Ise kaise padhen: har coordinate ki magnitude ko power p pe raise karo, sum karo, phir p-th root lo.
Root "undo" karta hai power ko taaki homogeneity hold kare.
L∞ limit ki derivation (scratch se). Maano M=maxi∣xi∣. Ise factor out karo:
∥x∥p=(∑i∣xi∣p)1/p=M(∑i(M∣xi∣)p)1/p.
Har ratio M∣xi∣≤1 hota hai. Maano k coordinates max ke equal hain (ratio =1), baaki <1 hain.
Jab p→∞, ratio <1 waale terms vanish ho jaate hain, toh sum →k ho jaata hai. Phir
∥x∥p→M⋅k1/p→M⋅1=M,
kyunki kisi bhi fixed k ke liye k1/p→1 hota hai. Is tarah ∥x∥∞=maxi∣xi∣. ∎
Imagine karo tum ghar pe ho aur tumhara dost 3 blocks east aur 4 blocks north rehta hai.
Agar tum galiyoon pe chalte ho toh 3 + 4 = 7 blocks jaoge. Yeh L1 distance hai.
Agar tum seedhi line mein ud sako toh yeh 5 blocks hai (diagonal). Yeh L2 hai.
Agar tumhe sirf sabse lamba single stretch chahiye, toh woh 4 hai (north wala hissa). Yeh L∞ hai.
Same do dost, teen jawaab — kyunki "kitni door" depend karta hai tum kaise move kar sakte ho.
L1 ka unit ball ek diamond hai jiske corners axes pe hain, toh optimal solutions axes pe land karte hain → coordinates exactly 0 ho jaate hain; L2 ka ball smooth hai (ek circle) jiske koi corners nahi.
Same vector ke norms ke beech general inequality?
∥x∥∞≤∥x∥2≤∥x∥1; bada p chota-ya-equal norm deta hai.
L0 true norm kyun nahi hai?
Yeh nonzeros count karta hai lekin homogeneity violate karta hai: ∥2x∥0=∥x∥0=2∥x∥0.
∥x∥∞=maxi∣xi∣ derive karo.
M=max∣xi∣ factor karo: ∥x∥p=M(∑(∣xi∣/M)p)1/p; ratios <1 vanish ho jaate hain jab p→∞, M⋅k1/p→M bachta hai.
Dot product se kaunsa norm relate karta hai?
L2, kyunki ∥x∥2=x⊤x.
Lp kis p ke liye valid norm hai?
p≥1 (usse neeche triangle inequality fail ho jaati hai).