The policy gradient theorem says:
∇θJ(θ)=Eπ[∇θlogπθ(at∣st)Ψt]
where Ψt is any "credit" signal. REINFORCE uses Ψt=Gt (the full Monte-Carlo return). This is unbiased but high variance — Gt depends on a whole random trajectory.
Claim: for any function b(s) that does not depend on the action,
Ea∼π[∇θlogπθ(a∣s)b(s)]=0.
Why this step? Because the gradient of a probability distribution integrates to zero:
Ea[∇θlogπθ(a∣s)]=∑aπθ(a∣s)πθ(a∣s)∇θπθ(a∣s)=∇θ∑aπθ(a∣s)=∇θ1=0.
So subtracting b(s) leaves the gradient unbiased but can shrink variance. The variance-minimizing baseline is close to V(s).
Recall What role does the critic play, and how does it reduce variance?
The critic estimates V(s) and serves as a baseline, so the actor is trained on the advantage (surprise relative to expectation) rather than the raw high-variance return Gt. Subtracting a state-only baseline keeps the gradient unbiased (its expected contribution is 0) while shrinking variance.
Recall Why does the SAME TD error
δt update both networks?
δt=r+γVw(s′)−Vw(s) is simultaneously (a) the critic's prediction error to be minimized and (b) a one-sample estimate of the advantage A(s,a) that scales the actor's policy-gradient step.
Recall Feynman: explain actor-critic to a 12-year-old
Picture a kid learning basketball. The actor is the kid's arm choosing how to shoot. The critic is a coach who, before the ball lands, says "that's better than your usual shot" or "worse than usual." The kid doesn't wait for the final score of the whole game (that's too random) — they trust the coach's quick judgment on each shot and adjust immediately. Over time the coach's judgments also get sharper, and the kid gets better together with the coach.
Why is REINFORCE high variance and actor-critic lower?
REINFORCE uses full random return Gt; actor-critic replaces it with a bootstrapped, baseline-subtracted advantage (only the surprise), cutting variance.
Should you backprop through the TD target r+γVw(s′)?
No — it's treated as a fixed (stop-gradient) target; this is semi-gradient TD.
Why is a two-timescale learning rate (critic faster) used?
So the advantage estimate the actor relies on is accurate; a lagging critic gives the actor misleading gradients.
What does the sign of the advantage tell the actor to do?
A>0: increase the action's probability; A<0: decrease it.
Dekho, RL me do camp hote hain: policy-based (REINFORCE) jo directly action seekhte hain, aur value-based (Q-learning) jo state ki value estimate karte hain. REINFORCE ka problem yeh hai ki wo pura random return Gt use karta hai as learning signal — yeh bahut noisy/high variance hota hai, jaise poore semester ki luck pe grade dena. Actor-critic dono ko jodta hai: actor decide karta hai kya karna hai (πθ), aur critic batata hai wo kitna accha tha (Vw).
Magic yahaan hai ki hum raw reward ki jagah advantage use karte hain, A(s,a)=Q(s,a)−V(s) — matlab "expectation se kitna better/worse rahe". Baseline V(s) subtract karne se gradient unbiased rehta hai (proof: policy ke gradient ka sum zero hota hai) par variance kaafi kam ho jaata hai. Practically hum bootstrap karte hain: δt=rt+1+γVw(st+1)−Vw(st). Yeh δt hi TD error hai.
Sabse pyaari baat: ek hi δt dono ko train karta hai. Critic ke liye yeh uska prediction error hai (isko minimize karo), aur actor ke liye yeh advantage estimate hai (agar δ>0 to us action ki probability badhao, agar δ<0 to ghatao). Example 2 dekho — reward positive tha par future bura tha, to δ negative aa gaya, action discourage hua. Yeh hi difference hai raw reward aur advantage me.
Do cheezein yaad rakhna: (1) TD target r+γVw(s′) ko fixed maano, uspe backprop mat karo (semi-gradient). (2) Critic ko thoda fast learn karao (bada learning rate) taaki actor ko accha signal mile. Yehi foundation hai A2C, A3C, PPO jaise modern algorithms ka.