
839
Intuition Notice karo yeh proportional NAHI hai
1→2→3 jaate waqt, length 154→134→120 drop karti hai (smooth) lekin energy 348→614→839 nahi hai 348 × 2 ya × 3 . Pehla (σ ) bond sabse strong hota hai ; extra π bonds har baar kam add karte hain kyunki side-on p –p overlap head-on se weaker hota hai. Steel-manning: "double bond = twice as strong" pairs count karne se sahi lagta hai , lekin σ = π strength mein — yahi fix hai.
MO theory se bond order (diatomics ke liye):
BO = 2 N b − N a
jahan N b = bonding MOs mein electrons, N a = antibonding MOs mein electrons. Example O2 : N b = 10 , N a = 6 ⇒ BO = 2 . Fractional orders yahan bhi aate hain (e.g. O2 + ka BO 2.5 hai).
Worked example 1. N–N, N=N, N≡N ko bond length aur energy se rank karo
Bonds: N–N (BO 1), N=N (BO 2), N≡N (BO 3).
Length ranking: N≡N < N=N < N–N. Yeh step kyun? Higher BO zyada shared pairs pack karta hai, nuclei ko aur paas kheenchta hai → shorter.
Energy ranking: N≡N (945) > N=N > N–N (163). Kyun? Zyada bonds ke liye deeper potential well. N≡N ki badi energy hi reason hai ki N2 itna unreactive kyun hai.
Worked example 2. NO ka BO compute karo aur NO
+ mein ionise hone par stability change predict karo
NO mein 15 electrons hain. MO filling deta hai N b = 10 , N a = 5 .
BO = 2 10 − 5 = 2.5
Yeh step kyun? Ek electron antibonding π ∗ orbital mein baithta hai, jo half deta hai.
Woh antibonding electron remove karo → NO+ : N a = 4 , BO = 2 10 − 4 = 3 .
Kyun? Ek antibonding electron lose karna BO badhata hai → shorter, stronger bond. NO+ zyada stable hai aur NO se shorter bond rakhta hai.
Worked example 3. Benzene C–C length puzzle
Benzene C–C = 139 pm — single (154) aur double (134) ke beech mein.
Yeh step kyun? Resonance/delocalisation har C–C ko effectively bond order 1.5 deta hai, isliye length beech mein land karti hai. Ise dual-code karo: imagine karo six electrons ek ring mein smeared hain, teen fixed double bonds mein nahi.
Common mistake "Bond energy woh energy hai jo bond form hone par release hoti hai, isliye yeh negative hai."
Kyun sahi lagta hai: bond banana actually energy release karta hai (exothermic).
Fix: Bond energy defined hai bond break karne ki energy ke roop mein, isliye yeh positive report hoti hai. Formation same magnitude energy release karta hai minus sign ke saath. Enthalpy calculation mein dono conventions mix mat karo.
Common mistake "Shorter bond ka matlab hamesha higher bond order hota hai."
Kyun sahi lagta hai: same pair of atoms ke liye yeh sach hai.
Fix: Sirf like se like compare karo. C–F (135 pm) C–C (154 pm) se shorter hai, despite dono single bonds hone ke — kyunki F ek chhota atom hai. Atomic size aur electronegativity bhi length set karte hain. BO trend sirf same two elements ke across hold karta hai.
Common mistake "Table se bond energy us molecule ke liye exact hai."
Kyun sahi lagta hai: tables har bond type ke liye ek number list karti hain.
Fix: Tabulated values bahut saare molecules pe averages hain. CH4 mein actual C–H CHCl3 mein C–H se thoda different hai. Δ H estimate karne ke liye great hai, precision ke liye nahi.
H 2 + Cl 2 → 2 HCl
Break: H–H (436) + Cl–Cl (242) = 678.
Form: 2 × H–Cl (431) = 862.
Δ H = 678 − 862 = − 184 kJ mol − 1
Negative kyun? Zyada/stronger bonds form hue hain break hone se → exothermic.
Bond length kya hai? Equilibrium internuclear distance — potential-energy curve ke minimum par separation.
Bond energy kya hai? Gas phase mein ek mole bond break karne ke liye required energy (homolytically); hamesha positive.
Bond order length aur energy ko kaise affect karta hai? Higher bond order → shorter bond length aur higher bond energy.
C=C bond exactly C–C se twice as strong kyun nahi hai? Doosra bond ek π bond hai (weaker side-on overlap) pehle σ bond se, isliye har extra bond kam energy add karta hai.
Bond order ke liye MO formula? BO = (N_bonding − N_antibonding)/2.
MO theory se O2 ka bond order? (10 − 6)/2 = 2.
NO⁺ NO se stronger/shorter-bonded kyun hai? Ek antibonding electron remove karna BO ko 2.5 se 3 tak raise karta hai.
Bond energies se reaction enthalpy ka formula? ΔH = Σ(bonds broken) − Σ(bonds formed).
Benzene C–C length 139 pm (single aur double ke beech) kyun hai? Delocalisation effective bond order ~1.5 deta hai.
Nuclei ke beech electron density atoms ko kyun bind karti hai? In-phase orbital overlap do positive nuclei ke beech negative charge pile karta hai, dono ko andar kheenchta hai.
Recall Feynman: 12-year-old ko explain karo
Do magnets imagine karo jo ek doosre ko dhakelte hain (nuclei). Ab ek chewy sticky glue ka blob (shared electrons) bilkul unke beech rakho. Glue dono ko pakad leta hai aur andar kheenchta hai jab tak dhakka aur khichaav exactly balance nahi ho jaate — woh gap bond length hai. Unhe alag kheenchne ke liye tumhe glue scrape off karni padegi, aur jo effort lagta hai woh bond energy hai. AUR ZYADA glue daalo (double, triple bond = higher bond order ) aur magnets aur paas baithenge aur alag karna aur mushkil hoga. Simple!
Mnemonic Trend yaad rakho
"More pairs, less space, more force." Zyada shared pairs (BO↑) → kam distance (length↓) → zyada force break karne ke liye (energy↑).
Molecular Orbital Theory — jahan bond order = (Nb − Na)/2 aata hai
VSEPR and Molecular Geometry — bond angles bond lengths ko complement karte hain
Resonance and Delocalisation — fractional bond orders (benzene, NO)
Hess's Law and Enthalpy — bond energies ΔH calculations mein jaati hain
Electronegativity and Bond Polarity — size/polarity bhi length affect karte hain
Sigma and Pi Bonds — kyun σ > π strength mein
Bond order - shared pairs
Electron density piles between nuclei
Nucleus-electron attraction
Nucleus-nucleus repulsion