Ek gene ke liye Punnett square theek kaam karta hai (4 boxes) ya phir do genes ke liye bhi (16 boxes). Lekin teen genes ke liye 64 boxes chahiye, chaar genes ke liye 256. Unhe banana slow aur galti-prone hota hai.
Gehri insight yeh hai: ek dihybrid (ya trihybrid) cross mein, alag chromosomes par gene independently assort karte hain (Mendel's Second Law). Independence exactly woh condition hai jo hume probabilities multiply karne deti hai. Toh ek bade square ki jagah, hum har gene ko apna chhota sa problem mante hain aur answers ko combine karte hain.
Probability ko equally likely outcomes ka fraction socho.
Product rule. Ek fair gamete-maker do baar roll karo. Event A ki probability p hai, matlab yeh fraction p of trials mein hota hai. Un hin trials mein, event B (independent) fraction q mein hota hai. Toh fraction jahan dono hote hain woh hai "fraction of a fraction":
A hota haip×phir B hota haiq=pq.Multiply kyun? Kyunki "B given A" nahi badlta (P(B∣A)=P(B)=q independence se), toh P(A∩B)=P(A)P(B∣A)=pq.
Sum rule. Maano genotype Aa ya toh "egg A, sperm a" ya "egg a, sperm A" se produce ho sakta hai. Yeh mutually exclusive hain (ek single fertilization ek ya doosra hoti hai, dono kabhi nahi). Outcomes count karo: favorable count hai (route 1 ka count) + (route 2 ka count), toh total outcomes se divide karne par:
P(A∪B)=NnA+nB=NnA+NnB=P(A)+P(B).Add kyun? Kyunki hum favorable outcomes ki alag-alag baskets pool kar rahe hain jisme koi overlap nahi hai double-count hone ke liye.
Recall Feynman: ek 12-saal ke bacche ko explain karo
Do coins flip karne ki imagine karo. Heads AND heads paane ke liye, dono ko cooperate karna hoga — woh rarer hai, toh tum chances multiply karte ho (21×21=41). Ek coin par heads OR tails paane ke liye, woh hai "dono taraf kaam karta hai," toh tum add karte ho aur yeh easy hai (21+21=1, hamesha!). Baby genes bhi waise hi kaam karte hain: "yeh gene AND woh gene" → multiply; "same gene ka yeh version OR woh version" → add. Bas yahi poora trick hai.